PROBLEM 3 - GEIGER COUNTER Introduction: In this problem we assume that we are at our placement at the Radiation Protection Institute of Ireland we have been assigned to the national laboratory for measurement of radioactivity levels in the environment. Our work involves the use of a Geiger counter – a device that detects radiation such as alpha particles. Since we are going to use it regularly we are expected to have a full understanding of the principals of operation of the equipment. In order to develop the understanding principles, we are asked to draw a sketch of Geiger counter and show the main components and explain their role, explain the principle of operation of the device, show the electric field lines created in a Geiger’s counter …show more content…
The ionization initiates a momentary avalanche of electrons accelerate by the high voltage potential used to power the Geiger counter tube. This avalanche, create a momentary conductive path between the wire at the center of the tube (Anode) and the wall of the tube (Cathode), resulting in a ‘click’ sound. By measuring the number of the clicks, the instrument indicates the radiation levels. (2) Radiation (dark blue) is moving randomly outside the detector tube. Some of the radiation enters the window (gray) at the end of the tube. When radiation collides with gas molecules in the tube (orange), it causes ionization, some of the gas molecules are turned into positive ions (red) and electrons (yellow). The positive ions are attracted to the outside of the tube (light blue). The electrons are attracted to a metal wire (red) running down the inside of the tube kept at a high positive voltage. Many electrons travel down the wire making a burst of current in a circuit connected to …show more content…
(4) Potential difference between two points is the work done in moving unit charge (i.e. one coulomb) from one point to the other, the formula to find potential difference is: V=W/Q (1) Where V is the potential difference in volts, W is the work done or energy transferred in joules, J and Q is the charge in coulombs, C. (5) The electric field of an infinite line charge with a uniform linear charge density (cylinder) can be obtained by a using Gauss' law. Considering a Gaussian surface in the form of a cylinder at radius r, the electric field has the same magnitude at every point of the cylinder and is directed outward. The formula for this is: E=1/(2πε_0 ) λ/r (2) Where E is the electric field, ε_0 is the permittivity constant, λ is the charge per unit length and r is the radius. (6) We need to derive a formula that shows the relationship between electric field and potential difference to do that we do the following
4.1.6 Flip ops as Counters As can be seen from Figure 4.7 and Figure 4.8, a T-FF can be implemented using a D- FF feeding back the negate output /Q to the input D. The input clock to be divided is then provided at the CLK input. Cascading n T-FF stages as shown in Figure 4.8, it is 26 possible to divide the input frequency by a factor of 2^n . Based on current requirement Figure 4.7: FlipFlop of IC, size and availability and operating temperature, the rst combination which is the cascade of divide-by-4, divide-by-10 and divide-by-10 is chosen. The ip op as divide by 4, 10, 40 etc have been simulated with ADS.
The design relied on two Schmitt triggers to generate the two different tones while using the transistors to act as a switch. This causes it to trigger continuously between two unstable states, allowing automatic switching between two frequencies producing two different tones. The RC values between the two Schmitt triggers will differ. Capacitors charge and discharge faster when it’s resistance is smaller.
For most sequences at position 4 and 5 we observe only the nucleotides G and T, respectively. There may be rare cases where other nucleotides may also be found. To consider such observations, we need to do a process called additive smoothing or Laplace smoothing to smooth the categorical data. [9] In this case, we add 4 sequences: AAAAAAAAA, CCCCCCCCC, GGGGGGGG, TTTTTTTTT.
I need to find the area of rectangle ABCD. I know that ABCD is a rectangle with diagonals intersecting at point E. Segment DE equals 4x-5, segment BC equals 2x+6, and segment AC equals 6x. I predict that To find the area of rectangle ABCD I need to find out the base and height of the rectangle. The first step is to find what x equals. Since I know the intersecting line segments AC and DB are congruent that means when I times the equation 4x-5 for segment DE by two it will equal the equation 6x for segment AC.
For this experiment we utilized varying forms of Ohm’s law (V=IR), rules for resistors in series (Rtotal=R1+R2+…) and parallels (1/Rt=1/R1+1/R2+⋯), and Kirchhoff’s Junction Rule (ΣIi=0). For these models we assumed that the DMM’s produced accurate readings
%% Init % clear all; close all; Fs = 4e3; Time = 40; NumSamp = Time * Fs; load Hd; x1 = 3.5*ecg(2700). ' ; % gen synth ECG signal y1 = sgolayfilt(kron(ones(1,ceil(NumSamp/2700)+1),x1),0,21); % repeat for NumSamp length and smooth n = 1:Time*Fs '; del = round(2700*rand(1)); % pick a random offset mhb = y1(n + del) '; %construct the ecg signal from some offset t = 1/
(a) 3Mbps / 150Kbpa =3 X 1024 / 150 = 3072 / 150 =20.48 20 Users can be supported 150Kbps dedicated. (b)
Figure shows the intersection of line joining the camera center and image points ${\bf x}$ and ${\bf x'}$ which will be the 3D point ${\bf X}$.\\ \end{figure} The ‘gold standard’ reconstruction algorithm minimizes the sum of squared errors between the measured and predicted image positions of the 3D point in all views in which it is visible, i.e.\\ \begin{equation} {\bf X=\textrm{arg min} \sum_{i} ||x_i-\hat{x_i}(P_i,X)||^2} \end{equation} Where ${\bf x_i}$ and ${\bf \hat{x_i}(P_i,X)}$ are the measured and predicted image positions in view $i$ under the assumption that image coordinate measurement noise is Gaussian-distributed, this approach gives the maximum likelihood solution for ${\bf X}$. Hartley and Sturm [3] describe a non-iterative
Using the data provided in each one of these tests it can be assumed that one has done the steps to be able to determine the magnitude and orientation of the charges of the tape in each test, thus, allowing them to apply the same principle to any object they so desired. Their results would line up with the following; that if the two pieces of tape are torn from the same 40 centimeter strip then the tops of both pieces of tape would be positive and the bottoms of both pieces of tape would be negative and that if they would double the tape the attraction or repulsion in general would lower due to the increased density. Their data would also show that two pieces of tape ripped from each other would result in one piece being entirely positive and the other being entirely negative, they would also be able to state that the orientation of how the tape is paired up doesn’t matter.
1. The test subjects will prepare for sleep by acquiring everything needed for the subjects’ sleep preferences. 2. The test subjects will all set alarms on their smartphones for approximately 6, 8, and 10 hours after the subjects’ enter the resting period (Subjects may wake during the resting period for the bathroom, but they must not stay awake for more than ten minutes at a time to prevent as much deviation as possible.). 3.
1. There are two ways of maximizing points in this experiment. The first one is that I should connect myself to a vertex that is in the biggest component and purchases immunization. Since the probability of being infected is based off of expected value, I would have less than 1% chance of getting infected. The second way is that I try to make myself stay in the second-largest connected component.
1. What area/aspect of this setting is the most challenging? 2. In the setting, you work in, is there a certain population of patients you see more? How does this affect you?
In Dixon and Brooks experiment unlike what I observed at the
Anything that has motion involved is kinetic energy. The motion can be able to produce kinetic energy. An object that is moving can be able to do work with anything it hits. The conclusion of its motion is the amount of work being done. Kinetic energy can be passed from one object to another by clashing towards each other.
Chemistry IA Background information: Introduction: Electrolysis it’s a chemical process that when you pass an electric current into a solution or a liquid that contains ions to separate substances back to their original form. The main components that are required for electrolysis to take a place are: Electrolyte: it’s a substance that when dissolved in water it ionize and then it will contain free moving ions and without these moving ions the process of electrolysis won’t take place. Direct current (DC): This current provides the energy needed to discharge the ions in the electrolyte Electrodes: it’s an object that conducts electricity and it’s used in electrolysis as a bridge between the solution and power supply. A great example