Introduction How do you find the concentration of an unknown acid? The law of conservation of mass will be observed in this lab because in a balanced or neutralized equation the number of moles of the acid is equal to the number of moles of the base. An equation that will be observed is that when an acid and a base are combined in a reaction they will produce salt and water. In order to properly conduct this lab procedure many different properties of acids and bases need to be understood. Acids have a pH lower than seven, turn litmus paper red, and when mixed with phenolphthalein remain colorless. However, when a base is mixed with phenolphthalein it turns a vibrant pink shade. Also bases have pH greater than seven and turn litmus paper blue. Bases do not react with metals, feel slippery like soap, and have a bitter taste, whereas acids do react with metal, have a sour taste, and feel smooth like water. If a titration is used to neutralize an acid or base the the molarity of the unknown can be found. In this lab the independent variable would be the volume (moles) of the titrant used and the dependent variable will be the molarity of concentration of the unknown acid. If done correctly this procedure should lead to a valid conclusion since the moles of the titrant used will equal the moles of the unknown acid that was neutralized. Once the moles and the volume of the titrant used are found then …show more content…
This would make the moles of the titrant used increase and in turn would make the calculation of the unknown concentration have an decrease in molarity.
Question3: Experiment 3 The unknown acid sample was 1 • Monoprotic Acid Trails Initial NaOH solution (mL) final NaOH solution (mL) The volume of NaOH to titrate the acid (mL) Amount of Unknown Acid sample 1 (g) The moles of the Unknown Acid (mol) Molar mass of the Unknown Acid (g/mol) A 3.38 28.31 24.93 0.150 0.0026 57.69 B 0.18 29.32 29.14 0.175 0.0029
In the first part of the experiment, Part A, the standard solutions were prepared. As a whole, the experiment was conducted by four people, however, for Part A, the group was split in two to prepare the two different solutions. Calibrations curves were created for the standard solutions of both Red 40 and Blue 1. Each solution was treated with a serial 2-fold dilution to gain different concentrations of each solution.
The anion tests followed the cation tests. To test for the presence of the chloride (Cl-) anion, a small scoop of the unknown compound was mixed with 1 mL of water in a test tube to create a solution. Then, 1 mL of 6 M nitric acid (HNO3) and 1 mL of silver nitrate (Ag(NO3)2) solution were added to the test tube to see if a white precipitate formed. To test for the presence of the sulfate (SO42-) anion, a small scoop of the unknown compound was mixed with 1 mL of water in a test tube to create a solution. Then, 1 mL of 6 M hydrochloric acid (HCl) and 1 mL of barium chloride (BaCl2) solution were added to the test tube to see if a white precipitate formed.
Eventually using the NaOH and the acid’s consumed moles, the equivalent mass will be determined. Procedure: Part 2: Obtain 45mL of NaOH, and then weigh 0.3-0.4g of the unknown acid (KH2PO4). Dissolve the acid into 20.00mL water.
Lab Report -- Relationship on Enzyme activity and substrate concentration Research Question: Is the more concentrated the substrate of hydrogen peroxide is, the shorter the time taken for the paper disc to rise from the bottom of the beaker? Aim: The opposite of hull hypothesis Background Information: This experiment aimed to investigate on the relationship of the substrate concentration and enzyme activity. Enzymes are proteins produced by a cell that acts as catalysts to increase the rate of a specific chemical reaction without changing the reaction itself.
Hypothesis: Increasing substrate concentration will increase the initial reaction rate until it stops increasing and flattens out. Independent Variable: Substrate concentration Dependent Variable: The substrate itself, 1.0% Hydrogen Peroxide How Dependent Variable will be Measured: Hydrogen Peroxide will be used in every experiment, just with different test tubes. The amount of Hydrogen Peroxide in the mixing table is the amount that will be added to each test tube.
A pH 7 is neutral, which means that it is neither an acid nor a base. A pH of 8 to 14 means that the substance is a base. The lower the pH level, the stronger the acid, and the higher the pH level, the stronger the base.
Once these two steps were done, the actual titration occurred where it started with 0.25 mL of the first 3 mL, then proceeded to 1 mL of increments until the next 20 mL, and then essentially to one drop increments in order to obtain the equivalence point. The titration was done for both the HCl solution and the unknown
The experiment was to indicate if the substances are acidic, base or neutral and was tested during the lab to obtain a final answer. The procedure we followed were simple: we gathered the materials and cleaned them out and then shortly after we tested the fluids with 2 Litmus paper of each color. As we finished the procedures we got result almost immediately with four out of the six being neutral and only two being acidic. The results supported part of our hypothesis as the last two were incorrect. The last two were guessed as being base and acidic but was neutral which was astonishing because rubbing alcohol showcased characteristics of being acidic which led us to believe it was, but was not supported with the data.
Ali Atwi : Internal assesment – calculating of the concentration of ethanoic acid in vinegar AIM : To calculate the concentration of ethanoic acid CH3COOH in vinegar using stoichiometric equations, ( Yamaha brand ) Introduction : I personally like to add a little bit of vinegar on my food because it makes it taste better, yet I know that vinegar contains acid, and I also know the consequences of highly concentrated acid intake, like severe itching and stomach ache, vomiting. Venigar contains a small percentage of ethanoic acid Ch3COOH. This practical aims to find out the concentration of the of the vinegar against a standard solution of sodium hydroxide soloution of concentration 0.1 mol dm3 through acid-base titration, the label on the bottle says 6%.
Procedure A. Preparation of NaOH solution The molarity of a solution is the ratio of the number of solutes dissolved in a liter of solution. To figure out the needed mass (in grams) of NaOH pellets to be dissolved in a 0.25 L of water, remember that a mole is equivalent to the quotient of mass over the molar mass of the substance. This was used to rearrange the base formula and to derive the mathematical equation of mass in terms of molarity. mass (g) =
A titration is the precise addition of a solution from a buret into an accurately measured volume of a sample solution. A titrant is the solution in the buret that is used for the titration, and the volume of the solution is known. The titrants used in this lab were 0.1M hydrochloric acid and 0.1M sodium hydroxide (the reactions can be seen in figure 4). A Bronsted-Lowry acid is a compound that donates a proton. A Bronsted-Lowry base is a compound that accepts a proton.
The chemical equation for this experiment is hydrochloric acid + sodium thiosulphate + deionised water (ranging from 25ml to 0ml in 5ml intervals) sodium chloride + deionised water (ranging from 25ml to 0ml in 5ml intervals) + sulphur dioxide + sulphur. As a scientific equation, this would be written out as, NA2S2O3 + 2HCL + H2O (ranging from 25ml to 0ml in
That caused a new initial reading of NaOH on the burette (see Table1 & 2). The drops were caused because the burette was not tightened enough at the bottom to avoid it from being hard to release the basic solution for titrating the acid. The volume of the acid used for each titration was 25ml. The volume of the solution was then calculated by subtracting the initial volume from the final volume. We then calculated the average volume at each temperature.
mass RFM 0.0250 = mass 40 0.0250 x 40 + 1g (mass) Explain how this enabled you to accurately calculate the molarity of each acid used in the titrations (equations explained)- Molarity of the acid = molarity of the alkali x volume of the alkali volume of acid Firstly we will need to add up all of the volumes found within the titration to find an average: 13.10+13.20+13.10= 13.13 Molarity of Ethanoic acid = 0.1 x 25.00 = 0.190 mol dm-3 13.13 Molarity of Hydrochloric acid = 1.0 x 25.00 = 0.077 mol dm-3 32.53