The probability of the Monty hall problem can be calculated with the use of Bayes Theorem (Bayes). Before I do however, let me first show how the theorem is deduced, which will also give an understanding of what it is. First it starts with the basic equation of conditional probability. P(A∩B)=P(B)∙P(A│B). The conditional probability of both event A and B happening is calculated by the probability of the event B multiplied by the probability of event A given event B happens.
To model the adsorption behavior two set of adsorption studies were studied and their correlation with the experimental data was assessed. This includes the Freundlich and Langmuir isotherms, which are the earliest and simplest known relationships describing the adsorption equation. 6.6.1 LANGMUIR ISOTHERM Langmuir isotherm equation in linear form can be shown as Ce/qe = 1/bqm +Ce/qm Where ,b and qm are constants related to the apparent energy of adsorption and the adsorption capacity, respectively qe → the amount adsorbed per unit mass of the adsorbent (mg/g) with an equilibrium concentration of Ce (mg/ L ). A plot of (Ce /qe) vs. Ce was linear (graph 6.9) and the constants qm and b were determined from the slope and intercept of the plot. The correlation coefficient obtained with the Langmuir equation was high, which indicated a good fit between the parameters.
This hypothesis testing uses the test statistics in which mechanism is based on the correlation integrals. The BDS test is a powerful tool for detecting serial dependence in time series. It tests the null hypothesis of independent and identically distributed (I.I.D.) against an unspecified alternative. The null and alternative hypothesis is as follows: H0:The data are independently and identically distributed (I.I.D.).
The ground state energy may be found by searching all possible wavefunctions for the one that minimizes the total energy. Hartree-Fock theory consists the structure of ψ and it is assumed to be an antisymmetric product of functions (fi) each of which depends on the coordinates of a single electron, that is; where det indicates a Slater determinant.11,12 Substitution of ψ into the Schrödinger equation results in an expression for the Hartree Fock
Then I find the middle location of all data in the upper half of the data rightward of the median (2.8) to get the third quartile (Q3). Then the difference between Q3 and Q1 is the interquartile range, the below-depicted image will demonstrate my approach ………………………………………………… Task 4 What is the formula for calculating the interquartile range? Solution to Task 4 The formula is IQR = Q3 – Q1 A short description of solution 4: According to Yakir(2011), “The inter-quartile range is the distance between the third Quartile (Q3) and the first quartile (Q1), i.e., IQR = Q3 - Q1” (p.
For n =2, there are two values allowed for l. The possible values of l are l=0 and l=1because this energy level is above the wells of l=0 and l=1and below l=2 (green) and l=3 (violet). In other words, there is only one possible orbital (1s) for the first energy level (n=1)). The existence of other superior orbitals (1p,1d,etc) is forbidden by the fact that their energy wells (in which they lie) are above the n=1n=1 energy. Figure 1: Sketch where n = 1 PART C: Sketch just the l = 0 effective potential. Add the locations of the n = 1,2,3 energy levels to your sketch.
For continuous random variables, the probability function is denoted f(x) and called the probability density function. Properties of discrete random variable: A probability function has two key properties: 0 ≤ p(x) ≤ 1, because probability is a number between 0 and 1 The sum of the properties p(x) over all values of X equals 1. If we add up the probabilities of all the distinct possible outcomes of a random variable, that the sum equals 1. Example: A coin toss has only two possible outcomes: heads or tails and taking a test could have two possible outcomes: Head or tail. The discrete possibilities of head can be as
The conductivity values can be used to calculate the conversion of sodium hydroxide. Sodium hydroxide is component B and due to the fact that conversion of B will be calculated, it is necessary to ensure that B is the limiting reagent. The relationship between conductivity values and conversion is given in equation 15. x= (K_START-K)/(K_START-K_FINAL )
When you multiply or divide measurements, the number of significant figures in the answer is equal to the number of significant figures in the least precise measurement. For the addition or subtraction of measurements, the number of significant figures in the answer is equal to the number of decimal places in the least precise measurement. Nonzero integers always count as significant figures, and exact numbers, quantities obtained without the use of a measuring device, have an infinite number of significant figures. For example, the number 15.1 has three significant figures because none of the integers are zero. However, there are three classes of zeros: leading zeros, captive zeros, and trailing zeros.
It has two properties - a code with a minimal length, it is not only the prefix code and is therefore uniquely decodable. The disadvantage is that we should know the probability distribution of the occurrence of each symbol. Sample Huffman’s coding table of a clear and coded pictures are as follows (Table1 and Table 2) Table 1: Huffman’s Coding – Clear Picture Bits DC, Class0 DC, Class1 AC, Class0 AC, Class1 1 0 0 0 0 2 82 537 111597 41239 3 2811 494 39917 30606 4 886 602 46384 31571 5 837 542 30163 18650 6 724 475 5825 7639 7 547 293 14139 724 8 213 112 6943 3479 9 44 17 2526 842 10 0 0 2580 352 11 0 0 658