Data Presentation:
Graph 1: Color vs Mass
The solutions in the colors red, orange, and blue had final weights greater than their initial weights. The potato cores gained mass. The yellow, green, and purple sucrose solutions had initial weights was greater than their final weights. The potato cores loss mass.
Table 1: Color vs Percent Change
Color
Percent Change red 5.22 % orange 10.81 % yellow -5.20 % green -1.56 % blue 9.45 % purple -1.81 % water 9.67 %
Percent Change in Mass = Final Mass – Initial Mass X 100 Initial Mass
The red, orange, and blue sucrose solutions resulted in percentage changes that were positive. Their final masses were greater and these solutions were hypotonic. The gain in mass suggests that it’s is a hypotonic environment because the solution moved into the potato core/cell. A hypotonic environment
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The lab also supported: the more mass the potato cores gain, the more hypertonic potato cores are to the sucrose solutions. Sources of human error could have been cutting the specific measurements potato, forgetting to zero the electronic mass, and/or reading/recording data incorrectly. The potato cores were cut from different potato which may have skewed the results. Some cores could have also been cut more diagonally than others, resulting in a greater volume to surface area ratio. There were no noticeable mistakes made that could be pinpointed and I do believe that the data was relatively accurate. I am not sure how the lab could be modified to improve the results. For most of the lab, I was not present, so I am not aware of any inherent weaknesses. Overall, the results were pretty similar to the intended conclusions, with the exception of purple and green / .6 M and .8 M being reversed. The difference in percent change was .15% and the cause for this was not
The tonicity of solution relative to eggs in water and the 0.5M glucose were hypotonic, because each egg increased in mass over 60 minutes. The tonicity of the eggs in 1.5M glucose and 2.0M glucose were hypertonic because each egg decreased in mass over 60 minutes. The water moved towards the hypertonic solution through the membrane of the egg in the water and 0.5M glucose solutions, causing the egg to increase in mass. The water moved out of the hypotonic membrane in a hypertonic 1.5M and 2.0M glucose solutions, which caused the egg to decrease in mass. Relevance
The beanium demonstrates this as there are more of one kind bean than there are of another kind. The results of this experiment could have been compromised by a number of things. The scales used seemed unreliable. When the beans were removed from the scales the numbers would count down from the weight they previously displayed. On multiple occasions they would stop at at negative number.
First, it was hypothesized that test tube "A", the control, would not show any red concentration, test tube "B" which contains supernatant II would show the most red concentration and test tube "C" which contains sediment II would only show a little red concentration. The second hypothesis states that the raw corn kernels would have mitochondrial activity while the boiled corn kernels would not. The last hypothesis interprets that the "gunk" and sediment I will both contain starch granules. It was only expected to find mitochondrial activity in Supernatant II. Unfortunately, after performing this experiment, we were not able to support this hypothesis and come up with a conclusion.
There are few vegetables and fruits that turns to the color brown if their surface is exposed to oxygen. Once the veggies or fruits been exposed to oxygen, then the browning begins to appear, and electrons and hydrogen will be removed. This happens because of an enzyme called catechol oxidase. The enzyme will act on its substrate catechol to form a yellow compound which then reacts with the oxygen in the air and change into benzoquinone. The more concentration of the enzyme, the more browning appears.
This indicates that all of the solutions have been hypertonic in relationship to the potato tubes. The concentration of the solute (salt or sugar) has been higher in them than the concentration of the solute in the solutions that we have tested them in. Nonetheless, some solutions have been a closer match to the osmolarity of the potato tubes than others, such as 0.6 (M per mL) which has caused the tissue to lose -3.6% of its weigh only, compared to 1.0 (M per mL), which has caused the potato to lose -36.6% of its weight. Therefore, the net movement of water in the solutions that displayed a bigger loss in the weight of potatoes has been higher than solutions where the potatoes have only lost a small amount of their weight.
Additionally, it was difficult obtaining a piece of rhubarb that was thin and particularly red, therefore the effect could not be best observed in the cells. Part B: Design your own experiment Parts of this practical were taken and slightly altered from the following link http://www.markedbyteachers.com/gcse/science/investigate-the-effect-of-surface-area-on-osmosis-in-potato-tissue.html Aim: To observe the effect different surface area: volume ratios have on osmosis in potato tissue. Hypothesis: If the potato has a larger surface area: volume ratio, the quicker osmosis will take place and the larger the mass will be at the end of the experiment, therefore the difference in mass of the potatoes from the start of the experiment to the end of the experiment will be larger. Additionally, the potato pieces left in a saltwater solution will decrease in mass, whereas the pieces left in water will increase in mass.
It would lead to the testing of lipid and carbohydrate content in croutons and pumpkin seeds as well as other substances with a high amount of measurable
For this lab I will be using water and sucrose to demonstrate the rate of osmosis. In this lab I will be exploring how temperature impacts the rate of osmosis by placing pieces of potato of equal size in solutions of different temperatures and observing the change in mass of potato after a given period of time. The change in mass will indicate the rate of osmosis.
Based on the data and the recorded observations, my hypothesis is correct. When a solution is hypotonic, this causes the cell to swell, because there are more water molecules on the inside of the cell. If positive feedback continues, the cell will eventually burst. When a solution is hypertonic, this causes the cell to shrink, because there are more water molecules on the outside of the cell. Over time, the cell will start to function poorly (“Difference between Hypertonic, Hypotonic, Isotonic Solutions”).
The results do not support the hypothesis that a higher surface area to volume ratio would result in sulphuric acid being diffused into the agar cubes in the shortest amount of time. This is evident in the results as the exact opposite to what was predicted occurred. Instead of the smallest cube with the largest surface area to volume ratio of 1cm3 having the quickest diffusion rate, it conversely took the longest at 0.092 cm3 per second, whilst the 2cm3 cube with 0.0384 cm3 per second took the least amount of time. This directly refutes the hypothesis. There was also no consistent trend evident in the results.
The starch-iodide complex forms because of the transfer of charge between the starch and iodide ion and results in spacing between the energy levels. This allows the complex to absorb light at different wavelengths resulting in a dark blue colour (Travers et al., 2002). A blue colour would indicate a positive test while a yellow colour would show a negative test. The Benedict’s test is useful for reducing sugars.
7. In this experiment, if the sucrose concentration were increased to 70 g/l would you expect sucrase activity to be significantly higher than the activity at 35 g/l. Explain your answer. No, because based on the results once it reached 30 g/l 35 g/l the results had stayed the same. There, the activity is lessening and coming to what looks like a plateau. 8.
By using the same mass of potato slices and putting them in different concentration of solutions for a specific amount of time will tell us how the concentration changes the mass of the potato slice. Therefore changing the rate of osmosis. Hypothesis: I predict that, if the piece of potato was put into a solution that has a high concretion of sucrose then the potato slice would lose mass as it would lose water from its cells because the water is moving out of the cell from a high concentration to a low concentration of water through a semi- permeable membrane. The cell is hypotonic and the solution is hypertonic.
The hypothesis we came up with for this project was that in the distilled water there wouldn't be no change in the potato, we wouldn’t see a gain or loss with the water sitting in the beaker. The beaker with the 30% Sucrose and Distilled water we predicted that there was going to be weight gain to the potato. And for the distilled water with the 30% sucrose and we predicted weight loss. But the results came out to be the first bag content being isotonic the second bag came out to be hypotonic and lastly the result came out to be
Biology Design Practical Joshua Edwards What are effects of the volume of a potato and the amount of weight it loses when placed in salt solution? Introduction This design practical uses a potato’s surface area to volume ratio to see what affects it has on osmosis in different concentrations. Osmosis is the movement of water molecules through a cell membrane into an area of a higher solute concentration. The movement goes the way of the solvent with more solute because the lower solute concentration is drifting through balancing the ratio of solute per solvent (En.wikipedia.org, 2018).