Stoichiometry Lab Report

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The purpose of this lab will be to identify the percent yield of copper in the unbalanced equation _Al(s) + _CuCl2(aq) → _Cu(s) + _AlCl3(aq). This will be determined by cutting a piece of aluminium 9cm by 9cm, recording its mass in grams, preparing a copper (II) chloride solution using the weight tray and electronic scale to measure 5.0g of CuC12 and adding it to 100 mL of distilled water. Then, a stirring rod will be used to dissolve the piece of aluminium into the CuCl2 solution until it is no longer visible. Additionally, the mixture will be filtered using a filter paper (which was previously weighted) on a funnel and weighted after it is fully filtered. Furthermore, the chemical equation will be balanced, stoichiometry will be used to find

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1371 Words | 6 Pages
Abstract In this experiment the separation of a copper (II) chloride and sodium chloride mixiture was attempted. The main aim was to separate the compounds from eachother while receiving as much of the original mass of both substances as possible - in perfect conditions the original mass will be received after seperation. Many techniques were considered but dissolution, filtration and evaporation proved to be easiest and most reliable in a school environment with school equipment. The copper (II) chloride and sodium chloride mixture was dissolved in a methanol solution and filtered out leaving the sodium chloride behind.
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451 Words | 2 Pages
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800 Words | 4 Pages
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563 Words | 3 Pages
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729 Words | 3 Pages
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1237 Words | 5 Pages
(0.01 moles of NaOH) x (1 mole Ca(OH)2/ 2 moles of NaOH) = 0.005 moles of Ca(OH)2 Tube 1: (0.0020 moles of CaCl2) x (1 mole Ca(OH)2/ 1 mole of CaCl2) = 0.002 moles of Ca(OH)2 (0.002 moles of Ca(OH)2) x (74.08 grams/mole) = 0.1 grams = theoretical yield Tube 2: (0.0035 moles of CaCl2) x (1 mole Ca(OH)2/ 1 mole of CaCl2) = 0.004 moles of Ca(OH)2 (0.004 moles of Ca(OH)2) x (74.08 grams/mole) = 0.3 grams= theoretical yield Tube 3 (0.0050 moles of CaCl2) x (1 mole Ca(OH)2/ 1 mole of CaCl2) = 0.005 moles of Ca(OH)2 (0.005 moles of Ca(OH)2) x (74.08 grams/mole) = 0.4 grams =theoretical yield Tube
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902 Words | 4 Pages
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599 Words | 3 Pages
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1346 Words | 6 Pages
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Stoichiometry Lab Report

Chem 100 Final Lab Report

Chemical Elements Lab Report

Copper Cycle Synthesis

Compare And Contrast The Separation Of Copper Chloride And Sodium Chloride Mixture