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Course: Heat of Fusion of Water
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Heat of Fusion of Water
Abstract
The aim of this experiment was to determine the specific heat of fusion for the change of phase from ice to water. A method based on the principle of energy conservation was used in the experiment. Simply, the ice absorbs heat that is equal to that lost by the stirrer, calorimeter, and water. Initially, the ice undergoes a change of phase from solid to liquid (melting point). The experiment was conducted by maintaining all the pieces of ice in a funnel until when the pieces would be used to drain off all the water. In the data analysis and uncertainty estimates, graphs were plotted to determine the latent heat of fusion and other variables. Although the specific heat of fusion of ice was determined successfully, some errors occurred during the experiment. As a result, the final values differed slightly from the theoretical ones.
Introduction
The heat of fusion is the heat required to convert a unit mass of a solid into a liquid without changes in temperature. For water at 0 ºC (standard freezing point), the specific heat of fusion is a constant, i.e. 334 J g-1. In other words, water needs to absorb 334 J of heat for it to
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The heat equation applies only at the freezing/ melting transition. At this point, the temperature does not change. When a substance is heated at a temperature below its melting point, the temperature of the ice to rise continuously up to its melting point. Although heat is applied in the process, no rise in temperature is observed. As the ice continues to melt, the temperature of the water increases gradually. In this experiment, the principle of conservation of energy was used and the first equation was as follows: ∑∆Q = 0. Similarly, ∆Q = mLf. Therefore, ∆Qc + ∆Qw + ∆Q ice + ∆Qi →(l) + ∆Q m ice
After the water temperature began to stabilize, the highest constant temperature was recorded. This data was used to calculate the calorimeter constant. This enter procedure was repeated to calculate another calorimeter constant in order to find the average of both answers. After that value was calculated, a 600 mL beaker was filled with 300 mL of water and heated till it started boiling. An unknown metal located on the instructor's bench was obtained and the mass was calculated.
When atoms are cold they sink because they are more compacted and don’t move around as much. Sink or Float was a lab that showed about temperature and density changes. With the cold water we saw it sink and just stay at the bottom of the container without moving. When the hot water was added it made it rise to the top of the container and spread. That showed us that the bottom layers would be hotter and the top layers would be colder.
Use the following data to find the energy change in J of each system Specific heat of ice= 2.03 J/gC Specific heat of steam= 1.99 J/gC Specific heat of water= 4.18
A boiling point of a substance is dependent on the temperature at which the substance can change its matter, such as liquid to gas. The molecules present in liquid are tightly compressed together, though they are still moving and colliding. If the liquid is heated, there is a rise in temperature which generates vibrations throughout the liquid, resulting in more collisions between molecules (Helmenstine, 2017). Once the collisions between the molecules become quite intense and rapid, boiling starts to take place. There are molecules that are so powerful, they break through the attraction forces that keep the molecules together, this is called intermolecular forces (Ophardt, 2013).
Introduction The intent of this experiment is to understand how hot and cold water interact with each other by combining clear hot water and black ice cold water. I hope to learn more about how hot and cold water interact with each other. As of now, I know that cold water is denser than hot water. Knowing this I formed my hypothesis.
Purpose: The purpose of this experiment was to determine the molar mass of unknown #43 using the derived freezing point depression. To obtain the freezing point depression, t-butyl alcohol was placed in a cold-water bath and frozen solid for a total of two runs. Then, unknown #43 was dissolved in t-butyl alcohol and placed in a cold-water bath until frozen solid. This process was repeated for a total of three runs, with the first two runs containing half of the unknown, and the last run containing the full amount of unknown.
Yes, the melting point data does make sense. While the melting point range was close to the given temperature range, the data was still a little lower than expected. This may have been caused by impurities in the product, since impurities cause melting point range to decrease. The product was observed moving up the capillary tube during melting point analysis, which indicates that the product was not completely dry before melting point range was taken. The water in the product evaporated and caused the product to be pushed up.
Materials: The materials that I will be utilizing during these experimentations are three to four ice cubes, one cup for measuring, six unblemished cups, one stopwatch, one hot water source, three tablets of Alka-Seltzer, one thermometer that measures from negative
Our objective was to pick the best chemical to be used in a hand warm. This chemical had to be cheap, relatively safe, and must raise the temperature by 20oC and no more. We add 6 different chemicals to water we record the inshell temperature and then add one a the 6 chemicals to the water and record the temperature change of the water. We also add cold water hot water together to find how much heat would escape the calorimeter. We found that the calorimeter absorbed 71.1J/oC. Then this information to calculate the energy that was released by all of the chemical reaction.
Introduction: Melting is the change of a solid into a liquid when heat is applied. Melting will occur at a fixed temperature which known as melting point. Melting point is the temperature at which the solid and liquid forms of a pure substance can exist in equilibrium. The temperature will increase until the melting point is reached when heat is applied. Heat will convert the solid into a liquid with no temperature change.
Research question What is the effect of temperature Amylase activity? Word count-1453 Background research Enzymes are biological catalysts that speed up a chemical reactions. They do this by decreasing the activation energy(the energy needed to start the reaction) of a chemical reaction. The enzyme present in our saliva is called Amylase. Amylase increases the rate of reaction by decreasing the activation energy needed to hydrolyse the starch molecules.
Heat stress is a condition in which the increase in core body temperature overwhelms the body’s homeostatic thermoregulation abilities, thus producing and absorbing more heat than the body could dissipate [1]. This results in a wide spectrum of heat-related illnesses, ranging from minor conditions such as heat cramps and heat exhaustion to the more severe condition known as heat stroke. Heat stroke is defined as a core body temperature of beyond 40.60C, commonly associated with the dysfunction of the Central Nervous System (CNS) and the failure of multiple organ systems, which may ultimately result in disability or death. [2] Heat stress can be categorized into two different entities: classical and exertional. Classical or environmental heat
Purpose/Introduction The process of recrystallization is an important method of purifying a solid organic substance using a hot solution as a solvent. This method will allow the separation of impurities. We will analyze Benzoic Acid as it is dissolved and recrystallized in water and in a solvent of Methanol and water. Reaction/Summary
Another way to calculate the enthalpy of neutralization is to assume the density of the solution to be equal to the density of water in order to assume the mass of the solution. 1.00 g 〖cm〗^(-3)×50 cm^3±0.96 %= 50.00 g ±0.96 % The heat released can then be calculated using the assumed mass. q=50.00 g±0.96 % ×4.18 J g^(-1)
When a solid dissolves in a liquid, it then changes its physical state (from solid to liquid) by melting. Heat is needed to break the bonds holding the molecules in the solid together and at the same time; heat is given off during the formation of new bonds between solute and solvent. Results Table1. Results for titration of benzoic acid with NaOH at 20◦C V(NaOH) ml V(C_6