1580 Words7 Pages

4. Description of the function files in the software package giant_test

4.1. calltest.m:

The program calltest.m is the main file that runs the simulations.

This program allows users to input parameters via two GUIs.

The input parameter N_val is a vector. The elements of N_val are the values for sizes of the networks. The program has set the maximum network size to 13,000. If user inputs number greater than 13,000 for the network size, then program displays following error messages in the command window:

`Extremely large network size. '

`Use numbers less than 13000 for network size '.

The minimum and the maximum values of the proportion of nodes of type 1 are given by input parameters q1min and q1max respectively. The program*…show more content…*

To compute rho, the program GSC threshold.m denes two non-linear functions root2d and root2r as in Equation (15) and (16) of [1]. Each of these functions represents a system of non-linear equations in two variables. The program numerically solves these two by two systems of non-linear equations by using the inbuilt MatLab function f-solve. Since the probabilities, PNi are numerical solution computed by MatLab these values can be very very small numbers. To avoid these artifacts, the program replaces values of rho less than l_t by*…show more content…*

For each distinct pair of the scaled mean vector c and the network size N, the program produces an adjacency matrix of a loop-free digraph (with all diagonal entries 0). To construct the matrix A, the program constructs four matrices A_ij of size Ni by Nj. The elements of these matrices A_ij are either 0 or 1. To assign a value to the element a_ij in the matrix A_ij, the program randomly generates a number from the standard uniform distribution on the open interval (0; 1) and if the number is less than Cij Nj then the element a_ij of the matrix A_ij will take value 1, otherwise the element will be 0. For matrices A_ij with i = j, the diagonal elements are made zero by replacing diagonal elements by zero. First, two matrices with the same k value are horizontally concatenated and then the matrices obtained after the horizontal concatenations are vertically concatenated to produce N1 - N2 adjacency matrix A. The numbers N1 and N2 represent the numbers of nodes of type 1 and type 2 respectively. The value of N1 is obtained by rounding the product of the network size N and the node proportion q1 of type 1 to the nearest integer. Then the remaining number of nodes N-N1 is the number N2 of nodes of

4.1. calltest.m:

The program calltest.m is the main file that runs the simulations.

This program allows users to input parameters via two GUIs.

The input parameter N_val is a vector. The elements of N_val are the values for sizes of the networks. The program has set the maximum network size to 13,000. If user inputs number greater than 13,000 for the network size, then program displays following error messages in the command window:

`Extremely large network size. '

`Use numbers less than 13000 for network size '.

The minimum and the maximum values of the proportion of nodes of type 1 are given by input parameters q1min and q1max respectively. The program

To compute rho, the program GSC threshold.m denes two non-linear functions root2d and root2r as in Equation (15) and (16) of [1]. Each of these functions represents a system of non-linear equations in two variables. The program numerically solves these two by two systems of non-linear equations by using the inbuilt MatLab function f-solve. Since the probabilities, PNi are numerical solution computed by MatLab these values can be very very small numbers. To avoid these artifacts, the program replaces values of rho less than l_t by

For each distinct pair of the scaled mean vector c and the network size N, the program produces an adjacency matrix of a loop-free digraph (with all diagonal entries 0). To construct the matrix A, the program constructs four matrices A_ij of size Ni by Nj. The elements of these matrices A_ij are either 0 or 1. To assign a value to the element a_ij in the matrix A_ij, the program randomly generates a number from the standard uniform distribution on the open interval (0; 1) and if the number is less than Cij Nj then the element a_ij of the matrix A_ij will take value 1, otherwise the element will be 0. For matrices A_ij with i = j, the diagonal elements are made zero by replacing diagonal elements by zero. First, two matrices with the same k value are horizontally concatenated and then the matrices obtained after the horizontal concatenations are vertically concatenated to produce N1 - N2 adjacency matrix A. The numbers N1 and N2 represent the numbers of nodes of type 1 and type 2 respectively. The value of N1 is obtained by rounding the product of the network size N and the node proportion q1 of type 1 to the nearest integer. Then the remaining number of nodes N-N1 is the number N2 of nodes of

Related

## Nt1310 Unit 1 Exercise 1

655 Words | 3 PagesThe preceding figures shows the Fibonacci and Galois implementations of maximal length shift register m-sequences. As can be seen in these figures, m-sequences contain m shift registers. The shift register set is filled with an m-bit initial seed that can be any value except 0 (if the m bits in the m shift registers are all zero, then it is a degenerate case and the output of the generator is 0). The following examples demonstrate bit generation. 1.

## Nt1310 Unit 9 Study Guide

478 Words | 2 PagesFor a system, y(n)=nx(n), the inverse system will be, a) y(1/n) b) y(n)/n c) ny(n) d) n-1y(n) 15. The evaluation of correlation involves, a) Shifting, rotating and summation b) Shifting, multiplication and summation c) Change of index, folding and summation d) Change of index, folding, shifting and multiplication 16. Z-transform of x(n)=δ(n) a) -1 b)0 c)1 d) None of the above 17. Z-transform of x(n)=-u(-n-1) a) 1/(1+z-1) b) 1/(1-z-1) c) (1+z-1) d)

## Pt2520 Unit 3 Datatype Analysis

643 Words | 3 PagesNote that the Database Engine inserts the same padding character regardless of the collation that is used. binary Trailing zeroes are removed. Table 4. Some of the MS SQL Datatypes Affected By Compression Some of the datatype that don’t yield any row level compression benefit are tinyint, smalldatetime, date, time, varchar, text, nvarchar,xml. MS SQL Server Page Compression can be applied to tables, table partitions, indexes and index partitions.

## Pt1420 Unit 6

693 Words | 3 PagesThe eight most commonly utilized graphs are linear, power, quadratic, polynomial, rational exponential, logarithmic, and sinusoidal. Domain and Natural Domain: Each function has a domain, the arrangement of (input) values over which it is characterized. In the event that I don 't state what the domain is, by tradition we take the domain to be all (real) numbers for which the expression characterizing the function can be evaluated. We call this the "natural domain" of the function. Piecewise Function: A function that acts differently in view of the input value, a function made up of pieces or a function which is characterized by multiple sub functions, every sub function is for sure interim of the primary function are called piece wise function.

## Nt1310 Unit 3 Research Paper 1

279 Words | 2 PagesOur protocol takes two integers decomposed into encrypted bit vectors [a][b] and outputs the greater integer. In this configuration cloud 1 (C1) has the encrypted bit vectors of the integers being compared and cloud 2 (C2) knows the private key. The protocol is as follows in a very concise form. we can say with firm conviction that vector [Y] consist of encrypted zeros at every location except one location which holds the value of encrypted one. This distinct location identifies the first position where vector [a] and [b] differ.

## Nt1310 Unit 6 Lab 1

443 Words | 2 PagesFrom the design specifications, we know that Q = 0 if DG = 01 and Q = 1 if DG = 11 because D must be equal to Q when G = 1. We assign these conditions to states a and b. When G goes to 0, the output depends on the last value of D. Thus, if the transition of DG is from 01 to 10, the Q must remain 0 because D is 0 at the time of the transition from 1 to 0 in G. If the transition of DG is from 11 to 10 to 00, then Q must remain 1. First, we fill in one square belonging to the stable state in that row. Next a dash is entered in the squares, where both inputs change simultaneously.

## Nt1310 Unit 4 Lab Report

603 Words | 3 PagesHowever, the cascade of the transmitter-to-relay and the relay-to-receiver channels, $h_{1} imes h_{2}$, are combined and represented by a single channel, $h$. Such representation leads to estimation of fewer parameters. It is to be noted that the real and imaginary components of $h$ have Laplace marginal pdfs. Details of the derivation of the statistical characteristics of $h$ is given in Section ef{sChmodel1.2}. The third channel model, represented by emph{Channel 2.1}, assumes $h_{1,k}$ and $h_{2,k}$ are time-varying circularly-symmetric complex Gaussian channels that take different values at every instant of $k$.

## Analysis Of Vigenère Cipher

2141 Words | 9 PagesFor example let the code be: “mybirthdayisinjanuary” and let’s take the key to be “math” Plain Text m y b i r t h d a y i s i n j a n u a r y Key m a t h m a t h m a t h m a t h m a t h m Encrypted Text y y u p d t a k m y b z u n c h z u t y k Thus the encrypted text cannot be broken easily and if someone tried without a key there are 265 ≈ 1.2 X 107 possibilities unlike the Caesar cipher with just 25 possibilities. Decrypting the Vigenère

## Nt1330 Unit 3 Assignment 1 Algorithm

170 Words | 1 PagesQ2.Given an array of n elements that accepts non-repeated items, design an algorithm to sort the array in O(n) time. For example, n=15 Items: 23,67,34,2,5,12,7,43,28,90,58,3,74,50,48. Solution: #include #include typedef struct Node { int data; struct Node * next; } Node; Node * create_node(int val){ Node * temp = (Node *)malloc(sizeof(Node)); if(temp){ temp->data = val; temp->next = NULL; } return temp; } /* This function inserts node at the head of linked list */ void push(Node **headRef, int data){ Node * new_node = (Node *)malloc(sizeof(Node)); new_node->data = data; new_node->next = *headRef; *headRef = new_node; } void printList(Node * head){ while(head){ printf("%d->", head->data); head = head->next;

## Episodic Memory Theory

1000 Words | 4 PagesThis pattern, represents an episode. It is similarly learnt as weight adjustments on the connections between F2 layer and selected category of F3 layer. An episode can be recognized based on the selected node in F3 layer and can be reproduced by a readout process. The corresponding events can be read out from F2 to F1 layer. Thus encoding, storing and retrieval of events is performed based on computational principles and

## Pt1420 Unit 2 Study Guide

420 Words | 2 Pages(2x − 3y)^4=16x^4-96x^3y+216x^2y^2-216xy3+81y^4 5. The possible variable terms would have to be a2b3; a5b3; ab8; b8; a4b4; a8; ab7; a6b5 because the exponents of each one of the terms all add up to 8. Task 3 Q&A Using the Fundamental Theorem of Algebra, complete the following: 1. Determine how many, what type, and find the roots for f(x) = x4 + 21x2 − 100. 2.

## Nt1310 Unit 1 Network Analysis Paper

598 Words | 3 PagesThese are defined by the first four bits of each address. You can identify what class an IP address belongs to by looking at these bits. The process of dividing a network into smaller network sections is called subnetting. This can be useful for many different purposes and helps isolate groups of hosts together and deal with them easily. As what was discussed above, each address space is divided into a network portion and a host portion.

## NT1330 Unit 3 Assignment 1

443 Words | 2 PagesThe knowledge base consists of a collection of fuzzy if-then rules of the following form: $R^{l}$: if $x_1$ is $F_1^{l}$ and $x_2$ is $F_2^{l}$ and $ldots$ and $x_n$ is $F_n^{l}$, then is $G^{l},~l=1,2, cdots ,n$, where $x=[x_1,cdots,x_i]^{T}$ and $y$ are the FLS input and output, respectively. Fuzzy sets $F_i^{l}$ and $G^{l}$, associated with the fuzzy functions $mu_{{F_i}^{l}}(x_i)$ and $mu_{{G}^{l}}(y)$, respectively. $N$ is the rules inference number. \Through singleton function, center average defuzzification and product inference cite{shaocheng2000fuzzy}, the FLS can be expressed as: For any continuous function $f(x)$ defined on a compact set $Omegain R^n$, there exists a fuzzy system $y(x) = heta ^T xi (x)$ and any positive constant $delta$, such that: where there exists an ideal parameter vector $ heta ^*$ to estimate the value of the vector $ heta$. The optimal parameter vector $ heta ^*$ can be defined as: According to Lemma 1, in order to estimate the

## Pt1420 Unit 6 Algorithm Report

150 Words | 1 PagesHash queries. To respond to H queries, C maintains a list of tuples called the H-list. The list is initially empty. When A issues a hash query for a conjunctive keyword W_i={W_1 || W_2 ||...||W_s}, algorithm C checks whether W_i=W_j, if so, algorithm C answers consistently with the previous queries by responding with H(W_i) = h_i. Otherwise, C generates a random coin d_i={0,1} so that Pr[d_i=0]=1/(q_T+1), then C selects a random element γ_i∈Z_q, if d_i=0, C computes h_i=g^(γ_i ), otherwise, C computes h_i=g^x, C adds the tuple to H-list, and responds to A with H(W_i) = h_i.

### Nt1310 Unit 1 Exercise 1

655 Words | 3 Pages### Nt1310 Unit 9 Study Guide

478 Words | 2 Pages### Pt2520 Unit 3 Datatype Analysis

643 Words | 3 Pages### Pt1420 Unit 6

693 Words | 3 Pages### Nt1310 Unit 3 Research Paper 1

279 Words | 2 Pages### Nt1310 Unit 6 Lab 1

443 Words | 2 Pages### Nt1310 Unit 4 Lab Report

603 Words | 3 Pages### Analysis Of Vigenère Cipher

2141 Words | 9 Pages### Nt1330 Unit 3 Assignment 1 Algorithm

170 Words | 1 Pages### Episodic Memory Theory

1000 Words | 4 Pages### Pt1420 Unit 2 Study Guide

420 Words | 2 Pages### Nt1310 Unit 1 Network Analysis Paper

598 Words | 3 Pages### NT1330 Unit 3 Assignment 1

443 Words | 2 Pages### Pt1420 Unit 6 Algorithm Report

150 Words | 1 Pages