During the flame test, the cation was able to be identified by the color of the flame it produced from my previous tests results I was able to conclude that unknown solution A’s cation was calcium and unknown solution B’s cation was copper. During the precipitate test, halide, the anion wasn’t able to be identified but we do know that it is a halide ion. From previous results we can assume that unknown solution A’s anion is chloride and unknown solution B’s anion is sulphate. During the precipitate test, sulphate, the anion was able to be identified by the type of chemical reaction it produced from my previous results I can conclude that unknown solution A’s anion was calcium and unknown solution B’s anion was
How is a daguerrotype fixed? After being developed in a mercury fume box, sodium thiosulfate is used to remove the remaining unexposed silver compound. Then the plate is guided with gold chloride after being rinsed with distilled water. Who made the first image? The earliest known surviving photograph made with a camera was taken by Joseph Nicéphore Niépce in 1826/7.
Afterward, filter this solution to obtain the calcium carbonate. Finally, heat the calcium carbonate at 248 degrees Fahrenheit to dry it out. Heat the calcium carbonate to 1,832 degrees Fahrenheit to get CaO. The following equation shows this reaction: CaCO3 -> CaO + CO2. Store the lime into a closed container and add aluminum.
Although most of our data supports our hypothesis, some of our data contradicts our hypothesis. For the radiation experiment, most of the trials support our hypothesis because when we microwaved the seeds 30-60 seconds, barely any of the radish seeds grew. On the contrary, in trial two, when we microwaved them for 30-60 seconds, most of the seeds grew. For the acidity
The SIM tube was first inspected for black precipitate indicating sulfur reduction and cloudiness around stab line for motility. Kovacs reagent was added in the tube a red color change in the alcohol layer. Red which also indicated is was positive for indole production. Methyl Red is used to determine if an organism is capable of performing a mixed acid fermentation. Methyl Red were added to MR test tube.
Formula 2: % Component= 100% component mass (g) sample mass (g) Procedure First, we measured out the evaporating dish to find the mass. Then we added around 3 grams of our sample (2.832g exactly). Next we added the isopropyl alcohol to dissolve the Benzoic Acid. We filled the evaporating dish, stirred, and then decanted the sample into a 140mL beaker with a stirring rod. This
What happens during this stage of the experiment showing visual change and acidic reaction that is becoming weaker as the molecules are deprotonated to become equal parts within the solution. So by finding the molar ratios we learned that acid to base are 1:1 when equally balance or concentrated. So therefore concentrations at stoichiometric end point can be found by plugging in the values to formulate a dilution equation as seen above. When expressing calculations I found when doing the Titration of an Unknown Acid I discovered that with .1 mL of Sodium Hydroxide and at least 10 mL Anthocyanin as/or acetic solution will produce an average molarity of 0.9 or higher according to my
He called this bacteria destroying mold penicillin. This was the world 's first antibiotic and it was created by accident. However Fleming was unable to purify and stabilize it, someone eventually would. He was awarded Nobel prize in 1945 for his discovery. (Alexander Fleming Biography) Unlike Alexander Fleming, Paracelsus made advancements with chemistry and toxicology.
What Kayden and I did first is get on EV3 robot out and connect it to bluetooth, after that we did that we started to think about how we were going to find out how many rotations that we were going to need to get it from start to finish. So, we got a ruler and since we already knew one rotation was equal to 7 inches we guesstimate that it would be about 5 rotations. When we tried it is was still a little short of its goal, so we added 0.5 to it and it barely went over its goal. Finally we took away 0.08 and tried it and it landed exactly on its target. So our final solution was 5.42 rotations at 27% would get us from the start to the finish exactly.
As relayed in Table 1, the results concluded that the only molecules to react and form a precipitate were 1-chlorobutane and 1-bromobutane. 1-bromobutane formed a precipitate first, after two minutes and eight seconds. 1-cholorobutane did not for a precipitate until after heat was applied after seven minutes and fifty-one seconds. 2-cholorbutane, 2-bromobutane, and tert-butyl-chloride did not react at all during the course of the experiment. 1-bromobutane was expected to react first, followed by 1-chlorbutane.