CH3COOH And Naoh Lab Report

The Wittig reaction is valuable reaction. It has unique properties that allows for a carbon=carbon double bond to form from where a C=O double bond used to be located. Creating additional C=C double bonds is valuable due to its use in synthesis. The Wittig reaction will allow the synthesis of Stilbene (E and Z) from a Benzaldehyde (Ketcha, 141). One purpose of a Wittig reaction is the formation of alkenes from aldehydes or ketones employing a carbo-phosphorous ylide, which is stabilized vie resonance to allow for the carbon bonded to phosphorus to be deprotonate from by a base (Ketcha, 142).

The goal of the experiment is to synthesize a bromohexane compound from 1-hexene and HBr(aq) under reflux conditions and use the silver nitrate and sodium iodide tests to determine if the product is a primary or secondary hydrocarbon. The heterogeneous reaction mixture contains 1-hexene, 48% HBr(aq), and tetrabutylammonium bromide and was heated to under reflux conditions. Heating under reflux means that the reaction mixture is heated at its boiling point so that the reaction can proceed at a faster rate. The attached reflux condenser allows volatile substances to return to the reaction flask so that no material is lost. Since alkenes are immiscible with concentrated HBr, tetrabutylammonium bromide is used as a phase-transfer catalyst.

In direct titrations, the number of moles of acid can be easily derived by simply manipulating with the values of acid and base given in the experiment. In back titration, excessive volumes of acid are always added. Of which, only a certain quantity would be neutralised. The number of moles of acid is eventually derived from titrating this excess acid with a strong base and using mole fractions to calculate. The quantity of acid neutralised is obtained by subtracting the moles of acid given at the start of the experiment, with the moles of acid titrated.

Estimation of superoxide dismutase (SOD) activity 246 SOD activity was estimated by its ability to catalyse NBT to formazan at 560nm 247 according to the method of Beyer and Fridovich (40). Five ml of reaction mixture 248 containing 50 mm phosphate buffer (pH 7.8), 13 mm methionine, 75 mm NBT, 2 mm 249 riboflavin, 0.1 mm EDTA and the enzyme extract. Absorbance of sample was read at 560 250 nm. The difference of percentage reduction of colour development in blank and the 251 sample was calculated. Fifty percent reduction in the colour was taken as one unit of 252 enzyme activity and was expressed in enzyme units per milligram protein (U mg-1 253 protein).

As we know acid reacts with bubbles when combined with sodium bicarbonate. 2. Write the chemical equation for the reaction in well A6. B BoldI ItalicsU Underline Bulleted list Numbered list Superscript Subscript3 Words NaOh + AgNO3>>>>NaNO3 + AgOH 3. One of the reactions you observed resulted in this product: NaCl + H2O + CO2 (g)?

In this experiment, 293 mg of aldehyde was weighted for method 1 instead of 250 mg and. Although .7906 mg of phosphonium salt was added, this probably was not enough to complete the reaction. The only significant change throughout method was 1 was that the yellowish mixture became slightly lighter. However, it was found that after vacuum filtration, there was some white and yellow

The original reaction done by Kolbe involved the formation of sodium phenoxide through the evaporation of a molar equivalent mixture of phenol and aqueous sodium hydroxide. The hygroscopic sodium phenoxide is then heated while carbon dioxide gas is passed over the molten salt. The mixture is then further heated to give the dianion of salicylic acid along with carbon dioxide and phenol both of which distill away from the mixture. Under these

Note that iodide ions are regenerated in Equation 2, so they are available to react with the hydrogen peroxide in Equation 1. The thiosulfate, on the other hand, is consumed as it is turned into tetrathionate. The lag period ends when the thiosulfate is all used up. At this time, the triiodide is able to react with the starch. Equation 3: I3- + starch → (I3- starch complex) • I3- = Triiodide • I3- starch complex, which is blue This equation says that starch reacts with triiodide to form a blue

We measured how long it took for the high pH test tube to change color versus how long our control took. The Lugol’s Iodine test identifies for complex carbs. In our case, if the substance changed to a light brown color, the test was negative and the substance contained like glucose, and if the substance changed to a dark brown or black color, then the test was positive and the substance contained complex carbohydrates like starch. The substance with the high pH changed to a light brown at a time of 12 minutes and 49 seconds and the control changed to the same color at an earlier time of 11 minutes and 15

The pKa of this unknown weak acid is 4.0 and the Ka is 1.0 x 10-4 mol dm-3 while the molecular weight is 166.67 g mol-1. It is closely related to the ascorbic acid with a pKa of 4.10 and a Ka of 7.9 x 10-5 with a molecular weight of 176.12 g mol-1. Therefore it can be concluded that the unknown acid is ascorbic acid. Titration technique is best suited for this experiment because the end point and equivalence point can be distinguished by the physical changes which are the colour change of the mixture. We are also able to better control and determine the volume of NaOH in the burette needed to neutralise HCI, CH3COOH and the unknown acid.