Type 1: metal vs metal Example: Explain why Mg has a higher melting point than Na. Reason: Compare the number of delocalized electrons. Type 2: ionic compound vs ionic compound Example: Explain why NaF has a higher melting point than NaCl. Reason: Compare lattice energy. Type 3: simple molecule vs simple molecule Example: Explain why H2O has a higher melting point than H2S. Reason: Compare the relative strength of the intermolecular forces. Type 4: ionic compound vs simple molecule Example: Explain why NaCl has higher melting point than H2O. Reason: Compare ionic bond strength with weak intermolecular forces. Type 5: giant molecule vs simple molecule Example: Explain why SiO2 has a higher melting point than H2O. Reason: …show more content…
As it is the same for all gases, R is also called the universal gas constant. R = 8.31 J K-1 mol-1 Assuming a gas sample to be under ideal conditions, the value of R can be determined by measuring its volume, temperature and pressure and substituting the values into the ideal gas equation. Consider one mole of a gas at standard temperature and pressure (s.t.p). E.g., P = 101 325 Pa, V = 22.4 x103 m3, n = 1 mol and T = 273.15 K Using PV = nRT, R = PV/nT = ((101325)(0.0224))/((1)(273.15)) = 8.31 J K-1 mol-1 Experimental Determination of the Molar Gas Constant When magnesium is added to an aqueous solution of hydrochloric acid, the following reaction occurs: Mg(s) + 2HCl(aq) MgCl2(aq) + H2(g) Preliminary Calculation (to determine the amount of reactants to be used) With a graduated gas syringe of 100 cm3 capacity, assume that 80.0 cm3 of H2 gas is collected. no. of moles of H2 gas = 80/24000 mol = no. of moles of Mg mass of Mg = 80/24000 x 24.1 = 0.0803 g Let the concentration of HCl(aq) used be 0.500 mol dm-3. no. of moles of HCl = 80/24000 x 2
Question3: Experiment 3 The unknown acid sample was 1 • Monoprotic Acid Trails Initial NaOH solution (mL) final NaOH solution (mL) The volume of NaOH to titrate the acid (mL) Amount of Unknown Acid sample 1 (g) The moles of the Unknown Acid (mol) Molar mass of the Unknown Acid (g/mol) A 3.38 28.31 24.93 0.150 0.0026 57.69 B 0.18 29.32 29.14 0.175 0.0029
A two-hundred and fifty milliliter(ml) flask was zeroed out on the scale. Fifty milliliters of HCl was put into the flask and weighed. The unknown mixture was poured into the HCl while
In order to find the amount of a product made during a double displacement reaction, the product has to be separated from the solution. From this number of moles of precipitate can be calculated. From there the number of moles of reactants can be calculated using the mole ratios of the particular reaction that occurred. As seen in Table 5 it is shown that by finding out the number of moles of the unknown, the molar mass of the unknown can be calculated. From the found mass of the unknown compound, the mound of the original ion can be found.
Green with a silver nitrate (AgNO3) solution. Assuming that certain amounts of AgNO3 was dissolved in a particular amount of water to produce the solution. Find out how many moles of Na2CO3 were involved in the silver nitrate reaction first. To my knowledge of Mr. Green’s addition of 1.5 grams of Na2CO3 to the silver nitrate solution comes from the statement. Since Na2CO3 has a molar mass of 105.99 g/mol, the amount of Na2CO3 is: moles of Na2CO3 = mass / molar mass moles of Na2CO3 = 1.5 g / 105.99 g/mol moles of Na2CO3 = 0.0141 mol
Which of the following unit is used to indicate mass? a. Cm3 b. Um c. Mg d. mL 21. Which of the following demonstrate a chemical reaction of water?
The melting point of sulphur is 112.8 °C and the boiling point of Sulphur is 444.6 °C. Sulphur has an equal number of proton and neutron due to its atomic mass subtracted by the proton/atomic number. Sulphur
Using the equation m = ΔTf/Kf , the molality of the unknown solution was found. Then, moles of unknown were calculated, which was used to calculate the average molar mass of unknown. Theory: After the experiment was completed, the data
The equation used to determine the molar mass is derived from the Ideal Gas Law equation. The objective of this experiment aims to determine the molecular mass of a
It can be hypothesized that the water in the product affected the melting point
This number was found by dividing the 0.282 g by the number of moles of NaOH, 0.00201 moles (which was found by dividing the 20.1 mL used by 1000 and multiplying that number by the 0.1 M concentration). The molecular weight data can be used to compare and identify experimental data to that of known data in order to identify the unknown. The known molecular weight of benzoic acid is 122.12 g/mol, so there were errors in obtaining the molecular weight from the lab as the lab molecular weight is almost 20 g/mol higher. These errors could have been caused by impurities remaining in the final product such as the previously used/present magnesium, iodine, or the original
These melting and boiling points are very high which is caused by strong attractive forces. Metallic bonding is the strong attraction between closely packed positive metal ions and a 'sea' of delocalized electrons. Iron as a pure element on the periodic table is also a good conductor, which relates back to the features of metallic bonding. Because the electrons involved in the bond of iron are free-moving, iron is a good conductor. Network covalent bonds generally have very high melting points, and substance A can be classified as a covalent network crystal since it has a melting point of 3974oC. Covalent networks are insoluble in water – they cannot be broken apart by trying to dissolve them.
One major source of error is that magnesium chloride is a hexahydrate, and water moisture from the air may have evaporated into the compound before weighing. Another source of error is that water droplets condensing on the side of the beaker added mass that was assumed to be only the synthesized compound. The two purity tests that were conducted, pH and flame tests, indicated that no basic or acidic compounds were
Also, salt is an ionic compound and not a polar covalent compound, even though it did not melt last, due to the fact that the elements Na and Cl, both lose or gain an electron and then bond because of their opposite charges, which is a property only ionic bonds possess. The wax was the only substance whose results were synonymous with my hypothesis, since it required a low temperature for its melting point and was not soluble in water, both properties of nonpolar covalent compounds. Potential sources of error included not labeling the spots each substance was placed in the aluminum foil boat, seeing as the result for sugar seemed to be the correct conclusion for salt and vice versa. A future experiment would involve individually testing each substance in an aluminum foil boat, of the same brand, on a heat plate in order to avoid uncertainty. Each substance should be timed to record the precise time each substance began to melt or burn.
10 g b. 12 g c. 9 g How many moles are there in 235 g CaCO3? 235 mol b. 23 mol c. 2.35 mol How many moles are there in C2H2? 1.07 mol b. 1 mol c. 0.227 mol 10. How many grams of magnesium are there in 7.52 mol MgO?
Procedure A. Preparation of NaOH solution The molarity of a solution is the ratio of the number of solutes dissolved in a liter of solution. To figure out the needed mass (in grams) of NaOH pellets to be dissolved in a 0.25 L of water, remember that a mole is equivalent to the quotient of mass over the molar mass of the substance. This was used to rearrange the base formula and to derive the mathematical equation of mass in terms of molarity. mass (g) =