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Molarity Murder Investigation Essay

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Adrian Menchaca Mr. Martin Chemistry 9 May 2023 Molarity Murder Investigation Abstract: Miss Scarlet was poisoned with silver nitrate, according to the investigation into the murder case. Data analysis revealed that Mr. Green had a specific reason for killing her. Further research revealed that Miss Scarlet had been poisoned by Mr. Green using a silver nitrate solution. It was found that Mr. Green’s silver nitrate solution had a molarity of 0.564 M using the balanced chemical equation. The conclusion that Mr. Green committed the murder and used silver nitrate as a murder weapon is supported by this evidence. This case is a reminder of the significance of chemical tests in criminal investigations and the need of carefully considering all available evidence when trying to figure out crimes. Hypothesis: Silver nitrate or potassium iodide could have been present in …show more content…

Green with a silver nitrate (AgNO3) solution. Assuming that certain amounts of AgNO3 was dissolved in a particular amount of water to produce the solution. Find out how many moles of Na2CO3 were involved in the silver nitrate reaction first. To my knowledge of Mr. Green’s addition of 1.5 grams of Na2CO3 to the silver nitrate solution comes from the statement. Since Na2CO3 has a molar mass of 105.99 g/mol, the amount of Na2CO3 is: moles of Na2CO3 = mass / molar mass moles of Na2CO3 = 1.5 g / 105.99 g/mol moles of Na2CO3 = 0.0141 mol Now, I used the balanced chemical equation to find the number of moles of AgNO3 that reacted with Na2CO3. From the chemical equation, I saw that 2 moles of AgNO3 react with 1 mole of Na2CO3. (2 AgNO3 + 1 Na2CO3 -> 1 Ag2CO3 + 2 NaNO3). moles of AgNO3 = (moles of Na2CO3) / 0.5 moles of AgNO3 = 0.0141 mol / 0.5 moles of AgNO3 = 0.00282 mol Finally, I found the molarity of the silver nitrate solution. We know from the statement that the volume of the silver nitrate solution was 50 mL

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