4.1.6 Flip ops as Counters As can be seen from Figure 4.7 and Figure 4.8, a T-FF can be implemented using a D- FF feeding back the negate output /Q to the input D. The input clock to be divided is then provided at the CLK input. Cascading n T-FF stages as shown in Figure 4.8, it is 26 possible to divide the input frequency by a factor of 2^n . Based on current requirement Figure 4.7: FlipFlop of IC, size and availability and operating temperature, the rst combination which is the cascade of divide-by-4, divide-by-10 and divide-by-10 is chosen. The ip op as divide by 4, 10, 40 etc have been simulated with ADS. A divide by 4 ip op employing D ip op is shown next in Figure 4.8. The simulation plot for divide-by-4 (Figure 4.9) is shown Figure 4.8: Cascaded ip ops …show more content…
The output frequency of divider gets divided by 4 ie 1.05 GHz. Since for practical realization, one cannot directly give RF signal directly to frequency divider input pin to avoid huge impedance mismatch. Use of microstrip line[4] in the ter- mination allows for smooth transition of signal from SMA probe to Microstrip and further 27 Figure 4.10: Divided output of divide-by-4 ip op to frequency divider pin. The schematic of divide-by-4 with microstrip is shown below in Figure 4.11. The width and length of microstrip is calculated from line calculator tool of ADS for the following: Substrate thickness-0.762 mm Metal thickness-0.035 mm Loss tangent-0.0015 Dielectric constant-2.55 Figure 4.11: Divide-by-4 ip op using microtrip line With microstrip lines inserted at input and output of divider ip ops, the output frequency from divider, for an input frequency of 5GHz is 1.234 GHz, more
Such as, 2 2 2 , , r s s r r r s r r r L L R L R M L L M L PM L R Where rd s i u , , and r : are respectively, the stator voltage, stator current, rotor flux and rotor speed. The indices d, q indicates a direct and quadrate index according to the usual d-axis and q-axis components in the synchronous rotating frame. M L L R R r s r s , , , , and : are respectively, stator and rotor resistance, stator and rotor inductance, mutual inductance and total leakage factor. P, J, TL and f: are respectively, the number of pole pairs, the rotor inertia, the load torque and the friction coefficient.
Dr. Colleen Winters – BIO 655 Vishall G. Kaistha TITLE: “Recombination-Directed DNA Repair Promote Homologous Stimulating Transcription of Genes That That Preserves Genomic Integrity by MEN1 Is a Melanoma Tumor Suppressor”.
Resistors 5. Coaxial cables 6. Alligator lines Procedure: 1. Change the frequency of the signal to examine the circuit shown in Fig.1. 2.
Results The lab experiment was done in two parts, one with the NAND, NOR, XOR and Hex Inverters and the other with a 7483 full adder gate, both will verify the truth table when two input bits and a carry are added together. The circuits were built by examining the 1 bits through a K-Map to create a Boolean expression for the sum and carry. The Boolean expression for the sum was A⊕B⊕C and the carry as AB+BC_in+AC_in. From these two expressions, we notice that we must use two exclusive-ORs gates in the sum inputs for A, B, and C. For the sum, we have to use NOR and NAND (the only available gates from the lab manual).
For most sequences at position 4 and 5 we observe only the nucleotides G and T, respectively. There may be rare cases where other nucleotides may also be found. To consider such observations, we need to do a process called additive smoothing or Laplace smoothing to smooth the categorical data. [9] In this case, we add 4 sequences: AAAAAAAAA, CCCCCCCCC, GGGGGGGG, TTTTTTTTT.
I need to find the area of rectangle ABCD. I know that ABCD is a rectangle with diagonals intersecting at point E. Segment DE equals 4x-5, segment BC equals 2x+6, and segment AC equals 6x. I predict that To find the area of rectangle ABCD I need to find out the base and height of the rectangle. The first step is to find what x equals. Since I know the intersecting line segments AC and DB are congruent that means when I times the equation 4x-5 for segment DE by two it will equal the equation 6x for segment AC.
4.) I noticed that there is a relationship between the ionic radius and the atomic number of the representative elements in Group 1A. The higher the atomic number, the bigger the ionic radius is. So, while hydrogen has an atomic number of 1 and Francium has an atomic number of 87, it is safe to assume that FR has a higher ionic radius. This is true; the ionic radius for Hydrogen is 0.012, and for Francium, it is 0.194.
Perhaps many are confused about the existing commands linux, this time I will discuss about the linux basic commands used along with examples of its use. 1: Seeing identification (id and group id number) $ Id 2: Looking the calendar date of the system a. Looking at the current date $ Date b. See calendar $ Cal 9 2002 $ Cal -y 3: Seeing the machine identity $ Hostname
7.7.1 Data Owners 1. One whose going to access files, one who owns file, who requires his data to be secure. 2. Data owners are responsible for encrypting the data by generating private key. MMCOE, Department of Computer Engineering, 2015-2016 26 Regeneration of code based cloud storage 3.
Goal In this lab the goal was to set GPOs and PSOs for the Windows Server 2012 box that we had set up in the previous lab. Group policies allowed us to manage the settings and configurations on the domain bound machines as well as fine tune the password complexity requirements. I had already set up multiple GPOs for my machines prior to starting this lab, so all I really had to do was add in any additional GPOs as well as create the Password Setting Objects. Windows Server 2012:
First Name_Siamrjeet__ Last Name _Singh_ Student #_n01142134__ LAB 4 CONFIGURING FILE AND SHARE ACCESS No-Penalty Due Date:. 7 Days from your lab session Submissions more than 5 days late receive a mark of zero.
1. Goal The objective of this lab was to create a Windows 2012 Datacenter Virtual Machine. On this virtual device, we were tasked with installing DHCP, DNS, and Active Directory services. This was very similar to lab 2 in that all of the core services had to be installed on this one device as with our RHEL7 server previously.
Goals of the Lab This lab has many different overall goals that are meant to introduce us to the challenges and procedures of building a preliminary enterprise environment from the ground up. Each task has it’s own set of goals that expose us to important areas of system administration in this type of environment. The lab first introduces us to installation and configuration of an edge routing device meant to handle all internal network traffic between devices, and allow access out to an external network, in our case the Internet. The lab then introduces installation of an enterprise Linux distribution, Red Hat Enterprise Linux 7, which will be used as the main Linux based server in our enterprise environment.
2.7 Observations from GMPCS Model Based on the above model, several observations can be made as follows. Observation_1: According to an interoperability feature between CSPs, a storage service will be hosted over a pool of resources that are in different geographical locations. Furthermore, different technologies, protocols, and security strategies are applied by each CSP within its datacentres to facilitate managing an environment to protect both resources and data. The technologies and strategies, therefore, might be disparate in terms of efficiency, and the type of storage network or storage system might be varied as well.
1a. What is a cell? A cell is the basic unit of life. 1b.