Dhake Lab Report
1.The transmitted light that was produced by the flashlight differs in terms of how much solution that was present in a test tube. Given the 5 test tubes, dye solution had the least transmitted light. It had the least transmitted light because the more molecules that is present in a container, the harder the light can pass through. Absorbance is the reason why light had to interact with a lot of molecule that is present in the dye solution. Unlike the clear water light can pass through easily because of its lesser presence of molecules.
2.The color differs with depth or length of the solution because when we are to use the flashlight above the test tubes the color may seem to be darker or more concentrated and if we are to light it from the
6.03 Pre Lab
993 Words | 4 PagesQuestion 4: List the 3 errors; • Adding too many drops of NaOH at the same time would affect the results because we can’t determine the exact equivalent point when the color changed. The results won’t be accurate and that will affect all the data that are dependent on the amount of NaOH to titrate. • Other error could be the hardness to notice a color change; we always use a white paper under the flask to determine when the color changes right away. And if we don’t use the white paper it will be hard to determine the color change and the amount of NaOH that was used to titrate it. • Also other source of error could be by not rising the burette with NaOH before we fill up with it, or it maybe they were rinsing it with a lot of NaOH which could affect the data recording for NaOH amount of titration.
6.03 Calorimetry Lab
775 Words | 4 PagesThe cuvette was placed in the spectrophotometer with the arrows, on both the cuvette and the SpectroVis, facing the same side. After the recording, the cuvette was removed from the SpectroVis and the content was poured back into the original volumetric flask. The absorbance as well as the maximum wavelength of each solution was recorded in Table 3 and
Nt1310 Unit 10 Lab Report
302 Words | 2 Pages%% Init % clear all; close all; Fs = 4e3; Time = 40; NumSamp = Time * Fs; load Hd; x1 = 3.5*ecg(2700). ' ; % gen synth ECG signal y1 = sgolayfilt(kron(ones(1,ceil(NumSamp/2700)+1),x1),0,21); % repeat for NumSamp length and smooth n = 1:Time*Fs '; del = round(2700*rand(1)); % pick a random offset mhb = y1(n + del) '; %construct the ecg signal from some offset t = 1/
Pt1420 Unit 6 Lab Report
155 Words | 1 PagesSuppose you need to find the fractional European call and the fractional European put options. Let the Hurst parameter be $H=0.85$, the $\sigma=0,25$, $r=0.10$, $S_{fbm} = 100$, $K = 95$, we have \begin{eqnarray*} d_1^{fBm} & = & \frac{\ln{\frac{S}{K}} + \frac{1}{2}(r( T - t) + \frac{(1)\sigma^2{( T^{2H} - t^{2H})}}{2})}{\sigma{\sqrt{T^{2H} - t^{2H}}}}\\ & = & \frac{\ln(\frac{105}{100}) + (0.10(0.25 -0) + \frac{(1){0.25^2}{0.25^{2(0.85)} - (1)0.25^{2(0.85)}}}{2}}{(0.25){\sqrt{0.25^{2(0.85)} - 0}})} \end{eqnarray*} we obtain $d^{fBm}_1= 1.0558$. We find in the normal distribution that $N(1.0558)= 0.8544$ and $N(-1.0558) = 0.1456.$
Pt1420 Unit 3 Lab Report
485 Words | 2 PagesTesting phase finds differences in positive/negative documents by the centroid obtained in training phase by ranking each of them. The simple way to estimate similarity between documents and centroid by summing weights of patterns which are in the documents. VII. Experimental Results To determine accurate measures of similarity or difference between documents you depict results by graph pattern and table pattern. The experimental setup consists of relevant documents that you termed as positive and negative documents .i.e
Ccto10 Unit 2 Lab Report
335 Words | 2 PagesK.D.A. Saboia et al. , (2007) have been prepared the Bi4Ti3O12–CaCu3Ti4O12 {[BIT(X)–CCTO(100-X)]} composite powders through solid state reaction method and calcined in the range of 900 to 1020 ºC for 12 h. The as-prepared powders have modified in the form of thick film onto alumina ceramic substrate by utilizing screen printing. At 100 Hz, the value of dielectric constant (κ) of CCTO100 and BIT100 is 316.61 and 53.64 respectively. Conversely, the composite with X=20 % shows an unexpected dielectric constant of 409.71, which is around 20% higher in comparison with the CCTO.
Unknown Lab Report
1444 Words | 6 PagesUnknown Lab Report Unknown # 25 By: Jenna Riordan March 19, 2018 Bio 2843 1. Introduction Microbiology is the study of microorganisms found in all different environments throughout Earth, from the hot thermal vents at the bottom of the ocean to the ice at the top of a mountain.
Enzyme Lab
901 Words | 4 PagesSet the wavelength to 470 nm, this is to measure the tetraguaiacol. Set the spectrophotometer to zero by using a blank. The blank should contain 13.3 mL of distilled water, 0.2 mL of guaiacol, and 1.5 mL of enzyme extract in a clean test tube. After, transfer a portion of this mixture into a cuvette, cover the top of the cuvette with Parafilm and then place the cuvette into the spectrophotometer and set it to
Pt1420 Unit 6 Lab Report
407 Words | 2 Pages• Write down the highlighted numbers. Do you observe a pattern? • Does the pattern grow? What is the reason for this? • Write down the last number (say 53).
Tn 4351 Unit 5 Lab Report
506 Words | 3 PagesTn 4351 was originally isolated from bacteroides fragilis [30] . The transposon was successfully introduced into Cytophaga succinicans, Flavobacterium meningosepticum, Flexibacter canadiansis, Flexibacter strain SFI and Sporocytophaga myxococcoides by conjugation [25]. Tn 4351carries two antibiotic resistance gene. One of the codes for resistance to erythromycin and clindamycin which is expressed in bactroides but not in E.Coli. The other gene codes for resistance in tetracycline and is expressed in aerobically grpwn E. coli, but not in anaerobically grpwn E. coli or in bacteroides.
Nahco3 Lab Report
558 Words | 3 PagesResults The data obtained from the experiment had undergone statistical analysis using t-tests and the results were recorded in Figure 1.0 and Figure 1.1 above. According to the data obtained in Figure 1.0, the p-value is less than 0.05 in all 5 treatment solutions. It is also shown intensity Figure 1.0, the calculated t-value of each concentration of NaHCO3 in each treatment is greater than the critical t-value.
Alkaline Phosphatase Enzyme Lab Report
2575 Words | 11 PagesUse these results to determine the product concentration, using Beer-Lambert’s Law: A= ɛCl (where A is the absorbance, ɛ is the molar absorptivity, C is the product concentration and l is the length of solution that the light passes through). Calculate the product concentrations at every minute for 10 minutes for all 7 of the test tubes using Beer-Lambert’s Law. Plot a graph of product concentration vs. time and then use the gradients of the 7 test tubes to determine the velocities of the reaction. After calculating the velocities, plot a Michaelis-Menten graph of velocity vs. substrate concentration.
Lab Report On Acid Base Titration
1346 Words | 6 PagesThrough the titration process, we are able to identify physical changes to the mixture such as the colour change to indicate the end point of the experiment. For example, the colour changes of phenolphthalein from colourless to pink and methyl orange from red to orange and subsequently yellow. Acids produce hydrogen ions and bases produce hydroxide ions. This causes the indicator to change colour due to the colour difference from the undissociate molecules.
Column Chromatography Lab Report
1696 Words | 7 PagesColumn chromatography set-up After setting up the column, 2 10-ml of the chosen solvent was obtained and was placed in two separate test tubes. Using a dropper, ~0.5 mL of the food dye was put into the column by dropping it at the side of the column in a circular motion. The chosen solvent was then added just after the green food
Chromatography Lab Report Discussion
1458 Words | 6 PagesThe solution with the pigments was spotted 15 times on both region A and region B and then allowed to dry. When the plate was dry it was placed into the tank for at least 20
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