3. GOVERNING EQUATIONS
In this paper, relaxation model is employed to account for thermal non-equilibrium between the phases. This model is presented by Downar-Zapolski et al. [16] and is employed by several authors to numerically simulate steady flashing flows [17-19]. Barret et al. [20] used this model to compute unsteady flashing flows in variable cross section ducts.
Relaxation model consists of three conservation laws (mass, momentum, energy) for the two-phase mixture in addition to the mass balance law for the vapor phase: ∂U/∂t+∂F/∂z=S where, U=[■(ρ@ρu@■(E@ρx))],F=[■(ρu@ρu^2+p@■(u(E+p)@ρux))],S=[■(0@(-2fρu^2)⁄d@■((4h_TP (T_w-T_L ))⁄d@(-ρ(x-x ̅ ))⁄θ))] where, ρ, p, u, x, x ̅, θ, f and hTP represent respectively mixture density,
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Indeed, the mass conservation law for the vapor phase accounts for the delayed liquid–vapor transition by a relaxation toward thermodynamic equilibrium. In other words, a very high value of the relaxation time (O(θ)≈1) corresponds to a very small inter-phase mass transfer and the model behaves as the frozen model. However, in the case of very low values of the relaxation times (O(θ)≈〖10〗^(-3)), the time required to achieve equilibrium becomes very low and the model approaches the equilibrium model. The relaxation time can be obtained from the correlations for relaxation time as suggested by Downar–Zapolski et al.[16] which gives a separate correlation for high pressure and low pressure flow. In this paper, to avoid discontinuity at the transition pressure; the correlation of Gopalakrishnan [17] which is a combination of two suggested correlations of Downar-Zapolski is employed: θ=6.51×〖10〗^(-4) α^(-0.54) [(p_s (T_in )-p)/(p_s (T_in ) …show more content…
To close the system of equations of Eq. (1) an accurate equation of state as well as proper relations for the void fraction, fanning friction factor and the heat transfer coefficient should be provided. Details of which are presented in the following subsections.
3.1 CONSTITUTIVE EQUATIONS FOR THE VOID FRACTION
Original relaxation model utilizes a simple relation for the void fraction: α= xρ/ρ_sv
According to the study of Bhagwat et. al. [13], the constitutive equations for the void fraction presented by Rouhani et. al. [11], Choi et. al. [12] are among the most accurate equations especially in the range of low and moderate values of void fraction. Both of these correlations are based on drift flux. The general form of void fraction correlations based on drift flux is: α= ρux/(C_o ρu[x+ρ_sv/ρ_ml (1-x) ]+ρ_sv V_j )
Where, Co and Vj are respectively the distribution parameter and the drift velocity. The relations given by Rouhani et. al. [11] for Co and Vj are: C_o=1+0.12(1-x)
V_j=1.18∜(gσ(ρ_sv-ρ_ml )/〖ρ_ml〗^2 )
& { 2872(25$\%$)} & { 2499(22$\%$)} & { 5795(26$\%$)} & { 5100(23$\%$)}\\ $N_{\omega\to\pi^0\gamma}^{\circ}$ & { 4487(15$\%$)} & { 3590(12$\%$)} & { 1978(6$\%$)} & { 1721(5$\%$)} & { 5846(9$\%$)} & { 5145(8$\%$)} \\ \hline $BR^{measured}_{\omega\to\pi^0\gamma}$ & \textcolor{red}{ 1.07} & \textcolor{red}{ 0.78} & \textcolor{red}{ 0.52} & \textcolor{red}{ 0.43} & \textcolor{red}{ 0.73} & \textcolor{red}{ 0.61} \\ ($\%$) & \textcolor{red}{ (15$\%$)} & \textcolor{red}{ (11$\%$)} & \textcolor{red}{ (6$\%$)} & \textcolor{red}{ (5$\%$)} & \textcolor{red}{ (9$\%$)} & \textcolor{red}{ (8$\%$)} \\ \hline & \multicolumn{6}{c|} {\bf $\sigma_{dedp-sys}=\sigma^{av}_{rms}\times(1-\sigma_{fit-sys}^{rel})$ } \\ \hline \end{tabular} \caption[The standard deviation $\sigma^{av}_{rms}$ in ${N_{\omega\to\pi^0\gamma}}^{rec}$, ${N_{\omega\to\pi^0\gamma}}^{\circ}$ and $BR^{measured}_{\omega\to\pi^0\gamma}$ for the different energy-momentum conservation constraint are presented] { The standard deviation $\sigma^{av}_{rms}$ in ${N_{\omega\to\pi^0\gamma}}^{rec}$ and $BR^{measured}_{\omega\to\pi^0\gamma}$ for the different energy-momentum conservation
= IDSS/2 then Schokley’s equation can be written as, I_DSS/2=〖I_DSS (1-V_GS/V_(GS(off)) ) 〗^2 1/2=(1-V_GS/V_(GS(off)) ) ^2 V_GS=0.29V_(GS(off))
In Figs. (\ref{fig:NC3Mont.eps}-\ref{fig:NC6Mont.eps}), the results of the Monte Carlo analysis is presented along with the result obtained for the central values of the parameter. It is observed that for the form factors $C_3^{N \Delta}(Q^2)$, $C_4^{N \Delta}(Q^2)$ and $C_6^{N \Delta}(Q^2)$, Monte Carlo analysis and the prediction for the central values agree at large values of $Q^2$, but deviate from each other for small values of
This new formula would give
In this week’s lab we had to determine the density of a quarter, penny, and dime. My question was “How does is each coin?” Density is the amount of mass in an object. To find the density of each coin in this lab, we used a triple beam balance to find each coin’s mass and a graduated cylinder to find their volumes. With all this information, I can now form a hypothesis.
Introduction The intent of this experiment is to understand how hot and cold water interact with each other by combining clear hot water and black ice cold water. I hope to learn more about how hot and cold water interact with each other. As of now, I know that cold water is denser than hot water. Knowing this I formed my hypothesis.
In 1972, G.S. Graham and P.J. Denning, developed the Graham-Denning Model that shows how subjects and objects should be securely managed to include creation and deletion. It also addresses how to assign specific access rights. The model is set up based on subject, object, and rules that tie in both. The Graham-Denning model resolves the security questions related to defining a set of specific rights on “how particular subjects can execute security functions on an object.” (Pfleeger & Pfleeger, 2003)
From the design specifications, we know that Q = 0 if DG = 01 and Q = 1 if DG = 11 because D must be equal to Q when G = 1. We assign these conditions to states a and b. When G goes to 0, the output depends on the last value of D. Thus, if the transition of DG is from 01 to 10, the Q must remain 0 because D is 0 at the time of the transition from 1 to 0 in G. If the transition of DG is from 11 to 10 to 00, then Q must remain 1.
We found that Joules from NaCl = 340 J, NH4NO3 = 1340 J, CaCl2 = -2320 J, LiCl = -3600, Na2Cl3 = -720 J, NaC2H3O2= 1070 J. Then we used energy release from one one these rxn to calculate the Hor the KJ per mol rxn.
In this lab there were five different stations. For the first station we had to determine an unknown mass and the percent difference. To find the unknown mass we set up the equation Fleft*dleft = Fright*dright. We then substituted in the values (26.05 N * 41cm = 34cm * x N) and solved for Fright to get (320.5g). To determine the percent difference we used the formula Abs[((Value 1 - Value 2) / average of 1 & 2) * 100], substituted the values (Abs[((320.5 - 315.8) /
Introduction: This assignment will explore the Roper, Logan and Tierney model used in first clinical placement and will explain how it helped to guide nurses to focus on the fundamentals of patient care. Patient dignity is upheld by using this model following the principles outlined in the Code of Professional Conduct and Ethics for Registered Nurses and Midwives as will be discussed. An outline of the philosophical claims of the nursing model that guides practice on the unit for first clinical placement.
What is the effect of surface area to volume ratio on the rate of diffusion of the colour from the agar jelly cube? INTRODUCTION: Diffusion is the movement of spreading particles from high concentration to low concentration in an environment such as a cell. This major procedure is used in cells to source them with nutrients, water, oxygen, and to transport unwanted wastes such as carbon dioxide out of the cell or to different cellular organelles.
Predict/ roughly determine the Vmax and ½ Vmax values from the peak of the graph, where the slope of the graph levels off (the asymptotical line). Predict/ roughly determine the Km by reading off of the graph the corresponding substrate concentration on the x-axis for the ½ Vmax value. Plot a Lineweaver-Burke graph (the inverse of the velocity of the reaction vs. the inverse of the substrate concentration). Calculate accurate Vmax and Km values using the following equation for the Lineweaver-Burk
Von Mises [3] states that “the forces due to viscosity appear as products of μ and expressions that have the dimensions area times (velocity / length)”. By further investigation, the mathematical analysis of these principles leads to a system of partial derivatives known as the Navier-Stokes equations. These equations are used to describe fluid flow and can be used to solve specific dynamic fluid flow cases. These include; velocities, pressure, temperature, density and can also be used to solve viscous problems of a dynamic fluid flow problems. These partial derivative equations relating to the specific variables are extremely complex and time-consuming to
so when you multiply the 2.9 by 2 it gives you 5.8 cm3 which was my result. As the voltage increases the volume of hydrogen and oxygen increases. The standard deviation when I used 9 volts for hydrogen it was 0.7 + 0.23= 0.93 and 0.7-0.23= 0.47 so the range of values is between 0.47 cm3 to 0.93 cm3. When I used 9 volts for oxygen it was 0.3+0.12=0.42 and 0.3-0.12=0.18 so the range of values is between 0.18 cm3 to 0.42 cm3.