Our lab results on all three data table experiments had a percent error less than 5 percent. When examining these results I can be almost certain it was not systematic error due to the fact that a major percent error was not detected on every trial that was run in each of the three tables. With there being some percent error there is the possibility for random error which are from unknown factors, which could come from impact of outside forces like the air track interfering with the acceleration of the cart. Beings that this was the first lab for my lab partners and I were working there was room for slight personal errors with our use of the computer program as well as the lab equipment. How does the acceleration in Data Table 2 compare with that of Data Table 1?
I think the data that I received from this experiment were relevant as the results were unexpected and contradicted my hypothesis giving me a different result to my research question. Next time for more reliability and validity in my experiment, I can find a way to make sure that as soon as the mass starts sliding the height is measured automatically. This can require an extra hand to help in the
A question that arose after this experiment was conducted is, how would the results differ if the force applied when swinging the object was kept the exact same? The experiment could be furthered by increasing the number of trials for more accurate results. Every experiment has errors that affect the accuracy of the results. In the experiment conducted, the three things that could be improved are the force with which all three objects were swung, the radius of the string (for all three objects) and pressing the stop watch without any delays or advances. To finally conclude, the trend observed as part of this experiment was that as the mass increases, the tangential velocity decreases and this also proves the hypothesis correct.
The change in an object’s momentum is equal to A) the product of the mass of the object and the time interval. B) the product of the force applied to the object and the time interval. C) the time interval divided by the net external force. D) the net external force divided by the time interval. ____ 9.
It does not however because the tracks act as a force and change the coaster's direction. Newton’s Second Law of Motion states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object. This relates to the roller coaster that we made in class because it is an unbalanced force. It is able to change the roller coaster's motion and pull it uphill. When
Since the force is always perpendicular to the electrons direction of motion, it makes it move in a circular path whose plane is perpendicular to the direction of the magnetic field. The force required to keep a body moving in a circle is F=m v^2/r (5) With radius r and mass m. The required centripetal force is provided by the force exerted on the electron by the negative field m v^2/r=Bev or m v/r=eB
By whatever amount the net force acting on the cart changes, I believe its acceleration will change proportionally. Because the relationship is linear, the results on the graph will be linear. This can be shown mathematically as: a ∝ F, or in words “a is proportional to F”. Therefore, a=kF, which can be rearranged to get F=(1/k)a. We know that F=ma where the mass is the cart plus the weights with friction considered, and we know that weight=mass x gravitational field strength.
The final velocity, and average velocity are the same. So, v=2m /0.632 s.--- v=3.165. The final momentum, however, is 965.625 kg m/s. By applying the equation, p = mv, Th, p=0.1349 kg x 3.165 m/s exhibits how this was calculated. The acceleration of the container is 5.008 m/s 2.
The process reaches an endpoint when the two solutions completely and exactly neutralized each other. However, in determining the neutralization time by speculating the change in color, one must be critical and careful enough to get accurate and precise data. In conducting this experiment, some possible errors affect the accuracy of the data. The first possible source of error encountered is in the miscalculation in preparing the titrant. Excess or lesser amounts of 1.00 M NaOH can lead to inappropriate standardization.
The second figure shows the cross track error plot and comparison of vehicle orientation error and commanded steering input to reduce the orientation error. Fig 5 shows the tracking of a circular path . Linear kinematic model is used to estimate the vehicle location. The vehicle moves at a velocity of 5 m/s. The second figure shows the cross track error plot and comparison of vehicle orientation error and commanded steering input to reduce the orientation error.