To find the volume of the quarter shaped tank you would have to use the volume of the sphere using the equation V=4/3(3.14)r^3. You would substitute the radius of 70 feet into the equation, V=4/3(3.14)(70*70*70). You would multiply the radius 3 times since it's the radius cubed. Once you use a calculator to solve it and you get the answer 1,436,026.67 feet. That's just the volume of the quarter tank so the find the volume of the main tank you would divide 1,436,026.67 by 4
To prove that both products were obtained, but only one of the two products was analyze, a TLC plate of the DCM layer, that contains both products, and of the final product, was obtain. Both had a single dot at Rf value of 0.924. However, the DCM layer dot was double in intensity than the final product. This means that there was more product in the DCM layer than there was in the final
The null hypothesis states that there is not a significant difference in the sizes from the baseline to trial 2. The mean number of coacervates for the baseline is 32. The mean number of coacervates in trial 2 was 26.67. The t- test supports the null hypothesis. A larger t-value means a larger variance in the means of the data, a smaller t-value means less difference between the means.
By: Andrew Barton Periodic Table of Elements The periodic table was created in 1869 by Dmitri Mendeleev. He developed the table to illustrate the trends in properties of then known elements. The periodic tables purpose is to summarize the properties of real elements. Dmitri Mendeleev also arranged the elements known at the time in order of relative atomic mass. Today there are 118 elements on the periodic table; Mendeleev’s version had only 63 elements on it.
9. Theoretical yield = (150.22g/mol)(3.5 x 10^-3 mol of nucleophile) = 0.525 g Actual yield = 0.441 g, Percent Yield = (0.441g/0.525g) x 100% = 84% 10. Percent recovery from recrystallization = (0.172g/0.441g) x 100% = 38% 11. The data table provided below obtained melting point data for crude product, pure product, and mixture of the pure and 4-tert-butylbenzyl. 12.
The first one, the digit value, is always more than one and less than 10. The other, the exponential term, is expressed as a power of 10. There is only one digit to the left of decimal comma. So, instead of writing that the diameter of an atom of lead is 0, 000 000 000 32 m you would write: 3, 2 × 10-10 m A number that is smaller than 1 is represented as something multiplied by
He predicted the discovery of more elements, and left spaces open in his periodic table for them. In 1894, Sir William Ramsay and Lord Rayleigh discovered the noble gases. The noble gases group was then incorporated into the periodic table. In 1897 physicist J. J. Thomson first discovered electrons; small negatively charged particles in an atom. John Townsend and Robert Millikan later on were able to determine their exact charge and mass.
There is no linear relationship between X and Y, and the best-fit line is a horizontal line going through the mean of all Y values. When R2 equals 1.0, all points lie exactly on a straight line with no scatter. Knowing X lets you predict Y perfectly. (http://www.graphpad.com/guides/prism/6/curve-fitting/index.htm?r2_ameasureofgoodness_of_fitoflinearregression.htm) In this graph the R2 value is 0.97 which can be rounded off to 1.0 which means that knowing X which in this case is the different concentrations of sodium thiosulfate, predicts the Y which is the time the time the solution turns cloudy resulting X not to be seen from the opening of the conical flask from a person’s eye
two different directions to the spin. He also gave the world a rule to dictate how an electron in an atom would behave. Pauli’s exclusion principal states that, “if an electron has a certain set of quantum numbers then no other electron in that atom can have the same set of quantum numbers.” When 1926 came Erwin Schrödinger another Austrian physicist built upon Einstein and Louis de Broglie’s idea of wave particle duality. He developed a mathematical Equation that related the pattern of electrons with that of waves, he gave his wave mechanics the symbol psi . In 1932 James Chadwick discovered a second particle in the nucleus, he fired alpha particles at beryllium and found that neutrons were released.
This is 4 point likert type scale. That is not important =0, somewhat=1, moderately important =2, very important =3. Discrepancy subscale reflects the difference between an individual’s actual and ideal appearance with high scores reflecting greater discrepancy it is 4 point likert type scale that is exactly as I am =0, almost as I am =1, fairly unlike me =2, very unlike
For energy signals a) The energy will be finite and power will be infinite b) The energy will be finite and power will be zero c) The energy will be zero and power will be infinite d) Both energy and power will be finite 4. The unit step signal u(n) is delayed by 3 units of time is denoted as, a) u(n+3) = 1 ; n≥3 = 0 ; n0 7. Which of the following system is causal a) h(n)=n(0.5)n u(n+1) b) y(n)=x2(n)-x(n+1) c) y(n)=x(-n)+x(2n-1)
For matrices A_ij with i = j, the diagonal elements are made zero by replacing diagonal elements by zero. First, two matrices with the same k value are horizontally concatenated and then the matrices obtained after the horizontal concatenations are vertically concatenated to produce N1 - N2 adjacency matrix A. The numbers N1 and N2 represent the numbers of nodes of type 1 and type 2 respectively. The value of N1 is obtained by rounding the product of the network size N and the node proportion q1 of type 1 to the nearest integer. Then the remaining number of nodes N-N1 is the number N2 of nodes of
At a level of significance of 0.05 the researcher is accepting a possible type I error 5 cases out of a 100 and 95 cases out of 100 a true null hypothesis (Loiselle et al., 2011). Step 3: Selection of one-tailed or two-tailed test The selection for a one-tailed or two-tailed test is not required for a Chi-Square for independence test (Salkind, 2013). Chi-Square test has both variables that are of a categorical level of measurement therefore, there is no direction (Salkind, 2013). Step 4: Excel output of test statistic The output for the Chi-Square for independence test is provided in the Statistic assignment seven outline and obtained from an SSPS output. Please refer to Statistics assignment seven to see the SPSS output for the Chi-Square tables.
The third step is identifying the limiting reagents for each test. It can easily be classified by the smallest number. The higher number will be the excess. 4. After identifying reagents and finding the theoretic yield, it’s possible to find the excess reagent mass and number of moles for each test.