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Molar Mass Lab Report

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Introduction A way to determine the molar mass of an unknown substance is to use other properties of that substance and solve for desired information. In this experiment, a colligative property, like the freezing point of an aqueous solution of the unknown substance, was used to find the molar mass of the substance. With the molar mass discovered, the identity of the substance was found. Material and Methods First, a Vernier temperature probe was attached to a plastic rod using rubber bands. A cork was then put in place around the plastic rod with the cork being clamped onto a ring stand. After, a wire was shaped into a handle with a loop at the end of it. The mass recorded of the 11-dram vial was 24.1847 grams. A graduated cylinder was used …show more content…

The experimental molar mass was calculated to be 87.5005 grams. Some source of error could be that there was not enough time to let the solution warm up to room temperature, letting the solid formed in the 11 dram dial to melt, causing the temperature probe to possibly read incorrectly. Also, while using a plastic pipet, the drops added were not consistent and varied in size. This could have led to different masses between the first and second set of 20 glycerol drops used in trial 2 and 3 of the experiment. These mistakes and errors can account for the percent error of 4.98%. This was done by taking the absolute value of the difference between the experimental value and the actual value, dividing by the actual value and multiplying by a 100. ((87.5005-92.09382)/92.09382) …show more content…

The equation is y=-.0493x+7.0838. The slope, -.0493 is around half as steep as trial one. This is because the solution is decreasing in temperature and the particles of the unknown are requiring the temperature to be colder so that the solution can freeze. For the freezing series the equation is y=.0006x-.5133. The slope is also close to 0 because the points are leveled out and generally conveying the temperature of the freezing point. These two lines of all three trials were used to find the freezing temperature that led to ultimately calculating the molar mass of the

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