The objectives of this experiment were to use knowledge of chemical formulas and chemical nomenclature to experimentally determine the empirical formula of copper chloride. Common laboratory techniques were used to conduct a reaction between copper chloride and solid aluminum in order to get rid of the water of hydration. The amount of water of hydration in the sample of copper chloride hydrate was calculated by measuring the mass before and after heating the sample. Afterwards, an oxidation-reduction reaction was conducted, resulting in elemental copper. Using the Law of Definite Proportions, the mass of this product was used to determine the number of moles of copper and chlorine in the sample, which led to being able to determine the …show more content…
As the water was added to the heated sample, the solid copper chloride began to dissolve into a pretty blue-green solution, as a result of the compound breaking apart into individual Cu2+ and Cl- ions. When the water was first mixed with the copper chloride, it dissolved the solid pretty slowly, turning into a sort of mush at first. However, eventually, the water dissolved all of the solid copper chloride and the solution was homogenous. Since the compound just changed physical form, from solid to liquid, this change was purely physical. Just as in the first part of the experiment, the chemical character of the compound was not altered, so the compound did not experience a chemical change. The dissolution of the salt could be reversed by evaporating the water as shown in part one of the experiment, just as evaporating the water could be reversed by adding water as demonstrated in part two of the …show more content…
As soon as the wire was submerged into the solution, the aluminum atoms and the copper (II) ions underwent a reduction-oxidation (redox) reaction, meaning aluminum was oxidized and donated its electrons to the copper ions, which were reduced. As a result, solid copper began to form on the surface of the aluminum wire, giving the wire a brown-orange color that resembled rust. The wire had to be regularly shaken in order to remove the solid copper particles and thereby expose more of the aluminum wire to react with the surrounding solution. As the reaction progressed, the liquid copper chloride solution slowly began to lose its color and turn clear. This was a chemical reaction, as seen by the bubbles formed with the wire was added, meaning gas was released when aluminum was oxidized and copper was reduced, but it also gave rise to physical changes, such as the change in color of the solution from blue-green to rusty orange to clear. The glass rod was used instead of the metal spatula because the metal from the spatula could have reacted with the copper ions in place of the aluminum wire, which would have interfered with the calculations of the solid copper’s
An error that could have been present during the lab includes not letting the zinc react completely with the chloride ions by removing the penny too early from the solution. For instance, the percent error of this lab was 45.6%, which was determined by the subtraction of the theoretical percent of Cu 2.5% and the experimental percent of Cu 3.64% and dividing by the theoretical percent of Cu 2.5%. This experiment showed how reactants react with one another in a solution to drive a chemical reaction and the products that result from the
The purpose of this lab was to be able to use physical characteristics to determine the identity of an unknown compound. The data from this experiment classified aluminum as metallic; ascorbic acid, paraffin, palmitic acid, sucrose, graphite, and water as molecular; sodium chloride as ionic. In order to determine this, 3 tests were conducted. The first test was to test the conductivity of each substance at room temperature. In this test, only graphite and aluminum conducted.
The heating of the solution caused the reaction to start which decomposed Cu(OH)2 and made the solution colorless and darkened the precipitate. The fourth step was the formation of CuSO4. After the solution was decanted from the precipitate and washed with near boiling water, 6 M H2SO4 was added to the beaker containing Copper (II) Oxide and this caused the precipitate to dissolve and the liquid become clear blue. The last step was the formation of Cu(s). This step recovered Solid elemental copper.
Abstract In this experiment the separation of a copper (II) chloride and sodium chloride mixiture was attempted. The main aim was to separate the compounds from eachother while receiving as much of the original mass of both substances as possible - in perfect conditions the original mass will be received after seperation. Many techniques were considered but dissolution, filtration and evaporation proved to be easiest and most reliable in a school environment with school equipment. The copper (II) chloride and sodium chloride mixture was dissolved in a methanol solution and filtered out leaving the sodium chloride behind.
Malachite was synthesized using the following reaction (1): 2CuSO4*5H2O(aq) + 2Na2CO3(aq) CuCO3Cu(OH)2(s) + 2Na2SO4(aq) + CO2(g) + 9H2O(l) Based on this chemical equation, two moles of aqueous hydrated copper (II) sulfate reacted with aqueous sodium carbonate, a precipitate of copper (II) carbonate hydroxide was formed along with aqueous sodium sulfate, gaseous carbon dioxide, and liquid water. The copper (II) carbonate hydroxide precipitate is also the malachite that was obtained from the solution. It was known that a chemical reaction was occurring when the copper (II) sulfate solution was mixed in with the sodium carbonate based on the fact that the color of the solution changed from blue to light blue and the solution frothed. The malachite
The Statue of Liberty is a prime example of oxidized copper. The oxidized surface consists of insoluble ionic compounds of copper (II) oxide and copper (II) carbonate. In class, we did an experiment with where we changed copper into its different states. For example, we added sodium hydroxide to copper (II) nitrate. We turned the copper into a
The purpose of this lab was to determine metal ions in two unknown compounds via a flame test. In order to do this, seven flame tests of known metal chloride compounds were completed and the results were observed and record. The known compounds ' results could be compared to the unknowns. The reason the light, of flame was emitted is because of electrons moving from excited state to ground state, releasing energy. Often times this energy is visible part of the electromagnetic spectrum, 400-750nm.
Balanced Chemical Equation: Cu(s) + 4HNO3(aq) —> Cu(NO3)2 (aq) + 2NO2 (g) + 2H2O (l) Reaction 2: when sodium hydroxide (NaOH) is added to copper (II) nitrate (Cu(NO3)2), a double displacement reaction will occur. Copper and sodium will displace each other to create copper (II) hydroxide and sodium nitrate. Balanced Chemical Equation: Cu(NO3)2 (aq) + 2NaOH (aq) —> CuOH2 (s) + 2NaNO3 (aq) Reaction 3: When copper (II) hydroxide is heated, a decomposition reaction will occur. The reaction will decompose forming two compounds, Copper (II) oxide, and water. Balanced Chemical Equation: Cu(OH)2 (s) + Heat —> CuO (s)
Throughout the experiment, copper was altered a total of 5 times, but after the final chemical reaction, solid, elemental copper returned. Each time the solution changed color, a precipitate formed, or when gas appeared, indicated that a chemical reaction was occurring. For the first reaction, copper was added to nitric acid, forming the aqueous copper (II) nitrate (where the copper went), along with liquid water, and
Then, this process was repeated 2 more times, using deionized water and standard sodium chloride solution as the
Introduction: In this lab, of water in a hydrate, or a substance whose crystalline structure is bound to water molecules by weak bonds, is determined by heating up a small sample of it. By heating, the water of hydration, or bound water, is removed, leaving only what is called an anhydrous compound. Based on the percent water in the hydrate, it can be classified as one of three types: BaCl2O ⋅ 2H20, with a percent water of about 14.57%, CuSO4
When hydrochloric acid and magnesium ribbon were mixed, it was a chemical change because gas was produced as shown in the bubbles, and there was also heat. When sodium hydroxide and copper sulfate solution were mixed, it was a chemical change because there was a jelly-like substance formed in the middle, which was a precipitate. When sodium chloride and water were mixed, it was a physical change because there was no heat, light or gas produced, it stayed the same colour, the sodium only dissolved. When copper sulfate solution and steel wool were mixed, it was a chemical change because there was a completely new colour created, a pink-copper colour. When hydrogen peroxide and manganese dioxide were mixed, it was a chemical change because gas was produced, which can be seen in the bubbles that formed.
Why using a copper cup might be good for you As a little girl, I remember my granddad storing up drinks in a copper cup overnight and he would almost force us to drink from it first thing in the morning. He claimed that it was healthy for us to have a sip of the water he stored in there. That was some decades ago. For years I had not seen this cup until a few months ago.
Copper is a solid metal found in group 11 in the periodic table. Humans first began to use this metal over 10,000 years ago. They used it to make weapons and later also coins, water pipes and ships. The Romans and Egyptians are known to have used copper in wide ranges. Copper was used for so long because it is relatively easy to mine and extract from its ore.
Wear suitable protective clothing if ingested, seek medical advice immediately and show the container or the label. 3-Copper chloride CuCl2 : It's a solid chemical compound with yellow-brown color, sabsorbs moisture to form a blue-green dihydrate. It occurs in nature as very rare mineral. Copper chloride dissolve in aqueous solutions to give [Cu (H2O)6]2+ which has blue color, and yellow or red color of the halide complexes [CuCl2+x]x-. Concentrated solutions of CuCl2 are green due to the combination of these various chromophores.