# Line slope calculator 2x-5y=-11

**Straight line given by points A[2; 3] and B[7; 5]**

## Calculation:

**Slope-intercept form of line:**y = 0.4x+2.2

**Canonical form of the line equation:**2x-5y+11 = 0

**Parametric form of the line equation:**

x = 5t+2

y = 2t+3 ; t ∈ R

**Slope:**m = 0.4

**Slope angle of line: φ =**21°48'5″ = 0.3805 rad

**X intercept:**x

_{0}= -5.5

**Y intercept:**y

_{0}= q = 2.2

**Distance line from the origin:**d

_{0}= 2.0426

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(5; 2)

**Normal vector: n =**(2; -5)

**Midpoint of the segment AB: M =**[4.5; 4]

**Perpendicular Bisector equation:**5x+2y-30.5 = 0

**Vector OA = (2; 3) ; |OA| = 3.6056**

**Vector OB = (7; 5) ; |OB| = 8.6023**

**Scalar product OA .OB = 29**

**Angle ∠ AOB = 20°46'20″ = 0.3625 rad**