At a constant interface area in double emulsion system and when the concentration of separated element in feed solution is much lower than the concentration of carrier in membrane and their chemical interaction does not change the concentration of carrier at interphase substantially, most of the results on membrane extraction (pertraction) can be approximated by a pseudo-first order kinetic law: Where R is the yield of recovery (dimensionless fraction) at time t and R is the yield at pseudo-equilibrium and k is the effective rate constant of membrane extraction (min-1), which consists from a hydro dynamically influenced part and distribution dependent part .Therefore, all results were statistically treated by standard least-square method on a PC computer (program) to obtain the …show more content…
The effect of the mixing speed on nickel extraction was presented in the figure (9). It was observed from figure (8), that increasing in nickel extraction percentage was observed to be very fast for all tested rpm at the end of first 2 min. After that time, changes in the percentage of nickel extraction were not sharp. In general, it was observed that the nickel extraction percentage was increased with increasing in mixing speed due to the large surface area of ELM. The increasing mixing speed causes an increase in the interfacial area between the membrane phase and the feed phase due to the formation of smaller globules smaller sized emulsion droplets were formed in 300 rpm, leading to a large surface area to provide the effective mass transfer. However, the stability of ELM was adversely affected with higher mixing speed leading to breakage around the ELM globules. So, the extraction rate of nickel was decreased and ELM stability was broken after the 4th min. It was clearly observed from figure (9) that stable extraction was achieved at the end of 10 min. with 250
Results The lab experiment was done in two parts, one with the NAND, NOR, XOR and Hex Inverters and the other with a 7483 full adder gate, both will verify the truth table when two input bits and a carry are added together. The circuits were built by examining the 1 bits through a K-Map to create a Boolean expression for the sum and carry. The Boolean expression for the sum was A⊕B⊕C and the carry as AB+BC_in+AC_in. From these two expressions, we notice that we must use two exclusive-ORs gates in the sum inputs for A, B, and C. For the sum, we have to use NOR and NAND (the only available gates from the lab manual).
For most sequences at position 4 and 5 we observe only the nucleotides G and T, respectively. There may be rare cases where other nucleotides may also be found. To consider such observations, we need to do a process called additive smoothing or Laplace smoothing to smooth the categorical data. [9] In this case, we add 4 sequences: AAAAAAAAA, CCCCCCCCC, GGGGGGGG, TTTTTTTTT.
I need to find the area of rectangle ABCD. I know that ABCD is a rectangle with diagonals intersecting at point E. Segment DE equals 4x-5, segment BC equals 2x+6, and segment AC equals 6x. I predict that To find the area of rectangle ABCD I need to find out the base and height of the rectangle. The first step is to find what x equals. Since I know the intersecting line segments AC and DB are congruent that means when I times the equation 4x-5 for segment DE by two it will equal the equation 6x for segment AC.
%% Init % clear all; close all; Fs = 4e3; Time = 40; NumSamp = Time * Fs; load Hd; x1 = 3.5*ecg(2700). ' ; % gen synth ECG signal y1 = sgolayfilt(kron(ones(1,ceil(NumSamp/2700)+1),x1),0,21); % repeat for NumSamp length and smooth n = 1:Time*Fs '; del = round(2700*rand(1)); % pick a random offset mhb = y1(n + del) '; %construct the ecg signal from some offset t = 1/
Suppose we have a single-hop RCS where there is one AF relay that amplifies the signal received from a transmitter and forwards it to a receiver. Assume that the transmitter sends over the transmitter-to-relay channel a data symbol ${s_k}$, from a set of finite modulation alphabet, $S={S_1, S_2,ldots,S_{cal A}}$, where ${cal A}$ denotes the size of the modulation alphabet. The discrete-time baseband equivalent signal received by the relay, $z_k$, at time $k$ is given by egin{equation} z_k = h_{1,k}s_k + n_{1,k},~~~~for~~k=1,2,ldots,M label{relaySignal} end{equation} where $n_{1,k}sim {cal N}_c(0,sigma_{n1}^2)$ is a circularly-symmetric complex Gaussian noise added by the transmitter-to-relay channel, $h_{1,k}$ denotes the transmitter-to-relay channel, and
(a) 3Mbps / 150Kbpa =3 X 1024 / 150 = 3072 / 150 =20.48 20 Users can be supported 150Kbps dedicated. (b)
1. The test subjects will prepare for sleep by acquiring everything needed for the subjects’ sleep preferences. 2. The test subjects will all set alarms on their smartphones for approximately 6, 8, and 10 hours after the subjects’ enter the resting period (Subjects may wake during the resting period for the bathroom, but they must not stay awake for more than ten minutes at a time to prevent as much deviation as possible.). 3.
1. There are two ways of maximizing points in this experiment. The first one is that I should connect myself to a vertex that is in the biggest component and purchases immunization. Since the probability of being infected is based off of expected value, I would have less than 1% chance of getting infected. The second way is that I try to make myself stay in the second-largest connected component.
1. What area/aspect of this setting is the most challenging? 2. In the setting, you work in, is there a certain population of patients you see more? How does this affect you?
1. Identify the range of senses involved in communication • Sight (visual communication), Touch (tactile communication), Taste, Hearing (auditory communication), Smell (olfactory communication) 2. Identify the limited range of wavelengths and named parts of the electromagnetic spectrum detected by humans and compare this range with those of THREE other named vertebrates and TWO named invertebrates. Figure 1: the electromagnetic spectrum source: www.ces.fau.edu Vertebrates Human Japanese Dace Fish Rattlesnake Zebra Finch Part of electromagnetic spectrum detected ROYGBV (visible light) detected by light sensitive cells in the eye called rods and cones.
In lab 3.1 we took a look at attentions and how different task require different amounts of attention for certain tasks. When a secondary task is added the participant has not done before or is difficult, it task away attention or “ space” for the primary task. For this lab we wanted to see how our walking would change when our attentional demands changed with the addition different task to perfumer using a tennis ball. In condition one the participant was asked to walk across the room (there and back) for a total of five trials.
In this week’s lab we had to determine the density of a quarter, penny, and dime. My question was “How does is each coin?” Density is the amount of mass in an object. To find the density of each coin in this lab, we used a triple beam balance to find each coin’s mass and a graduated cylinder to find their volumes. With all this information, I can now form a hypothesis.
Brenda Umana Daniels 17 July 2014 English 3 Nickel and Dimed: On (Not) Getting by in America Important; that’s the first word that comes to mind after the reading of this novel. Ehrenreich’s writing in Nickel and Dimed: On (Not) Getting by in America is very powerful, brutally honest, and extremely engaging. She gained so much from her experiences, and we gained even more when reading them. Although she cheated on few occasions, she gives a clear insight into what poverty is, and how a life in a low pay, heavy workforce is not a life at all.
The purpose of this lab was to change pennies from copper to silver to gold, like alchemists have attempted to do in history. Through the data and observations gathered throughout this experiment, it can be concluded that the pennies were not changed into a different element. For example, the density of the penny from 2005; which was the penny that was experimented on to see whether or not it could turn into silver; was 4.62 g/cm3 before the experiment and 4.89 g/cm3 by the end of the experiment. If this copper penny really would have turned into silver, then the density of the penny would be 10.49 g/cm3; which is the density of silver; by the end of the experiment. The penny may have turned silver in color, but this was only because it was plated in the zinc that was added to the beaker of water in the experiment.
Copper Cycle Lab Report Ameerah Alajmi Abstract: A specific amount of Copper will undergo several chemical reactions and then recovered as a solid copper. A and percent recovery will be calculated and sources of loss or gain will be determined. The percent recovery for this experiment was 20.46%.