Sherm1 M3 M2
Question 1
The reason for the difference in the σM1-M2 across the two studies:
There is a chance that the distribution of differences and variables varies from study in group A and that of Group B
Question 2
Calculate the σM1 – M2 σM1 – M2 = 1.4 – 1.22 = 0.18
Question 3
Question 4
Complete the following:
Identify the IV and DV in this study.
IV=> receipt of coupon
DV=> purchase amount
State the null hypothesis and the directional (one-tailed) research hypothesis.
Null hypothesis => there is no difference in the amount purchased whether a customer receive or not receive a coupon i.e. there is no difference in the means of purchase amount from both groups.
Run an Independent-Samples T Test using SPSS file assessment4b.sav and paste your output
…show more content…
She decides to quiz her students at the beginning of class and again at the end of class.
Repeated measures were used
Question 6
Question 7
Compare t with the one-tailed critical t at the .01 α level. Did the students who studied online score significantly higher on the quiz? Give a decision about the null. one-tailed critical t at the .01 α level = 2.539 reject null since our t value of 4.316 > than critical t of 2.539, we reject the null hypothesis which states that there is no significant difference between the means on the quiz between those who did online research and those who watched a movie.
Therefore, from the higher mean of 19.55, students who studied online scored significantly higher on the quiz.
Question 8
Refer back to your SPSS output from Assessment 4 Question 3. Based on that output, what is the 95 percent confidence interval of the difference?
Equal variances assumed 95% CI (17.989, -1.122)
Equal variances not assumed 95% CI (-18.223, -0.889)
Question 9
Assume the within-group deviation is 108.45 and the between-group deviation is 48.68. Calculate the total deviation.
SST = SSB +
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