┐ F = T . ( True ) at x = -3 ( ( -3 )2 > 4 ) ^ ( -3 < 2 ) ( 9 > 4 ) ^ ( -3 < 2 ) Q¬−3: [2+3 marks]
Calculation: Initial Mass(g)-Final Mass (g)=Change in Mass (g) Trial 1 74.5-62.0=12.5(g) Trial 2 272.7-271.5=1.2(g) Percent Error: 272.7-271.5 x 100 272.7 =0.440% Percent Change: 74.5-62.0 x 100 74.5 (Trial 1) =16.778% 272.7-271.5 x 100 272.7 (Trial 2) =0.440%
A way that you can figure it out is by adding ⅖ to ⅓ you can do that by adding the top to which is 2+1=3 so that would be your numerator usually for the bottom it would stay the same if they both have the same denominator but since it is not the same you have to add those to
-x \) And \( \ r(x) = x \) Using the inverse steps introduced in Task 1a the process will be as follows \( \ r(x) = -x \)
10 - 1= 9) If that doesn’t work, and one side is a multiple of ten, reduce, and then use this equation: [(x+10) - 4] / 2 = rebounds (EX. [(6+10) - 4] / 2]
You will now get x = 5 y = 5 You can see that in this example, the x value remains as 5, but the value of y is changed to 5. This is because the statement y = x assigns the value of x to y (y <- x). y becomes 5 while x remains unchanged as 5.
-What is the domain of an algebraic expression? Domain is a set of values for the variable for which the expression makes sense. You can’t have zero in the denominator. As a result of this, restrictions are needed to list the values for the variables in which the denominator would equal zero. Closed dot on timeline =
I learned about my POC was that since I have converted the equation to exponential form, it made this problem a few steps easier now that the only thing that I need is to get t only; the only variable in the equation. The converted equation is (t-1)^2 lne = e^3; at first, Kirby thought that it was easy and try to help me, but in result, when Mr.Marshall came by, he told that "lne" can be cancel out because "lne" is equal to 1, so wouldn't make any changes in the equation at all. Next, I square root both side after he told me to cancel out the "lne" and got t-1= e^3. I added 1 to both side and I got t=
∫▒〖x^2 (〖2x〗^3-1)dx〗 2. ∫▒(x+1)dx/∛(x^2+2x+1) 3.∫▒(2x+3)dx/(x^2+3x+4) 4. ∫▒((〖(x〗^(1/3)+1)^(3/2) dx)/x^(2/3) 5.∫▒〖sec x dx〗 6.∫▒ 〖e^4x dx〗 7. y dx – x2 dy = 0 8. (1 + x2) = dy/dx y3 9. dy/dx=
The equation becomes the following [( ) ] [ ] [ ] We have [ ] [ ] And At the end: [( ) ] [ ] 2 2 2 2
Because this was written on a Chromebook, free applications that are both robust and available online without requiring a downloaded program was key. Google Docs has built-in mathematical typesetting that is easy to use, allowing for both typed shortcuts and simply clicking the option on the menu (if the shortcut is forgotten). For more intensive purposes, the options available in Google Docs may not be sufficient, but for the purpose of this project it was adequate. While there is an add-on for Google Docs that allows for both the construction of equations and graphs, the graph is not created in real-time as the function is being entered.
To graph population or disease, we needed to use exponents; in equation-form, the exponent was an X, but it could be substituted for any number, which would represent the year. You would also find the current population or number of cases and divide them by the amount the previous year (the starting number) and add that to one to find the rate, which would show you if it was growth or decay. Finally, you use the starting number as your constant or y-intercept. If you were trying to graph the decay of a population, the equation could be: y=150,000(1.5)x; if you were trying to graph decay, the equation could be: y=150,000(0.5)x. You can replace X with any number (number of years) to find the population in the future (positive number) or in the past (negative numbers).
A function has three sections the input, relationship and output. e.g. input is a number = 4 relationship is a condition = *2 Output is the value= 8 /*these three steps shows a function.*/ There are numerous types of functions and every type has its own particular diagram.
Write 9-4x^2-x+2x^4 in standard form You first look at all the the numbers in the polynomial and see which coefficient has the highest number exponent. (the degree) which is 2x^4. Then you keeping descending down so -4x^2 would be next. Then you look at the numbers and variables in the problem, all you have left is 9 and -x you always put the variable first so it would be -x, then 9. So your answer would be