Therefore, the distance from the origin is a fixed proportion of the distance of the line. Based on this, it can be stated that d is the position of the directrix of the conic section considering that the eccentricity is greater than zero and less than one. Furthermore, the equation, r=ed1+e(cos(), is the exact equation for an ellipse in polar coordinates with a directrix at x=d and focal points at both the origin and the negative x-axis, further proving Kepler’s First Law of Planetary Motion: that the shape of the orbits is an ellipse with one focal point being the center of the
Below is an example equation using hypothetical values: Let x = 15 meters Let d= 7 meters (standard width of goal posts in Rugby Union) y= √(〖15〗^2-(7/2)^2 ) y=√(225-〖(3.5)〗^2 ) y=√212.75 y=14.58 The optimal position to take the conversion 15 meters away from the centre of the posts is 14.58 meters from the try line, along the conversion line. Hughes’s Model After doing some research I came across Hughes’s Model. It is an extension of my model as it provides points along a conversion line that allow the kicker the best chance to successfully convert the ball. In order to find the position that provides the maximum angle, a series of expanding circles with AB as a chord can be drawn. All the inscribed angles in each of the circles are equal (inscribed angles on the same chord law) and these sets of equal angles decrease with an increase in size of the circle (exterior angle theorem for a triangle).
What´s difficult is getting the ball at a certain speed, placing it at the right angle, from a particular distance at a specific angle in the net, that´s what most soccer player struggle with and hence the question: At what angle, velocity in correlation to distance does a soccer ball need to be in order for it to hit the net? Different distance Calculate the Vertica Height of the football Calculate the velocity and angle (trail) Different angles you can place the ball, from a certain distance Lastly, at what angle, velocity do you need to hit the ball, from a certain displacement to get in the goal post? Spin The first thing that should be known is the distances, the vertical distance and the horizontal distance. The vertical distance can be measured through different ways moreover the horizontal distance which is more easier can be measured using a tape. Moreover in this investigation different distance were taken to measure the two other variables which are the velocity of the ball and the angle at which the ball went at.
Find the area under the standard normal curve between z = -1.65 and z = 0. Answer: The area may be represented as . Since the normal curve is symmetric, then 3. Find the area under the standard normal curve between z = -1.65 and z = 1.96. Answer: The area may be represented as.
the retina, not on the retina, because the cornea bends the rays too much or the eye was stretched too long, the eye is myopic, or nearsighted. To bring this eye into focus, the rays must be diverged (actually, less converged) so that the point of focus is on the retina. When the rays meet or focus in front of the retina, they cross and are diverging when they hit the retina. Instead of a point of light on the retina, they cast a blur circle. When the many points of an image become overlapping blur circles, the image is blurred and fine detail is lost.
The diameter of the individual dots was 0.06°. Spheres rotated around either vertical or horizontal axis with an angular speed of 72°/s (0.2 Hz). Objects were placed to the left and to the right of the fixation (horizontal arrangement) or above and below the fixation (vertical arrangement). The gap between the objects was 0, 0.1, 0.25, 0.5, and 0.8 sphere widths or, respectively, 0.0° (the touching layout configuration in Experiment 1), 0.6°, 1.5°, 2.0° (the gap layout in Experiment 1), and 4.8°. Displays were presented either on a uniform gray background (no background condition) or on the textured background (background condition).
Therefore, my result is very close to the actual value. From these results, we can conclude that the relation between tension and wavelength is direct. Consequently, using the data, I proved that my hypothesis was correct and they are related as in the formulas presented.
Calculate “i”/angle of impact. Solution: The formula for angle of impact is θ=arcsine (W/L). The width in the triangle is 3m and the length is 16m. Sine i= width / length. Sine i=3m/16m= .1875 Inverse Sine I (.1875)=10.80 the angle of impact is between 10-11° Question 15 Topic: B2 – Analysis of Materials – Fingerprints Question: What is dactylography?
Run the result in point 3 (P1') through a transformation function called F In which the 32 bit is divided into 4 bytes each one uses as indices to a value in the S-boxes a ,b ,c ,d as shown in fig 2. 5. The first two values from S-box 1,2 are added to each other then Xored with the third value from S-box3 . 6. The result is added to the value from S-box4 to produce 32 bit .