Nt1310 Unit 1 Lab Report
(a) 3Mbps / 150Kbpa =3 X 1024 / 150 =3072 / 150 =20.48 20 Users can be supported 150Kbps dedicated. (b) (i) Each user transmits only 10% of the time, means a user is idle in 90% of the time, transmits in 10% of the time. \therefore The Probability P=10% (ii) Using Binomial Distribution, P(X=n)=\binom{120}{n}p^{n}\left (1-P)^{120-n} Where P is the Probability of one user is transmitting. (iii) We need to calculate P(X\geq n), Which can be calculated by its complement P(X\leq n). For P(X\leq n), since n is big enough, we can use Central Limit Theorem to calculate out the approximation value of P(X\leq n); where n is 21. \therefore P= (1-P)\left ( \sum_{i=1}^{120}Xi\leq 20 \right ) Xi be independent random variable such that P(Xi=1)=P
Nt1310 Unit 5 Lab Report
409 Words | 2 Pages4.1.6 Flip ops as Counters As can be seen from Figure 4.7 and Figure 4.8, a T-FF can be implemented using a D- FF feeding back the negate output /Q to the input D. The input clock to be divided is then provided at the CLK input. Cascading n T-FF stages as shown in Figure 4.8, it is 26 possible to divide the input frequency by a factor of 2^n . Based on current requirement Figure 4.7: FlipFlop of IC, size and availability and operating temperature, the rst combination which is the cascade of divide-by-4, divide-by-10 and divide-by-10 is chosen. The ip op as divide by 4, 10, 40 etc have been simulated with ADS.
Nt1310 Unit 4 Lab Report
1764 Words | 8 PagesAnderson and Wood (1925) determined a magnification value equal to 2800 but they neglected the deformation of the tungsten wire under different equilibrium situations. Conversely, the deformation of the wire could be sufficient to reduce the magnification factor of 30%, increasing the moment of inertia. For this reason Uhrhammer and Collins (1990) and Uhrhammer et al. (1996) recomputed the instrument static magnification (GS) that was estimated equal to 2080 ± 60. Using 2800 instead of 2080 in the BB WA simulations leads to a magnitude error of +0.129 (e.g. Uhrhammer et al., 2011).
Nt1310 Unit 2 Lab Report
638 Words | 3 PagesFor most sequences at position 4 and 5 we observe only the nucleotides G and T, respectively. There may be rare cases where other nucleotides may also be found. To consider such observations, we need to do a process called additive smoothing or Laplace smoothing to smooth the categorical data. [9] In this case, we add 4 sequences: AAAAAAAAA, CCCCCCCCC, GGGGGGGG, TTTTTTTTT.
Nt1330 Unit 1 Case Analysis
1295 Words | 6 PagesBU275 Assignment 2 Equations Question 1 A Station 1: Prep Inter-arrival time is the time between consecutive arrivals of the customers. Because the inter-arrival times are exponentially distributed, customers arrive at random times. The mean is 100 customers/ hours. This indicates that a customer arrives every 0.6 minutes.
Nt1310 Unit 3 Lab Report
512 Words | 3 Pagesdetermine each pixel belongs to background or foreground. Wis the weights between the pattern and summationneurons, which are used to point out with which a pattern belongs to the background or foreground. They areupdated when each new value of a pixel at a certain position received by implementing the following function:Wt+1ib =fc(1−βNpn)Wib+MAtβ!(37)Wt+1i f=(1−Wt+1ib)(38)whereWtibis the weight between theith pattern neuron and the background summation neuron at timet,βisthe learning rate,Npnis the number of the pattern neurons of BNN,fcis the following function:fc(x)1,x>1x,x≤1(39)MAtindicates the neuron with the maximum response (activation potential) at frame t, according to:MAt1,f or neuron with maximum response0,otherwise(40)Function
Pt1420 Unit 6 Lab Report
155 Words | 1 PagesSuppose you need to find the fractional European call and the fractional European put options. Let the Hurst parameter be $H=0.85$, the $\sigma=0,25$, $r=0.10$, $S_{fbm} = 100$, $K = 95$, we have \begin{eqnarray*} d_1^{fBm} & = & \frac{\ln{\frac{S}{K}} + \frac{1}{2}(r( T - t) + \frac{(1)\sigma^2{( T^{2H} - t^{2H})}}{2})}{\sigma{\sqrt{T^{2H} - t^{2H}}}}\\ & = & \frac{\ln(\frac{105}{100}) + (0.10(0.25 -0) + \frac{(1){0.25^2}{0.25^{2(0.85)} - (1)0.25^{2(0.85)}}}{2}}{(0.25){\sqrt{0.25^{2(0.85)} - 0}})} \end{eqnarray*} we obtain $d^{fBm}_1= 1.0558$. We find in the normal distribution that $N(1.0558)= 0.8544$ and $N(-1.0558) = 0.1456.$
Nt1310 Unit 3 Data Analysis
554 Words | 3 Pages4. Strong collision: given a message M1, it is not possible to find two distinct messages such that h (M1’) = h (M1). The probability of this collision is 2n/2.
Nt1330 Unit 1 Test Paper
513 Words | 3 Pages\section{Building Blocks} \subsection{Access Structures} \textbf{Definition 3.8.}(Access Structure\citeup{beimel1996secure}) \emph{Let $\{P_1, P_2,...,P_n\}$ be a set of parties. A collection $\mathbb{A}\subseteq 2^{\{P_1,P_2,...,P_n\}}$ is monotone if $B\in\mathbb{A}$ and $B\subseteq C$ implies $C\in\mathbb{A}$. An access structure is a monotone collection $\mathbb{A}$ of non-empty subsets of $\{P_1,P_2,...,P_n\}$, i.e., $\mathbb{A}\subseteq 2^{\{P_1,P_2,...,P_n\}} \setminus\{\emptyset\}$. The sets in $\mathbb{A}$ are called the authorized sets, and the sets not in $\mathbb{A}$ are called the unauthorized sets}. In our settings, attributes will play the role of the parties such that the access structure $\mathbb{A}$ will contain the authorized
Nt1420 Unit 5 Lab 4 Study Guide
778 Words | 4 Pages(1/2 points) Answer:- This happen because I’m logged on as Administrator in system and as administrator on this system I am allowed full permissions. Question 4 For the purposes of this lab, you assign permissions directly to the Student user account. How does this differ from standard enterprise networking practice?
Nt1330 Unit 3 Paper
513 Words | 3 PagesIf BHE chooses, policyIQ log-ins can be integrated into the internal user directory (such as Active Directory) utilizing LDAPS integration. This requires just a few pieces of information to be exchanged by the BHE IT department and the policyIQ technical team. With this integrated, a user can log into policyIQ using his/her network log-in ID and password, and policyIQ will validate that log-in information to the BHE network. This can be set up for multiple network domains, if users do not exist within a single domain.
Nt1330 Unit 1 Paper
501 Words | 3 PagesThe difference between the two and three-tier client/server configuration, are the tiers (layers) that make up the systems. In a two-tier system you have a client and a server, each has the capability of doing the processing for the application (Brown, DeHayes, Hoffer, Martin, & Perkins, 2012). The software is loaded on the client computer, and access the data server directly. In a three-tier system, there is an additional server/computer between the client and data server; this third component contains the business logic or processing for the application (Brown, DeHayes, Hoffer, Martin, & Perkins, 2012; Luke, n.d.). A three-tier configuration could be a web-enabled business application.
Nt1310 Unit 3 Major Study
942 Words | 4 Pages1 What type of documentation did you see and inspire you? To my perspective, all those projects have been a trip toward the unconscious mind of the child and has released his/her deep emotional and visual experience. Also, the project has been a bridge between the self-unconscious (intangible) and language of self-expression (touchable) as “Artifacts”. To me as an educator with major study field in graphic and Fabric design, the outcome of the documentation has been a pure art which was occurred based on the unconscious of the child and affected his/her behavior and emotions. For the art, the timing of skill and the skill itself must be primarily unconscious responses.
MG 620 Management Answers
1051 Words | 5 PagesMG 620 Research and statistics for Managers July 30, 2014 Final Exam Instructions: Answer all questions Part II : Problem 1. In a sample of size of 10, the sum of all values is 400. What is the sample mean a. 20 c. 800 b. 560 d. None of the above SHOW YOUR WORK!
Nt1330 Unit 2.7 Observation Paper
500 Words | 2 Pages2.7 Observations from GMPCS Model Based on the above model, several observations can be made as follows. Observation_1: According to an interoperability feature between CSPs, a storage service will be hosted over a pool of resources that are in different geographical locations. Furthermore, different technologies, protocols, and security strategies are applied by each CSP within its datacentres to facilitate managing an environment to protect both resources and data. The technologies and strategies, therefore, might be disparate in terms of efficiency, and the type of storage network or storage system might be varied as well.
802.11b Pros-Fast Wireless Networking
614 Words | 3 PagesThe first item to change would moving from 802.11b to the new standard 802.11ac. As a result of going to this new standard of 802.11ac offer higher rates of data transfer up to 1.3Gbps per radio transmitter. Furthermore, the new standard 802.11ac has a higher encoding density, increased number of spatial streams, and multi-user MIMO. Bearing in mind that the wireless network is used by students, staff, and facility, it would be in the best interest of the school to create separate VLAN’s and access lists within the network.
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