Volume Lab
In this four parted lab the purpose is to use measurement and water displacement and calculations to find the volume of various objects.
Part A questions were how much drops of water were needed to make 1mL the original hypothesis made was ten drops however this was proven wrong once the data in which twenty drops of water rose 10 mL of water to 11 mL of water, nineteen to rise from 11 mL to 12 ml, and finally eleven drops of water to rise from twelve mL to thirteen mL. Once the average was calculated which was 16.6 drops, which meant on average that's how much it needed to make one mL. By subtracting from the average with the hypothesis the hypothesis was revealed to be 6.6 drops off.
Part B questions were based on water displacement. In which the question was how much was the difference between 20 mL of water and 3 marbles. To figure out the answer knowing how much water was in the cylinder is before adding the 3 marbles so once the marbles were added you can subtract the original volume from the new volume. In this case we know that the cylinder held 20 mL of water so upon adding all three which rose it to 28 ml all we had to do was 28 mL - 20 mL which equals 8ml in difference which can also be translated as to what the volume for 3 marbles was.
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Because of the question it asks to find the volume of any box. The chosen box in the lab measurements was then inputted into the formula 31 cm x 21 cm x 12 cm which resulted in the volume being 7812
Prelab week 1 Calculations Preparation of 1.5μmol/L mixed low-level standard dilution 150μmol/L × V1=1.5μmol/L × 10ml V1=(1.5μmol/L×10ml)/(150μmol/L)=0.1ml Conversion of milliliters to microliters (0.1ml×1000)μL= 100μL Preparation of 3μmol/L mixed low-level standard dilution 150μmol/L × V1=3μmol/L × 10ml V1=(3μmol/L×10ml)/(150μmol/L)=0.2ml Conversion of milliliters to microliters (0.2ml×1000)μL= 200μL Preparation of 3μmol/L mixed low-level standard dilution 150μmol/L × V1=7.5μmol/L × 10ml V1=(7.5μmol/L×10ml)/(150μmol/L)=0.5ml Conversion of milliliters to microliters (0.5ml×1000)μL= 500μL Preparation of the blank samples The volumetric flask will be filled to the mark with 150μmole/L of stock solution to act as blank (reference). Additional two blanks will
Therefore, the null hypothesis H0: µ ≥ 16 ounces is rejected, leading to the mean being less than sixteen ounces. Step 4: The following is discussion based on the conclusion of the test: If it is concluded that there are less than sixteen ounces in a bottle of soda, create a hypothesis on three possible causes. Followed by the suggestions of the strategies to avoid the deficit in the future.
Fill beaker with water Use the disposable pipette to place water in the graduated cylinder until the unidentified object would be completely submerged in water Record what the measurement of water in milliliters before placing the unidentified object into the graduated cylinder Gently place the unidentified object into the graduated cylinder Record the measurement of the water in milliliters after placing the unidentified object into the graduated cylinder Subtract the measurement of water in milliliters before placing the unidentified object into the graduated cylinder from the measurement of the water in milliliters after placing the unidentified object into the graduated cylinder, this is the volume of the unidentified object Record the volume (the answer you got in step 10) of the unidentified object in the data table Weigh the unidentified object on the scale, this is the mass of the unidentified object Record that number in the data table Calculate the density of the object by dividing the mass by the volume and rounding it to the proper significant figure, Record the density of the unidentified object in the data table Repeat the lab 2 more times and with each experiment record the data in the chart under the correct trial number corresponding with the correct
In conclusion, the dime was able to pull it off and hold more drops than the penny. My hypothesis was incorrect because, I thought the penny would hold more drops than the dime because the penny was bigger and I thought it would absorb more. But the dime held more. Preston and I even ran the tests or investigation three times for each coin. The one question I had was ,what if the penny was stacked 1 time and the dime was stacked one time,would it make a difference ?
In the lab “All That Glitters” the objective that was focused on during the lab was calculating the density, volume and mass of various substances. The method that was used in finding the volume of the samples is called the displacement method. This is a process where the volume of the water in the graduated cylinder is calculated before and after the sample is placed. In this lab, the goal of the experiment was to identify and come to consensus about what the unknown substance might be. For this experiment, the required materials were ten pre and post pennies, unknown sample, graduated cylinder, weigh boat, water, paper towels and a weighing scale.
Next, I removed the water and the quarter from the graduated cylinder and poured 50 mL of water again. I repeated this until I got results for all three coins. To find the volume of each coin, the formula I used was volume of water and coin - initial volume of water ( 50 mL ). To find the density, I divided the mass and the volume of each
A possible error could have occurred while measuring the mass of the individual pennies, while the pennies were dry and were allowed be measured individually, we did not clean or thoroughly examine each penny for flaws or cleanliness. This may have slightly affected the mass of the penny. Another possible source of error could have been measuring the volume of the water and the pennies in the water. Since we were using a measurement device the was accurate only to whole numbers, we had to make an educated estimate between the values provided by our measuring device. While these measurements are very close to the actual value a more accurate measuring device would have given more significant figures.
The bottom of the tank is a curved surface. What is the volume of both tanks if the radius of tank #1 is 15 feet and the height of tank #2 is 120 feet? You must explain your answer using words, and you must show all work and calculations to receive credit. The first step would be to use the volume of a cyclinder again since the tanks are the shape of a cylinder.
This experiment demonstrated water density because the cold water moved beneath the hot water, because it is denser. 5. Was your hypothesis supported or refuted? Explain.
We then took the potato cores out of the empty beaker and dabbed them lightly with paper towel to get any excess solution off. We did this quickly and following it we then took the mass of all four potato cores again and recorded
It was impossible to accurately measure the volume of liquid at any given moment, as the meniscus was moving side to side. Secondly, the distillation was ended while there was still liquid in to round bottom flask. The composition and volume of this liquid were unaccounted for in the calculated
Place the the beaker onto a hot plate that is on a low heat setting (about setting 3). Every 5 minutes for 20 minutes, measure the circumference of the balloon and record it in Data Table A. You can measure the circumference of the balloon by looping a piece of string around it then using a ruler to measure the string’s length. Record the data in the data
The hypothesis we came up with for this project was that in the distilled water there wouldn't be no change in the potato, we wouldn’t see a gain or loss with the water sitting in the beaker. The beaker with the 30% Sucrose and Distilled water we predicted that there was going to be weight gain to the potato. And for the distilled water with the 30% sucrose and we predicted weight loss. But the results came out to be the first bag content being isotonic the second bag came out to be hypotonic and lastly the result came out to be
Thus the measurements will repeat for each experiment, where the paper cup’s height from the ground varies in each
That caused a new initial reading of NaOH on the burette (see Table1 & 2). The drops were caused because the burette was not tightened enough at the bottom to avoid it from being hard to release the basic solution for titrating the acid. The volume of the acid used for each titration was 25ml. The volume of the solution was then calculated by subtracting the initial volume from the final volume. We then calculated the average volume at each temperature.