1) A brief description of the activity The activity involved the testing of aggregates in a laboratory to determine whether they are suitable for use as aggregates for concrete. The tests involved the use of a Flakiness Index (FI) to define their shape, a grading and Fineness Modulus (FM) to determine their sizes and a 10% Final Aggregate Crushing Test (FACT) to determine their strength. During the laboratory tests the students were required to take notes of what was being said. 2) Importance of properties of aggregates Aggregates make up about 70% of the volume of concrete (Owens, 2013). They do not react with cement and water; they are present to make a stronger more durable and workable cement mix and are used as filler in the concrete …show more content…
It refers the proportion of flaky particles within a given sample. (Owens, 2013) The FI involves the use of a flakiness gauge, which is a flat piece of metal with rectangular gaps cut into it; each gap in the gauge represents a different size, measured in millimeters. It is calculated as the percentage of the mass of stone that will pass through gaps of a given width for the appropriate size of the aggregates. (Owens, 2013)Values of the Flakiness Index taken during the laboratory tests are shown in appendix 3.1.4) 10% Final aggregate crushing test (FACT) The FACT is used to assess the resistance of an aggregate to mechanical degradation and to compare aggregates. These results do not necessarily relate to the compressive strength of concrete made with that aggregate (Afrisam, 2016). Once the crushing has taken place the material is placed into a sieve and the final material is the material that passes through a 2,8mm sieve. If the final material is not exactly 10% of the original mass of material then the test has to be redone until exactly 10% is reached. All the groups’ results were put into a table and with these results a graph plotting a trend line could be produced. Using this trend line, the FACT results were calculated by solving for x in the trend line equation. This result came to be 367,5 …show more content…
Round aggregates are optimum aggregates to use because the load is distributed over the whole area of the aggregate. Elongated aggregates are weaker than round aggregates because the load is applied at a point of weakness on the aggregate. Aggregates have a FM as low as 0.5 (consists of very fine sand) and have a FM as high as 3.5 or more (consisting of very coarse sands). The medium range of FM lies between 2.4-2.9 thus means that there is a balance between fine and coarse sands
The weekly average was not precise due to the values on Tuesday and Thursday being so much higher proportionally compared to Monday and Wednesday (Graph 1 ). Specific heat was also a value which varied based on the accuracy of the execution of the experiment. Different days lead to different amounts of precision and this was due to the random errors. Random errors were mistakes caused by the experimenter. Tuesday had the lowest standard deviation for all the metals (Table 1).
As the $\chi^2/ndf$ of the fits in Fig.~\ref{fitbr15sysin} are $\approx$ 1, the fit error represents the uncertainty in the distributions. On the other hand, the $\chi^2/ndf$ of the fit functions in Fig.~\ref{fitbr15sysex} are $<<1$, shows that the errors are overestimated. Thus, in these cases, Equation~\ref{Ssdlumsys} is used for error estimation.
75 90 Doc 1 1.31556 1.80357 1.80357 Doc 2 1.75182 1.87012 1.87012 Doc 3 2.13338 2.27178 2.27178 Doc 4 1.56941 1.0743 1.0867
The Correlation coefficient=0.523. This correlation relies on the assumption that the variables are normally distributed, and that there is no presence of outliers. Statistics GPA final N Valid 105 105 Missing 0 0 Skewness -.053 -.334 Std. Error of Skewness .235 .235 Kurtosis -.811
0 0 0 0 0 15 40.1 40.1 0.2673 -0.35 0.89643061 30 24 64.1 0.4273 -0.64 0 60 23.5 87.6 0.584 -1.04 0.170474179 85 23.8 111.4 0.7427 -1.74 0.308657862 205 19.2 130.6 0.8707 -3.42 0.511460529
In conclusion, air pressure has a direct influence on the distance that the ball will travel when thrown. The hypothesis stated that if pressure is added to the football, then the distance the ball projects will increase when distance is a function of pressure. Based on the data that was collected from the experiment, the hypothesis was supported. When the football had more air inside, it went the farthest distance compared to the other two pressures that data was collected from.
11. 27. 35. Those arbitrary numbers remained in my head for an entire week. They were questions I knew I missed on my last test.
\section{Facility Static and Dynamic Control}\label{Calibr} The facility calibration is the transfer function between the oscillating gauge pressure $P_C(t)$ in the chamber (described in ~\autoref{Sub31}) and the liquid flow rate $q(t)$ in the distributing channel, i.e. the test section. Due to practical difficulties in measuring $q(t)$ within the thin channel, and being the flow laminar, this transfer function was derived analytically and validated numerically as reported in ~\autoref{Sub32} and ~\autoref{Sub33}. \subsection{Pressure Chamber Response}\label{Sub31} Fig.\ref{fig:2a} shows three example of pressure signals $P_C(t)$, measured in the pneumatic chamber.
33.385 million =10.235 million * exp (0.12*10) is the value of the of the population when the rate changes by an increase of 2%. 38.950 million =10.235 million * exp (0.14*10) is valuation of the future population when the rate increases by 4% from its original rate of 10% for a total rate of 14%. Each input is accurate in comparison with its Excel counterpart, however, the Word calculations will have greater precision due to the estimation of the of the Excel counterparts.
Use your results in Data Table 2 to support your answer.
The surface at which the concrete is supposed to be placed should be properly damped so that excess water is removed. Use of fibers or silica fumes can also help to reduce the crack formation. 5. Plastic Shrinkage in Shape of
Off shore dredging of sand and shingle in adjacent areas increases erosion in other areas and significantly affects the ecosystem in the dredging area. Large storms easily degrade beach replenishment inputs, thus increasing costs. £20.000 per cubic meter Managed retreat In areas where Managed retreat is permitted, it retains the natural balance of the coastal system. The eroded material promotes the development of beaches and salt marshes in specified areas.
With this small change (by 51.4 seconds), it can be concluded that there is a relationship between the different temperatures of sodium solution and the time it takes for the ice cube to melt in the sodium solution. The raw data graph also has a c or the y intercept of 64.24 seconds and the R2 value is 0.97281. R2 value is a fraction between 0.0 and 1.0, and has no units. An R2 value of 0.0 means that knowing X does not help you predicts Y. There is no linear relationship between X and Y, and the best-fit line is a horizontal line going through the mean of all Y values.
Norm-referenced tests are created by professionals, researched and published. They are used to compare a student with others that are similar to them. These comparable students are a norm reference group that is compose of those with similar culture, background, ethnicity, sex and other characteristics.