a. ffss b. FfSs c. ffSs d. Ffss 2. A blood sample taken from a patient who has an infection can be expected to show which of the following? a Elevated white blood cell count b Elevated red blood cell count c Reduce red blood cell count d Reduce White blood cell count 3. Which of the following organs remove nitrogenous waste from the body? a. Liver b.
Introduction: For my final lab, I was given the task of producing the coordination complex Tris(Oxalato)Ferrate(III) Trihydrate using the following equation: FeCl3+3K2C2O4H2OK3Fe(C2O4)33H2O(g) +3KCl(aq) As a result, 4.105g of green crystal complex was produced and analyzed based on percent composition. To complete this analysis, four other experiments using titration, visible spectroscopy, ion sensitive electrodes, and dehydration and were used to determine the composition of oxalate, iron, potassium and water in the produced complex. The following report records the the results of these experiments and discusses any finding or errors in the procedure. Experimental Data: When the individual components of the complex were analyzed, it was
The ABO system consists of four blood groups; A, B, AB and O. Individuals can be divided into these by the ABO blood group system; this is according to the different type of antigen that is present on the surfaces of their erythrocytes. (Ahmed, 2007) The antigens that determine ABO blood groups are oligosaccharide constituents of cell surface glycolipids and glycoprotein (Ahmed, 2007). The H antigen, which is located on chromosome 19, can be attached to type I or type II precursor chains. The H gene encodes an enzyme, L- fucosyl tranferase that adds L-fucose to the terminal galactose to form the H antigen (Ahmed, 2007).
LDL is formed from VLDL and some are released by the liver. LDL is a major transport form of cholesterol and cholesteryl esters in the circulation.. LDL has a specific cell surface receptors  as show in figure (1-10). The amount of LDL receptor is regulated by the cellular requirement for lipids, with the primary regulatory lipid being cholesterol . High level of LDL-C is connected with elevated risk of heart disease. LDL-C is the “bad cholesterol” of the common
• Mild or even moderate phenylketonuria : Phenylalanine tolerance can range from 250 to 400 mg per day. THE PHENYLALANINE HYDROXYLASE (PAH) ENZYME : The human phenylalanine enzyme is expressed in liver as well as in the kidney. This enzyme is involved in the conversion of phenylalanine to tyrosine. The phenylalanine hydroxylase enzyme has two forms among which tetrameric form is active and dimeric form is inactive. Additionally, there exists three domains of the enzyme namely C- terminal catalytic domain, an N- terminal regulatory domain and a tetramerization domain.
This organic molecule has a lot of critical roles in the human body. First off proteins come in four main structures and these structures are called primary, secondary, tertiary and quaternary. A primary protein structure is a linear arrangement of amino acids. Secondary structure has areas of folding or coiling and these are known as an alpha helices and pleated sheets. Tertiary structure has a three-dimensional structure, which is from non-covalent contact between the amino acids.
İn our case malignancies can metastate to spleen were excluded. 60% of splenic metastases have no clinical symptom. Most of them are found insidentaly at examinations. Fatigue, weight loss, fever, abdominal pain, splenomegaly, anemia and trombositopenia are rarely seen symptoms and signs. Most rare finding is splenic rupture(18-19).
A) Lipids B) Carbohydrates C) Proteins D) Nucleotides E) Polysaccharides Answer: A Diff: 4 Page Ref: 21 4 Copyright © 2011 Pearson Education, Inc. 15) ________ are molecules composed of a glycerol and three fatty acids. A) Phospholipids B) Saturated fatty acids C) Eicosanoids D) Steroids E) Triglycerides Answer: E Diff: 3 Page Ref: 21 16) A fatty acid that contains three double bonds in its carbon chain is said to be ________. A)
The causes of this disorder due to an autosomal recessive and a mutation in several genes involve the absence production of melanin. In some types of albinism, if each parent has one copy of defective gene there is a chance that each offspring will be an affected or a carrier. The signs and symptoms of Albinism are absence color (skin, hair, and eyes), lighter than a normal coloring (hair, skin and eyes), patches of skin that have an absence of pigment. The most common to diagnosed albinism by the used of genetic testing, it detects the defective gene that related in this disorder. Since the Albinism is no cure, treatment is for relieving the symptoms or preventing sun damage, they wear sunglasses with UV protection to protect their eyes from sun’s rays, protective clothing and sunscreen protection to protect skin from UV
VIII. Methods and materials : hemoglobin types determined by cellulose acetate and citrate agar electrophoresis methods based on different electrical charges when place the sample in electrophoresis, when electrical current is passed through the hemoglobin blood sample, causes separation of hemoglobin type at different rates and form bands . (14)(15) materials 1. Tris-EDTA Boric Acid buffer (TEB), pH 8.4. Tris hydroxymethyl amino methane (TRIS): 10.2 g Ethylene diamine tetracetic acid (EDTA): 0.6 g Boric Acid: 3.2 g 1 litre with distilled water 2.
The Diverse Parts of Macromolecules in Science There are four sorts of macromolecules that I am going to portray: Proteins, starches, lipids and nucleic corrosive. I will likewise depict the capacities and why they are critical in our bodies. Proteins Proteins are polymers of amino acids that are joined head-to-tail in a long chain that is then collapsed into a three-dimensional structure one of a kind to every sort of protein. The covalent linkage between two contiguous amino acids in a protein (or polypeptide) chain is known as a peptide bond. There are twenty amino acids that make up proteins.
This gene is located on the X chromosome, which is one of the two sex chromosomes. In males (who have only one X chromosome), one altered copy of the COL4A5 gene in each cell is sufficient to cause kidney failure and other severe symptoms of the disorder. In females (who have two X chromosomes), a mutation in one copy of the COL4A5 gene usually only results in hematuria, but some women experience more severe symptoms. A characteristic of X-linked inheritance is that fathers cannot pass X-linked traits to their sons. In approximately 15 percent of cases, Alport syndrome results from mutations in both copies of the COL4A3 or COL4A4 gene and is inherited in an autosomal recessive pattern.
Starch amylase testing was equally unsubstantial since the only amylase producing bacteria was ruled out after Gram staining. Unknown #10’s negative citrate test result was also unhelpful because E. coli is citrate negative and P. vulgaris is a variable citrate producer that can also be citrate negative. H2S production in the Kligler’s Iron Agar test ultimately proved that Unknown #10 was Proteus vulgaris. P. vulgaris is the only assigned bacteria that produces H2S, so when a black precipitate obscured the yellow butt of the Kligler’s Iron Agar slant, E. coli was ruled out. Not only did the H2S product confirmed that Unknown #10 was P. vulgaris, it confirmed P. vulgaris’ motility.
In part C. pairs of compounds were investigated to determine whether the compounds were miscible or immiscible. Diethyl ether and methylene chloride, diethyl ether and ethyl alcohol, water and ethyl alcohol, heptane and methyl chloride, and heptane and diethyl ether were all were found to be miscible each of these paired compounds showed a homogenous mixture with no chunks or particles left over when combined. On the other hand, water and heptane, water and methylene chloride, and water and diethyl ether were all immiscible, when mixed together it was observed that the compounds had two layers rather than one homogenous
(About Cystic Fibrosis) Cystic Fibrosis is caused by a mutated gene that changes the protein that controls the salt in and out of the cell. There are many different mutation which can change the severity of the disease in each case. For this to be passed on a child must receive one copy of the gene from each parent to develop this disease. If a child receives a copy from only one parent then