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Flame Test Lab Report

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Introduction: In this experiment, we are required to discover the 2 unknown chemicals provided by the teacher through the usage of different lab equipment and scientific procedures to conclude what the unknown substances are. The findings/results will be presented in a qualitative table and further discussed. There are 6 possible substances that the 2 unknowns could be. If the substance is benzoic acid then it would have to pass the organic solvent test because it dissolves in only organic solvents, while if it were silicon dioxide it would fail both solubility tests for organic and aqueous solvents. When doing the flame test, if the flame colour of the substance is yellow then it is either sodium chloride or sodium carbonate. The difference between sodium chloride and sodium carbonate is that the first is pH neutral while the latter is basic, which means a pH test would need to be conducted to …show more content…

Based on the chemicals table provided, it was evident that there is only one substance that can dissolve in an organic solvent; benzoic acid. If Substance B did not dissolve in an organic solvent then it likely would have been likely to have been one of the other substances. If it dissolved in water then a flame test would have been used to determine whether it was one of the four substances Sodium Chloride, Sodium Carbonate, Glucose and Potassium Chloride. However, if it had not dissolved in water it would have ended up being Silicon Dioxide. If the result for the flame test ended up being yellow then a pH test would have to be conducted to find out if the chemical was pH neutral or pH basic. If it were pH neutral then it would be Sodium Chloride and if it were basic then it would be Sodium Carbonate. However, if the colour of the flame test was light lilac then the chemical is Potassium Chloride and if the colour of the flame did not change at all then the compound is

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