Benzyne Formation and the Diels-Alder Reaction Preparation of 1,2,3,4 Tetraphenylnaphthalene Aubree Edwards Purpose: 1,2,3,4-tetraphenylnaphthalene is prepared by first producing benzyne via the unstable diazonium salt. Then tetraphenylcyclopentadienone and benzyne undergo a diels-alder reaction to create 1,2,3,4-tetraphenylnaphthalene. Reactions: Procedure: The reaction mixture was created. Tetraphenylcyclopentadienone (0.1197g, 0.3113 mmol) a black solid powder, anthranilic acid ( 0.0482g, 0.3516 mmol) a yellowish sand, and 1,2-dimethoxyethane (1.2 ml) was added to a 5-ml conical vial. A spin vane was added and a water-jacked condenser was attached. Isopentyl nitrite (0.06ml, 0.045 mmol) was dissolved in 1,2-dimethoxyethane (0.50 ml) in a 3-ml conical vial and caped to prevent loss by evaporation. Running the reaction. The mixture in the 5-ml conical vial containing the tetraphenylcyclopentadienone and anthranilic acid was heated on an aluminum block to 140° C. Once the mixture started to boil the prepared mixture of isopentyl nitrite was added to the 5-ml conical vial through the top of the condenser using a pasture pipette. The solution continued to boil for 25 more minutes until a …show more content…
The crude tetraphenylnaphthalene in a 25-ml Erlenmeyer flask and dissolved in boiling isopropyl alcohol (12 ml). The solution was cooled to room temperature and further cooled in an ice bath for 30 minutes. Crystallization of colorless crystals occurred. The product was collect in a Hirsch funnel and washed with isopropyl alcohol. The solid was left to dry over the weekend. The following lab period the solid was weighed (0.0483 g) and percent yield was calculated (65.5%) with the limiting reagent being tetraphenylcyclopentadienone. The melting point was determined. The first melting point was 204-204.9 °C and the second melting point was 215.6-215.9°C. Finally, an infrared spectroscopy was obtained for the
A hot plate was placed under the ring stand. 50 mL of 3.0 M NaOH in a 250 mL beaker and a stir bar was placed in the beaker. The beaker with NaOH was placed on the hot plate and 3.75 grams of NaAlO2*5H2O was placed in the beaker. The temperature probe was placed in the beaker with the solution, not touching the bottom of the beaker. The solution was heated and stirred till the solution dissolved.
Leave the boiling tubes for 1 hour to allow the precipitate formed to
From the data obtained in Tables 1-3, we were able to plot multiple graphs using excel. These graphs give a better representation of the data as seen in Figures 1-9. It can be seen that each figure shows a slight increase in CO2 production, which signifies a possible change in metabolic rate. Figures 4 and 7 show a relatively large change between the control and fox urine. The changes in slope between theses two are 0.0267 for Figure 4’s slopes and 0.0192 for Figure 7’s slopes.
Suppose you need to find the fractional European call and the fractional European put options. Let the Hurst parameter be $H=0.85$, the $\sigma=0,25$, $r=0.10$, $S_{fbm} = 100$, $K = 95$, we have \begin{eqnarray*} d_1^{fBm} & = & \frac{\ln{\frac{S}{K}} + \frac{1}{2}(r( T - t) + \frac{(1)\sigma^2{( T^{2H} - t^{2H})}}{2})}{\sigma{\sqrt{T^{2H} - t^{2H}}}}\\ & = & \frac{\ln(\frac{105}{100}) + (0.10(0.25 -0) + \frac{(1){0.25^2}{0.25^{2(0.85)} - (1)0.25^{2(0.85)}}}{2}}{(0.25){\sqrt{0.25^{2(0.85)} - 0}})} \end{eqnarray*} we obtain $d^{fBm}_1= 1.0558$. We find in the normal distribution that $N(1.0558)= 0.8544$ and $N(-1.0558) = 0.1456.$
Testing phase finds differences in positive/negative documents by the centroid obtained in training phase by ranking each of them. The simple way to estimate similarity between documents and centroid by summing weights of patterns which are in the documents. VII. Experimental Results To determine accurate measures of similarity or difference between documents you depict results by graph pattern and table pattern. The experimental setup consists of relevant documents that you termed as positive and negative documents .i.e
Nonetheless, the light yellow solid was purified by using the recrystallization technique. The formation of o-nitroacetanilide is inevitable and in order to eliminate it, 95% ethanol is used as the solvent of choice. The ortho isomer is soluble in the cold alcohol solution whereas p-nitroacetanilide in insoluble. As a result, the ortho isomer remains in the liquid solution and the final product, the p-nitroacetanilide is isolated with a final vacuum
Vacuum filtration was performed on the crude product, then it was recrystallized for purification. Melting point analysis was conducted on the recrystallized product to determine its identity. 3. The three possible mechanisms in this experiment were syn-addition
Glacial acetic acid and acetic anhydride were added to the mixture while refluxing, which converted the lime colored solution into a clear mixture. The flask was cooled in an ice bath and the solution
• Write down the highlighted numbers. Do you observe a pattern? • Does the pattern grow? What is the reason for this? • Write down the last number (say 53).
Abstract: The purpose of this experiment was to identify given Unknown White Compound by conducting various test and learning how to use lab techniques. Tests that are used during this experiment were a flame test, ion test, pH test, and conductivity test. The results drawn from these tests confirmed the identity of the Unknown White Compound to be sodium acetate (NaC2H3O2) because there were no presence of ions and sodium has a strong persistent orange color. The compound then will be synthesized with the compounds Na2CO3 and HC2H3O2 to find percent yield.
Results The data obtained from the experiment had undergone statistical analysis using t-tests and the results were recorded in Figure 1.0 and Figure 1.1 above. According to the data obtained in Figure 1.0, the p-value is less than 0.05 in all 5 treatment solutions. It is also shown intensity Figure 1.0, the calculated t-value of each concentration of NaHCO3 in each treatment is greater than the critical t-value.
Nevertheless, the latter is not used in this experiment since it is very reactive and extremely flammable. On the contrary, NaBH4 is relatively mild and it can be used with protic solvents. In this manner, 1.507 grs of the ketone 9-fluorenone were mixed with 30.0 ml of 95% ethanol in a 125 ml Erlenmeyer flask. The bright yellow mixture was stirred during 7 minutes until all the components were dissolved.
The objective of this experiment was to use an aldol condensation reaction to synthesize 3-nitrochalcone from 3- nitrobenzaldehyde. This was accomplished with a Diels-Alder reaction that utilized 3-nitrobenzaldehyde, acetophenone, ethanol, and sodium hydroxide. The mechanism for the synthesis of 3-nitrochalcone is presented in Figures 1 and 2. The alpha carbon on the acetophenone is deprotonated. This is followed by the attack of the alpha carbon anion on the carbonyl carbon on the 3-nitrobenzaldehyde.
Experiment 2 Report Scaffold (Substitution Reactions, Purification, and Identification) Purpose/Introduction 1. A Sn2 reaction was conducted; this involved benzyl bromide, sodium hydroxide, an unknown compound and ethanol through reflux technique, mel-temp recordings, recrystallization, and analysis of TLC plates. 2. There was one unknown compound in the reaction that was later discovered after a series of techniques described above.
Introduction Chevron Phillips Chemical Company is the major producer of Cyclohexane. This successful company hoses the three largest cyclohexane plants in the world. Many are puzzled by how the production of cyclohexane seems to have become stagnant. Perhaps this is due to the cost of benzene increasing or the demand increasing. Through thorough investigation, the answer to this question and many more can be answered.