Nt1310 Unit 3 Lab Report
Lab 1 helps create a better understand of the changes in crystal structures when the annealing and quenching process is applied to 1020 and 1080 steel. The numbered steel refers to the ASTM grain-size number. Formula 1 is used to solve for the grain size. n=2^(G-1) Equation (1) at 100x magnification Crystal structures change shapes which changes the strength of the material and its properties. The metal might become soft, brittle, hard, or ductile. The four test specimens are all made from cold drawn steel. When steel is cold drawn, the crystal structure changes and creates stress. The stress in the grains can be reduced by the process of annealing. Quenching creates small stresses because carbon does not have time to escape. The annealing process is when …show more content…
Creating larger grain boundaries makes the steel more ductile due to there being less paths for dislocations on the boundaries. The grain boundaries are caused by a dislocation. When there is an extra plane of atoms, or a plane of missing atoms, a gap is created causing the grain boundaries. Pearlite, as shown in figure 1 picture B, is caused when the steel is annealed. Pearlite has multiple layers that consist of ferrite and cementite. Ferrite is has a crystalline structure known as a Body Centered Cubic structure. Ferrite is a ceramic compound that has very little carbon causing it to be soft and ductile. Cementite is also a ceramic that has more carbon than ferrite. Quenching a metal is slightly different than annealing. When the steel is heated up, the steel is then rapidly cooled down is water or oil. When the steel is quenched, the heat energy within the center of the part is pulled out quickly. The process of cooling rapidly cooling down the steel creates lots of tinny grain boundaries on the surface. The small grain boundaries are called martensite, as seen in figure 1 picture C. Martensite is a very hard microstructure due to having a dense amount of grain boundaries. The martensite crystals
Nt1310 Unit 4 Test Lab Report
462 Words | 2 PagesIII SYNTHESIS AND SIMULATIONS RESULTS The simulation and synthesis work is finally done by the xilinix and modelsim respectively. Figure 5:synthesis results of Fault FFT. The figures intimate the fault injected FFT,which is checked by the manual error injected via all diferent possibilities by using RTL scripting. Eventhough the soft error is added in the FFT the error detector code 100% detect the errors and corrector correct the errors.
Nt1210 Lab Report
798 Words | 4 PagesResults The lab experiment was done in two parts, one with the NAND, NOR, XOR and Hex Inverters and the other with a 7483 full adder gate, both will verify the truth table when two input bits and a carry are added together. The circuits were built by examining the 1 bits through a K-Map to create a Boolean expression for the sum and carry. The Boolean expression for the sum was A⊕B⊕C and the carry as AB+BC_in+AC_in. From these two expressions, we notice that we must use two exclusive-ORs gates in the sum inputs for A, B, and C. For the sum, we have to use NOR and NAND (the only available gates from the lab manual).
Pt1420 Unit 2 Lab Report Sample
695 Words | 3 PagesFrom the data obtained in Tables 1-3, we were able to plot multiple graphs using excel. These graphs give a better representation of the data as seen in Figures 1-9. It can be seen that each figure shows a slight increase in CO2 production, which signifies a possible change in metabolic rate. Figures 4 and 7 show a relatively large change between the control and fox urine. The changes in slope between theses two are 0.0267 for Figure 4’s slopes and 0.0192 for Figure 7’s slopes.
Nt1310 Unit 2 Lab Report
310 Words | 2 PagesI need to find the area of rectangle ABCD. I know that ABCD is a rectangle with diagonals intersecting at point E. Segment DE equals 4x-5, segment BC equals 2x+6, and segment AC equals 6x. I predict that To find the area of rectangle ABCD I need to find out the base and height of the rectangle. The first step is to find what x equals. Since I know the intersecting line segments AC and DB are congruent that means when I times the equation 4x-5 for segment DE by two it will equal the equation 6x for segment AC.
Is3350 Unit 5 Lab Report
477 Words | 2 PagesYou have made it a point to go through the timesheet and DAR book every day to look for errors. Yes, I placed the sticky note and made the pen and ink changes to the projected timesheet that is not submitted to payroll until Friday. That way you will have enough time to see it ask questions or make the necessary changes to the document. We all know that there is going to be a last-minute change to schedule do to the bad last-minute planning of the scheduling. Since there is no one currently filling the 3 to 11 time slot.
Nt1310 Unit 4 Lab Report
603 Words | 3 PagesSuppose we have a single-hop RCS where there is one AF relay that amplifies the signal received from a transmitter and forwards it to a receiver. Assume that the transmitter sends over the transmitter-to-relay channel a data symbol ${s_k}$, from a set of finite modulation alphabet, $S={S_1, S_2,ldots,S_{cal A}}$, where ${cal A}$ denotes the size of the modulation alphabet. The discrete-time baseband equivalent signal received by the relay, $z_k$, at time $k$ is given by egin{equation} z_k = h_{1,k}s_k + n_{1,k},~~~~for~~k=1,2,ldots,M label{relaySignal} end{equation} where $n_{1,k}sim {cal N}_c(0,sigma_{n1}^2)$ is a circularly-symmetric complex Gaussian noise added by the transmitter-to-relay channel, $h_{1,k}$ denotes the transmitter-to-relay channel, and
Nt1310 Unit 7 Lab 7
91 Words | 1 PagesLab 7: Moon Phases was designed to measure the relative position of the Sun and Moon over the course of one phase cycle (i.e. one month, 29.5 days) The idea for Lab 7: Moon Phases was to examine how the illumination of the moon by the Sun produces the different phase cycles we see as the Moon rotates around Earth and as the Earth rotates around the Sun. The observations of the Moon were taken on four different days in the month of February to March capturing four different Moon Phases.
Nt1310 Unit 3 Lab 7.1
560 Words | 3 Pages7.7.1 Data Owners 1. One whose going to access files, one who owns file, who requires his data to be secure. 2. Data owners are responsible for encrypting the data by generating private key. MMCOE, Department of Computer Engineering, 2015-2016 26 Regeneration of code based cloud storage 3.
Nt1330 Unit 1 Test Paper
513 Words | 3 Pages\section{Building Blocks} \subsection{Access Structures} \textbf{Definition 3.8.}(Access Structure\citeup{beimel1996secure}) \emph{Let $\{P_1, P_2,...,P_n\}$ be a set of parties. A collection $\mathbb{A}\subseteq 2^{\{P_1,P_2,...,P_n\}}$ is monotone if $B\in\mathbb{A}$ and $B\subseteq C$ implies $C\in\mathbb{A}$. An access structure is a monotone collection $\mathbb{A}$ of non-empty subsets of $\{P_1,P_2,...,P_n\}$, i.e., $\mathbb{A}\subseteq 2^{\{P_1,P_2,...,P_n\}} \setminus\{\emptyset\}$. The sets in $\mathbb{A}$ are called the authorized sets, and the sets not in $\mathbb{A}$ are called the unauthorized sets}. In our settings, attributes will play the role of the parties such that the access structure $\mathbb{A}$ will contain the authorized
Hsc300 Unit 9 Lab Report
313 Words | 2 PagesMedical biller is a position that will require you to take in medical claims and code them and bill out medical claims to insurance companies, Medicare and Medicaid on a daily basis. You will have to reconcile Explanation of Benefits (EOB) weekly. Verify if insurance companies require that patients get PA for certain procedure and products. Five requirements for Medical Biller position 1. How to bill claims 2.
Ccto10 Unit 2 Lab Report
335 Words | 2 PagesK.D.A. Saboia et al. , (2007) have been prepared the Bi4Ti3O12–CaCu3Ti4O12 {[BIT(X)–CCTO(100-X)]} composite powders through solid state reaction method and calcined in the range of 900 to 1020 ºC for 12 h. The as-prepared powders have modified in the form of thick film onto alumina ceramic substrate by utilizing screen printing. At 100 Hz, the value of dielectric constant (κ) of CCTO100 and BIT100 is 316.61 and 53.64 respectively. Conversely, the composite with X=20 % shows an unexpected dielectric constant of 409.71, which is around 20% higher in comparison with the CCTO.
Nt1310 Unit 3 Lab Report Sample
474 Words | 2 PagesFigure 6 shows the glass container with a soil that is susceptible to liquefaction. The proponents provided a set of containers to observe different data. Scanning Electron Microscope (SEM) Test
Igneous Rock Research Paper
958 Words | 4 PagesSurrounded by pre-existing rock (called country rock), the magma cools slowly, and as a result these rocks are coarse grained. The mineral grains in such rocks can generally be identified with the naked eye. Intrusive rocks can also be classified according to the shape and size of the intrusive body and its relation to the other formations into which it intrudes. Typical intrusive formations are batholiths, stocks, laccoliths, sills and dikes.
Powder Diffraction Method Analysis
730 Words | 3 PagesThe powder method is used to determine the value of the lattice parameters accurately. Lattice parameters are the magnitudes of the unit vectors a,b and c which define the unit cell for the crystal.
Thermal Expansion In Mississippi Summer
467 Words | 2 PagesHeat is another word for temperature when one considers thermal expansion. This could be from the outside temperature or direct heat of a flame. A Mississippi summer can easily reach 100 degrees or higher; and, therefore, when you consider this prolonged heat on a piece of metal such as a railroad track, the metal is going to continue to get bigger and expand. In order to prevent derails because the rails have buckled, engineers leave small gaps.
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