Post Lab Questions for Immunofluorescence
1.) In our experiment the primary antibody that was used was anti-tubulin, which was generated in the rabbit anti-mouse tubulin antibody. It is specific for the tubulin proteins to help identify their binding sites.
2.) The secondary antibody that was used was anti-actin, which was stained with FITC. It was generated in the goat anti-rabbit IgG. It is specific for the actin proteins. Adding a flurofore, which helps identify certain targets, better modified the secondary antibody.
3.) We used primary and secondary because they can be used simultaneously to identify different antibodies by switching light wavelengths. Whereas if only a primary fluorescent antibody were to be used some of the structures would not be seen. Only the first binding site of the antibodies would be visible, thus the other half of the bounded structure would be invisible.
4.)
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The structure of the cell was very visible when using the anti-tubulin. When observing the anti-actin the microfilaments were visible. The actin filaments were much thinner than those of the microtubules. The actin filaments were best observed in the periphery of the cell compared to those of the tubulin, which are spread throughout the cell because they help stabilize the cell. The TRITC dyed cells depict better the whole structure of the cell, the nucleus is more visible than those that are dyed with FITC.
5.) On the controlled slide both microfilaments and microtubules are visible because it is treated with both anti-tubulin as well as anti-actin. The control is necessary because when observing just one of the antibodies you can go back and compare it and see if the structure correlate with what you
Endomysium is found within a muscle and it contains nerves and capillaries. It is a fine layer of connective tissue that extracts each individual myocyte. P5 – Describe the sliding filament theory, giving a step by step process.
The sample was then incubated at 56°C to lyse the tissue. The sample was checked every fifteen minutes and vortexed between each checking for an hour and a half until the tissue was completely lysed. The tissue sample was then again vortexed. Next 200 microliters of buffer AL was added and
Staphylococcus epidermidis is the organism that was identified based on the tests that I had conducted. The tests that I used to identify this organism were the coagulase test and the catalase test. My bacterium was beta hemolytic as well. First, a gram stain had to be done to determine whether the organism was a gram positive organism or a gram negative organism. This determined which set of tests that had to be done.
The flies in vial 1A will demonstrate AO activity while the flies in vial 1B will show no AO activity. So if the flies from vial 1A turn blue after the assay test, then they have the enzyme for AO activity. If the flies from vial 1B present no color change, then they do not have the enzyme for AO activity. In the second part of the lab, the pattern of inheritance of the aldox gene will be determined, whether it is autosomal or sex-linked. The pattern of inheritance will be autosomal and the genotype of the parents will
However, differential quantity in protein carbonylation between controls and treated groups is still to be investigated. Other lab techniques include sterile technique, MTT toxicity testing, ELISA (indirect), maintenance of tissue culture, western blot, protein extraction, column chromatography, and mass
Testing for the Presence of Macromolecules in McDonald’s Happy Meals Clayton Wagoner MST Biology White 4 duPont Manual High School Introduction Carbohydrates, lipids, proteins, and nucleic acids are organic molecules found in every living organism. These macromolecules are large carbon based structures. The macromolecules are assembled by joining several smaller units, called monomers, together through a chemical reaction called dehydration synthesis. The resulting polymer can be disassembled through the complementary process called hydrolysis.
DIY - What Is Life? How can you determine whether something is alive, dead, or non-living? Whenever we speak of life, we must think in terms of cells.
The addition signs for each test on serum 2216 illiterates how concentrated the molecule is like purple for example was the most concentrated due to the amount of addition signs in the table. For Macromolecule test 1 and 2 the sample was diluted. Both the concentration and decreased by an equal set of intervals. The volume of distilled water is what was added and the results illustrate how deeply colored each concentration was. Each cup was diluted with the test pertaining to it with a syringe that explain the volume and the concentration is from heating or mixing the sample throughout the investigation.
Specimen Preparation Specimen is stained with materials such as lead, osmium and uranium salts. The salts are then absorbed by the organelles and cell membrane, but not the cytoplasm. This means that the electrons cannot pass through the salt. Allowing there to be dark and light areas in the image created. This is done to prevent the image from being distorted through collision between electrons and air particles.
The streaking technique used was a modified streaking for isolation with a heavy quadrant one. The result revealed that bacteria is alpha, with an incomplete breakdown of the medium with a susceptibility of 17mm from the bacitracin gamma hemolysis. That is why the organism represented by the bar graph was in low numbers because it was incomplete. The other test was DNase agar, it is an enzyme test used to identify if the organism has the enzyme DNA. The streaking technique is a single straight line down the middle of the plate.
The chromatids contain an identical DNA molecule where the protein complex of cohesins attaches it all along its length. Cohesins are also responsible for maintaining the overall chromatid together. Choice C is incorrect. The assembly of the mitotic spindle consist of microtubules that were dissociated from the cytoskeleton. However, the microtubules are not held together by cohesin proteins but rather the protein, tubulin.
This root tip was choosen because of its rapid growth and it can be easily avaliable and grown in large numbers. The rapid root growth proved advantageous as it allowed the observation of multiple cells in each mitotic stage within a small sample. It was expected that the majority of the cells found would be in interphase as a large proportion of the cell division cycle is spent with the cell performing its normal cellular functions. Materials: The Materials required for this experiment include; a
Finally, the amplified DNA regions are compare using a gel. DNA Profiling
*During breeding season, each testis becomes enlarged in size. *Each testis is made up of a large number of coiled tubules called seminiferous tubules. * In between tubules, cluster of small cells are found called Leydig cells (Interstial cells).
They separate the chromosome pairs during mitosis. The microtubules are protein cylinders that aid movement of organelles. The actin filaments are protein fibers that play a role in cell division and