Combustion Reaction Equations For: Cellulose

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Homework: Question - Answer (55) The combustion reaction equations for:
Cellulose: C6H10O5 + x(O2+3.76N2)  y (CO2) + z (H2O) + k(N2)
Solution:
25C_6 H_10 O_5 + 150O_2 + 558N_2 ==> 150CO_2 + 125H_2 O + 558N_2…[1.1]
Nitrocellulose: C6H10O5(NO2)3+ x(O2+3.76N2)  y (CO2) + z (H2O) + k(N2)
C_6 H_10 O_5 (NO_2 )_3+ 〖3O〗_2+ 7.52N_2  6CO_2 + 5H_2 O + 10.52N_2…[1.2] (5) Amount of less air needed to completely combust the nitrocellulose compared with the cellulose in terms of moles
A stoichiometric balance of the combustion reactions is as shown in the equations in [1.1] and [1.2] above. Equation [1.1] shows that cellulose requires about 150 moles of oxygen and 558 moles of nitrogen.

wide, how tall is the fire? Figure 1: Pallet
In order to determine the height of the fire, it is imperative to revisit the NFPA rules that govern the storage of pallets (protection against fire). In this case, it is assumed that the pallets were actually arranged and met the NFPA regulations. The NFPA 13_12.12.3 provides guidelines for Idle Pallets Stored on Racks, on Shelves and Above Doors (“NFPA 13 Standard for The Installation of Sprinkler Systems”).
Assume the pallet used to carry the stacks is wood, then most wooden pallets would be ≈ 10.1cm high. NFPA requires that each stack should be separated from another stack by either 8 ft. clear space of 25ft. of the permitted material. Thus, thus the space between stacks would be 243.84 cm, each of the stacks cannot exceed 4ft. high according to NFPA rules. However, visual inspection, suggests that the stack is square-shaped. The height of a stack is ≈ 3 ft. (“NFPA 13 Standard for the Installation of Sprinkler Systems”).
Overall, (243.84*2) cm + (10.1*3) cm + (91.44*3) cm + height of fire above the top stack (approx. 91.44+10.1) cm.
= 893.76 cm. Thus, the height of the