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Copper Synthesis Lab Report

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The Single Replacement Lab of Iron Replacing Copper in a Copper (||) Chloride Solution Lab The purpose of this lab was to help the students further their understanding of single-replacement chemical reactions, and to have a hands-on experience with it in order to practice equation writing and stoichiometry functions. In this experiment, an iron nail was placed in a solution of Copper (||) Chloride that was dissolved with water in a baby food jar. Observations were taken over the next three (schools) days. On day 1, the masses of the baby food jar, the Cu (||) Chloride, and iron nail were recorded. The nail was placed in the Cu (||) Chloride and water solution. On day 2, the nail was removed from the copper buildup surrounding it, and placed …show more content…

CuCl2 (aq) + Fe (s) = Cu (s) + FeCl2 (aq). The second value calculated was the mass of the iron nail used. This was calculated with the end mass of the nail being taken away from the initial mass of the nail. Using numeric values, the equation looked like: 6.8639 grams - 4.4564 grams = 2.4075 total grams of iron used. The third value calculated was the moles of iron used, using the formula of grams of iron used, multiplied by 1 mole of iron over the gram atomic weight of iron. With values inputed, the formula was 2.4075*1 mole/55.85 grams, equaling .0431 moles of iron. The next value calculated was the moles of copper produced, figured out with the formula of moles of iron used multiplied by moles of copper over moles of iron used. With values inputed, the formula was .0431 moles of iron*1 mole of Cu/1 mole of iron = .0431 moles of copper. The fifth formula used for the purpose of calculating the grams of copper produced was moles of Cu multiplied by the gram atomic weight of copper over moles of copper. This ended up being used as .0431 moles of Cu* 63.55 grams of Cu/ 1 mole of Cu = 2.740 grams of copper produced. The actual yield of copper is calculated by the baby food jar and copper mass minus the mass of the baby food jar. 97.7070 grams- 94.8280 grams = 2.8791 grams of copper. The percent yield of copper is calculated by the actual yield (value #6) being divided by the theoretical yield of copper (value #5), then multiplied by 100. 2.8791 grams/2.740 grams *100= 105.07%

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