862 Words4 Pages

The simplest data searching algorithm is sequential search. In this method, we insert data into the tables in any order. In order to search for an entry in the table, we perform searching starting from the first element and perform the action sequentially until a matching entry is found or end of table is reached. In this case, the best-case performance is O(1), since matching entry is obtained in the first searching itself. However, the worst-case scenario occurs if the element to be searched is not in the table. When such a condition occurs, we need to search the whole table to conclude the element is not in the table. If there are ‘n’ number of elements in the table, the worst-case performance for sequential search will be O(n). As n becomes
*…show more content…*

Let U = {0, 1,..,m-1} be the universe of ‘m’ keys from which an application draws its keys. If this universe of keys is reasonably small and if no two elements have the same key, then we can use an array to store the keys. Each slot in the array corresponds to a key in the universe U. Hence there will be ‘m’ slots in the array or Direct-address table, corresponding to each element in the universe. We can use the key value as index of the array to directly access the array location to see whether an element is present or not. This method works good for small universe of keys since the dynamic subset of keys that the application draws from the universe might not contain all the keys. This lefts a lot of unused slots if the universe is large and subset of keys drawn are small. Also if the universe is large, it would be difficult to have a large table of size |U|, since we might encounter space issues constrained by the memory size of the machine. However, this method is having the advantage that the worst-case computational complexity to check if an entry is present in the table is only
*…show more content…*

This helps us to reduce the storage requirements considerably if the universal set is large and subset of keys is small. The storage requirements is bounded by Θ(|K|), whereas average-case searching time is O(1). In this scenario, instead of having |U| slots where element with key k, is stored at slot k, we are hashing the number of slots to |K| where |K| < |U| and store all the elements into these |K| slots using a mapping function called hash function. Hash function, h, is used to compute the slot for key, k, and element is stored in slot h(k). In other words, hash function h maps the universe U of keys in to hash table T[0,1,…,m-1]. Hashing reduces the range of array indices that need to be handled to m

Related

## Nt1330 Unit 9 Final Paper

865 Words | 4 Pages1. Planning Before you want to jump right into planning, you want to meet with your client to talk about the project, you want to obtain certain information so that it can help you learn more about the project and whether or not the project should go ahead. Once you accept doing this project, you want to make sure that the client knows the requirements you’re looking for and whether they will meet your standard. For example, your payment estimates for future stages of the project.

## Nt1310 Unit 9 Final Paper

1018 Words | 5 Pages3.3. Frontier molecular orbital The electronic structure of the doped fullerene interacting with glycine compared to pure fullerene C20 has been calculated with density functional theory using the B3LYP/6-31G basis set. The molecular orbital theory, the relative chemical reactivity of a molecular system can be estimated using HOMO and LUMO energies and overlaps of molecular orbital [18-20]. The electronic transition from the HOMO to LUMO are mainly derived from the electron density transfer n orbital to p* orbital.

## Nt1310 Unit 3 Assignment 1 Data Analysis

404 Words | 2 PagesAssign. 3 Andrew McConnon 13349871 1. In terms of specification of the framing in relation to the classic Ethernet protocol, it is specified by IEEE 802.3-2012.

## Pt1420 Unit 6 Algorithm Report

150 Words | 1 PagesHash queries. To respond to H queries, C maintains a list of tuples called the H-list. The list is initially empty. When A issues a hash query for a conjunctive keyword W_i={W_1 ||

## Pt2520 Unit 3 Datatype Analysis

643 Words | 3 PagesSome of the MS SQL Datatypes Affected By Compression Some of the datatype that don’t yield any row level compression benefit are tinyint, smalldatetime, date, time, varchar, text, nvarchar,xml. MS SQL Server Page Compression can be applied to tables, table partitions, indexes and index partitions. This compression technique can be viewed as an enhanced version of Dictionary Encoding discussed in [4]. The following two figures illustrate the effects of page compression on an uncompressed

## Nt1310 Unit 4 Component Analysis

331 Words | 2 PagesMultilinear principal component analysis (MPCA) is a mathematical procedure that uses multiple orthogonal transformations to convert a set of multidimensional objects into another set of multidimensional objects of lower dimensions. There is one orthogonal (linear) transformation for each dimension (mode); hence multilinear. This transformation aims to capture as high a variance as possible, accounting for as much of the variability in the data as possible, subject to the constraint of mode-wise orthogonality. MPCA is a multilinear extension of principal component analysis (PCA).

## Nt1310 Unit 3 Assignment 1 S-Csp

343 Words | 2 PagesThe owners or users are those who would like to outsource their data in public cloud to S-CSP then it access that stored data later whenever required. In this system of storage, in support of Deduplication method, a user uploads only unique single data copies/files although it is impossible for them to upload any duplicated data files. In this system, each of user who has concerned with set of level of privileges i.e. privilege levels (e.g. upload, download) is the settled down in the system. Each file is said to be safer or protected by having both the keys named CE key and PE key. These keys used for understanding the Deduplication with user’s authorization with differential privilege levels.

## Nt1310 Unit 6 Segression Analysis

164 Words | 1 Pagesif((shmid = shmget(key,sizeof(shared_data), IPC_CREAT|IPC_EXCL|0666)) = = -1){ printf(" Shared memory segment exists ");

## Cmm570 Unit 1 Assignment

495 Words | 2 PagesCMO570 Report 1. Item and Customer data are stored in a hashPublic Map getCustomers() { return customers;} Public Map getItems(){return items;} When you search for a key/value pair in a hash table you can go directly to the location that contains the item you want, you rarely have to look at any other items, you can just look at the key and go directly to the location where it is stored. Hash maps allow the execution time of basic operations, such as get() to remain constant even for large sets. HashSets and HashMaps are implemented using a data structure known as a hashtable. ‘The concept of a hash table is a generalized idea of an array where key does not have to be an integer.

## Nt1310 Unit 2 Regression Analysis

599 Words | 3 Pagessubsection{Recommending Unexpected Relevant Items} Once the forgotten items have been identified, we need to distinguish relevant ones from the rest. Given user taste shifts, as well as the changes in the system as a whole, not all unexpected items remain relevant, and consequently useful for recommendation. The key concept to identify relevant items is the extbf{relevance score} of the items at each moment. We propose four strategies to define the relevance score of each unexpected item.

## Nt1310 Unit 1 Linear Study

591 Words | 3 PagesThere are several things that I appreciate from this class: \begin{enumerate} \item[1] \[ u_t=Ku_{xx}+Q\] To solve the above equation most of the time (For the sake of simplicity) we set $K=1$. This is how I solved similar type of equations in my undergraduate study. But you explained the importance of K. You said, for a small rod, K is not that important as in airplane (K is a material property). I will never forget this. I'm really interested studying PDE and to see the world through mathematics and then work for a new invention.\\ \item[2] You have introduced short and sweet ways of simplifying.

## Nt1310 Unit 3.4 Data Analysis

2265 Words | 10 Pages3.4 Displaying meaningful results Plotting points on a graph for analysis becomes difficult when dealing with extremely large amounts of information or a variety of categories of information. For example, imagine you have 10 billion rows of retail SKU data that you are trying to compare. The user trying to view 10 billion plots on the screen will have a hard time seeing so many data points. One way to resolve this is to cluster data into a higher-level view where smaller groups of data become visible. By grouping the data together, or “binning,” you can more effectively visualize the data.

## Nt1310 Unit 3 Term Paper

831 Words | 4 PagesVP networks are the best solution for the company. Because it will improve productivity, extend geographic connectivity and simplify network topology with ensuring security, reliability and scalability. Also, VPN can be very convenient not like other methods e.g. leased lines that can get very expansive. There are two types of VPN: Remote-Access and Site-to-Site.

## Nt1330 Unit 3 Data Encryption Algorithm

85 Words | 1 PagesThis algorithm consist of series of substitutions and permutation on each block of 64 bit message, which is then EX-OR with input. This process is repeated 16 times. Due to 16 rounds of DES algorithm it is more secure . Very high throughput is achieved using this

## Procedural Programming Assignment

1009 Words | 5 PagesITPP111- Procedural Programming Assignment. Name: Bradley barker: Student Number: RJMMLYX21 Question 1 1.1. Computers store data of all sorts in a binary number format.

### Nt1330 Unit 9 Final Paper

865 Words | 4 Pages### Nt1310 Unit 9 Final Paper

1018 Words | 5 Pages### Nt1310 Unit 3 Assignment 1 Data Analysis

404 Words | 2 Pages### Pt1420 Unit 6 Algorithm Report

150 Words | 1 Pages### Pt2520 Unit 3 Datatype Analysis

643 Words | 3 Pages### Nt1310 Unit 4 Component Analysis

331 Words | 2 Pages### Nt1310 Unit 3 Assignment 1 S-Csp

343 Words | 2 Pages### Nt1310 Unit 6 Segression Analysis

164 Words | 1 Pages### Cmm570 Unit 1 Assignment

495 Words | 2 Pages### Nt1310 Unit 2 Regression Analysis

599 Words | 3 Pages### Nt1310 Unit 1 Linear Study

591 Words | 3 Pages### Nt1310 Unit 3.4 Data Analysis

2265 Words | 10 Pages### Nt1310 Unit 3 Term Paper

831 Words | 4 Pages### Nt1330 Unit 3 Data Encryption Algorithm

85 Words | 1 Pages### Procedural Programming Assignment

1009 Words | 5 Pages