Sodium Chloride Lab Report
In this experiment, groups were given two different unidentified substances with the goal of being able to figure out what chemical each substance was. Unidentified substance “2” was proven to be Tin (II) Chloride and the Unidentified substance “4” turned out to be Sodium Chloride. The conclusion that substance “2” was Tin (II) chloride could be proven due to the fact that it reacted with Zinc and Sodium Hydroxide. When Tin (II) chloride reacted with Zinc, it began bubbling. This occurred because there was a single replacement reaction between Tin (II) Chloride and Zinc. Zinc is far more reactive than Tin (II) Chloride, making this a very likely conclusion. In the experiment, Tin (II) Chloride should have reacted with the Sodium Hydroxide because …show more content…
Sodium Chloride and Sodium Hydroxide do not produce a reaction with one another, as both of the reactants contain sodium. In a reaction, these two products will stay apart from each other. Moving on, Sodium Chloride Zinc will also produce no reaction. This is because Sodium Chloride and Zinc perform a single replacement reaction. Since Zinc is much less reactive than Sodium Chloride, therefore mixing the substances together will not give you a reaction. In order for a single replacement reaction to work, the lone element has to be more reactive, or higher on the reactivity series, than the element it would be replacing. Because a double replacement reaction occurs between Sodium Chloride and Nitric Acid, one again, there would be no reaction. Double replacements produce two brand new compounds, an aqueous solution, and a substance in a different state of matter. This is caused by two compounds trading cations or anions to create two new compounds. Because two soluble chemicals are incapable of reacting with one another, the “Solubility Chart” must be considered when dealing with double replacement reactions. Since there is not reaction between Sodium Chloride and Nitric acid, as well as the other two chemicals, the conclusion that Sodium Chloride is what Substance “4” consists of
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