Rate Law Of A Reaction Rate Of Hydrochloric Acid

800 Words4 Pages
Abstract: To determine the rate law in each reaction and find the reaction rate, an experiment was conducted with acetone, acid, iodine, and water. By using different concentrations of each substance, a number of 4 times, the rate was giving of each reaction and recorded the times it took to react. Based off the results from the first four reactions, further data was collect with a fifth reaction. Using 15mL of acetone, 10mL of hydrochloric acid, 5mL of iodine, and 20mL of water, we got a rate of 8.77× 10-7. The reaction rate was much higher than the rates of the previous reactions. So essentially the amount of water determines the rate, and the amount of acetone determines how long it takes the solution to react and become completely clear. Introduction: To conduct this experiment, the rate law of a reaction was used, and included the rate of the reaction, the rate of the constant, and the concentrations of the reactants. Stated in this equation: rate ₌₌ k (reactant one)m (reactant two)n (reactant three)p. Where is k being the rate law constant and m, n, and p are the reactant order. The concentrations of the reactant are then determined by the reaction order. To calculate the concentrations, we used the equation: M1V1=M2V2 and used that to determine the rate using the equation rate= iodine/ time. Time involves in how fast the reaction takes place. If their action occurs in a short time, the reaction will be faster and if the reaction takes a long time, it has a slow

More about Rate Law Of A Reaction Rate Of Hydrochloric Acid

Open Document