Aim: To be able to identify the five different fruit flavors of skittles by using the sense of taste, while the participants of this experiment are blindfolded.
In class, a series of experiments were performed that pertained to the enzyme known as catalase, which converts hydrogen peroxide into oxygen. Due to peroxide being toxic to the tissues of both plants and animals, both possess the enzyme catalase, which breaks into two non-toxic compounds: water and oxygen gas. Enzymes are proteins that react to certain substrates to create a product, and continue doing so afterwards.
1. Free ears in dogs are controlled by dominant allele (F), and attached ears are controlled by the recessive allele (f). In addition, Short dogs is due to a dominant allele(S), and long hair is due to a recessive allele (s). Which of the following is the genotype of the dogs with free ears and short hair?
The theory I hope to try and figure out is that how long would it take me to get to the center of the Tootsie Roll Pop? Also are there other ways to get to the center of the Tootsie Roll Pop? Like really have you ever looked at a Tootsie Roll Pop it looks like it would take forever to get to the center of the Tootsie Roll Pop! Unless you bite it or like some other technique of getting to the center of the lollipop. That’s why I’m also conducting other techniques of getting to the center of the Tootsie Roll Pop.
Obtain a small sample of the red epidermal cells from the stalk of the rhubarb by carefully peeling away the layer with forceps.
Research Question: How does the change in the concentration of a sucrose solution affect the process of osmosis in a potato cell by measuring its mass?
The results do not support the hypothesis that a higher surface area to volume ratio would result in sulphuric acid being diffused into the agar cubes in the shortest amount of time. This is evident in the results as the exact opposite to what was predicted occurred. Instead of the smallest cube with the largest surface area to volume ratio of 1cm3 having the quickest diffusion rate, it conversely took the longest at 0.092 cm3 per second, whilst the 2cm3 cube with 0.0384 cm3 per second took the least amount of time. This directly refutes the hypothesis. There was also no consistent trend evident in the results. Between the two largest blocks of 2cm3 and 3cm3, there was only a 0.00243 cm3 per second, however, and in contrast to the hypothesis,
In this lab we used two processes called Diffusion and Osmosis. Diffusion is the movement of molecules from areas of high concentration to areas of low concentration. Diffusion is a process that requires no energy and involves smaller non-polar molecules. In Figure 1 you can see the molecules spreading throughout the glass from the area of high concentration, so that the areas with low concentration are filled evenly as well. The other process was osmosis. Osmosis is the diffusion of water through a membrane from an area of high contraction to an area of low concentration. Osmosis happens in three different environments. Osmosis is like diffusion in it requiring no energy.
Based on the data and the recorded observations, my hypothesis is correct. When a solution is hypotonic, this causes the cell to swell, because there are more water molecules on the inside of the cell. If positive feedback continues, the cell will eventually burst. When a solution is hypertonic, this causes the cell to shrink, because there are more water molecules on the outside of the cell. Over time, the cell will start to function poorly (“Difference between Hypertonic, Hypotonic, Isotonic Solutions”). Therefore, the cell needs to maintain its internal environment through osmosis. In a hypotonic solution, osmosis allows water molecules to move from the inside of the cell to the outside, so as to keep the concentrations balanced. In a hypertonic
The cell membrane act as a roadblock for cells. The cell membrane has a very hectic job. It restricts the access to what comes in and what goes out. The bond the membrane shares with others is the idea of accountability. The cell membrane regulates the deoxyribonucleic acid, enzymes, and it builds a pathways for any reaction such as metabolic. When waste products are present the cell membrane gets rid of it and the cell membrane allows important things inside . A great example of what the cell membrane allows in or out is water and oxygen. Specific molecules are only made to enter the cell which is also called semipermeable. Molecules can be passed by active transport or either passive transport. Active transport is when passage of materials using energy. Passive transport is the passage of materials using kinetic energy.
In this lab I will be exploring how temperature impacts the rate of osmosis by placing pieces of potato of equal size in solutions of different temperatures and observing the change in mass of potato after a given period of time. The change in mass will indicate the rate of osmosis.
This experiment is an attempt to investigate the amount of water potential across root storage plant species. The root storage plant species that shall be used are the carrot and the potato and the method that shall be used is known as Chardakov’s method. Water potential is the tendency of water to enter or leave a cell. Water moves from an area or region of low water potential to an area of high water potential. It is important to note that the highest water potential is 0(the water potential of pure water) and the other water potential values are in negative numbers .
When you put an egg in vinegar, we see that the shell dissolves, but do you ever wonder why? An egg is made mostly out of calcium carbonate which reacts with an ingredient in vinegar, acetic acid. Acetic acid is about 4% of the vinegar and what breaks apart the solid calcium carbonate crystals. The bubbles we see, from the egg, is the carbonate that make carbon dioxide and the other calcium ions float free. This is the equation:
The overall project goals and central questions that has to do with the project is mostly trying to determine the isotonic concentration of the salt in potato roots and the use of the ideal soil salt conditions for the potato plant growth. In part 2, we had to test the enzyme activity that is in the was involved in the potato, so we can also determine the ideal soil pH conditions for the potato plant growth. In part 3, we were able to test absorb the leaf pigment at various wavelengths that determine the optimum light absorption conditions and was able to make recommendations for the light conditions that would be used un greenhouses.
What are effects of the volume of a potato and the amount of weight it loses when placed in salt solution?