I have been asked to use Ubuntu? One comparison between windows and linux is that Linux is a lot freer than windows because windows are restricted. Another comparison is windows are a lot safer because if something breaks you get paid support whereas on Linux you do not have any support. My experience with Linux is not much as I am entirely a windows user. Task 1: I have been asked to open a terminal (the terminal allows me to access to the command prompts) and show which directory I’m in, and then navigate to the home directory, to make shore I’m in the correct one I type cd (change directory). I think it will take me to the home directory and I will do this by typing in cd ~. I think this will work because cd ~ is what you type to get to the home directory. This print screen shows me going to the home directory. I have tested it and it worked but it wasn’t the most efficient as you can just press …show more content…
I will do this by typing mkdir before the name desired. Mkdir just basically creates the file. I think it will create a file named A452. This print screen shoes me doing the task and proof of it working as I have listed and opened the A452 directory. I have tested it as you see on the print screen and it was the most efficient way. I thinki it went well because I did not mess up the commands and it could be improved by reducing steps. Task 6: I have been asked to navigate to my new directory (A452) and type touch (Mitchelltextfile) and explain what happened. I think it will create a file named (Mitchelltextfile) I think I will do this by typing what it says in. I think it will work because it has text file in the name. This print screen shows me doing the task and I have tested it which proves I thought correctly as it now list the file. It was the only way I saw so it was the most efficient. I think it went well because it was
For example; M = 4 bits, N = 16 bits If P(j) = 1 (Propagation); then Group(j) will be skipped X(j): m-bits of group (j) Y(j): m-bits of group (j) Cin(j): Carry in to group(j) Cout(j) = Cin(j+1): Carry out of group(j) = Carry in to next group(j+1) (j): Group(j) consisting of m-bits numbers to add Fig 5.14: Carry Skip Adder Block diagram Table 5.3: Carry out Cases Table Case Xi Yi Xi + Yi Ci+1 Comment Ci = 0 Ci = 1 1 0 0 0
where $x_i,i=1,2, cdots ,n$ are the states, $underline{x}_i=[x_1,cdots,x_i]^{T} in{R}^i$, $i=1,2, cdots ,n $, $uin {R}$ is the input, and $f_i(cdot)$,$i=1,2, cdots ,n $ are the unknown smooth nonlinear functions which satisfy the global Lipschitz condition. It is assumed that the output $y(cdot)$ is sampled at instants $t_k,k=1,2, cdots ,n$, which represent the sampling instants. $T=t_{k+1}-t_k$ is the sampling interval which is a positive constant. The output signal is available for the observer at instants $t_k+ au_k$, where $ au_k$ are the transmission delays and satisfy $0 leqslant au_k leqslant T$. egin{remark} label{rem:1}
%addcontentsline{toc}{section}{Activity 5.4} section*{Activity 5.4} egin{enumerate} item I divide the class into pairs. item I gave the learners the following exercises in Grade 10 (Set 7).\ extbf{Simplify the following expressions:}\ egin{enumerate}[(a)] egin{minipage}{0.60 extwidth} item $frac{4m}{n^{-3}} imes frac{3}{10m^2 n^2}$ \ \ item $frac{2^x + 2^{x+1}}{2^x}$ \ \ item $frac{3^a - 3^{a-1}}{3^{a+2} - 3^{a+1}}$ \ \ item $frac{5^x.2^x}{10^x}$ \ \ item $frac{7^{x+1} - 7^{x}}{6.7^{x}}$ \ \ item $frac{6^x.3^{-1}}{36^{-x+1}}$ end{minipage}% egin{minipage}{0.60 extwidth} %egin{enumerate}[{11.} ] item $frac{5^{x+2} - 5^{x+1}}{5^{x+1}}$ \ \ item $frac{3^x - 3^{x-2}}{8.3^x}$ \ \ item $frac{2.2^{n+1} - 2^{n}}{3.2^{n-1}}$ \ \ item
You can use one of the following: which command type command Searching all over the filesystem. (... not a preferred way. Instead use type or which) We will use "type" command to determine about the "grep" and "cd" commands: For external commands, the command displays the physical path.
the root directory of the file below. Be sure to add two backslashes in-between each component. String rootDirectory = "C:\\Users\\Jake\\Desktop"; //Enter the name of the file you would like to locate in the quotes String nameOfFile = "Hello.txt"; Chapter19Program9Roth findFile = new Chapter19Program9Roth(); File newFile = new File(rootDirectory); if (findFile.findFile(rootDirectory, nameOfFile))
4.4.2. Attack group knowledge A biggest thing is that to provide attackers to information about system. Which means to gain information about system?
Reading this question, I experienced a high level of mathematics anxiety, I realised I could solve this question however I hesitated. I was contemplating ‘how I was going to communicate and explain my thinking?’ Initially to solve this question I utilised ‘the order of operations’, this is a knowledge I previously developed and indicates ‘multiplication and division are always completed before addition and subtraction’ in mathematics. I referred to a text book to extend my understanding, and according to Van de Walle (2010), ‘the power of two’ is an exponent which in this question is merely a shorthand interpretation for repeated multiplication of a number, times by itself.
* The user is asked to type in the name of the directory that is * to be listed. If the name entered by the user is not a directory, * a message is printed and the program ends. */ public class RecursiveDirectoryList { public static void main(String[] args) { String directoryName; // Directory name entered by the user. File directory; // File object referring to the directory.
Unit 1 I have learned about so many different technology which is I am very interest about it. I am first time user for zoom video conference which was quiet interesting but I was nervous about talking on the video. I don't look good on video. Our team was little struggle about recording it
1) The goals for energy vary in whether or not they are truly measurable. Some of them like 7.2, and 7.3 are in fact measurable. Both are searching for increases that are possible to document and record. 7.2 asks for a substantial increase in the share of renewable energy in the global energy mix. As long as the trend is increasing, target 7.2 is effectively succeeding.
Read & Execute allows the viewing and accessing of the file’s contents and you may execute the file. Modifying the folder allows the reading, writing of the files and subfolders, but you may delete the folder or files if you choose. Lastly, Full Control allows the
We can see in Fig. 1, that the embedded computing interacts with their physical environment which can early predict the health problem, secure the sensitive data and enable the uninterrupted operation. Here the paper defines [2], in Figure 1, the computing unit characterizes the quantitative property set C and it is time-varying. Similarly, the physical unit in CPS characterizes the physical property set P and it varies over time and space. For instance, in members of C it includes server utilization, the duty-cycle and control- algorithm during communication.
Create shortcut folders on Nicholas McConnell’s (NSM) Filesite/Carpe Diem
Event 1. At point A corner of 74th St and Madison Avenue a LTB Mechanical Inc. employee parks his Van and seems very happy ( my personal comments S.H.) after find parking because of busy traffic in city. The driver goes to the nearby muni meter and inserts his credit card and he presses couple of buttons but was unable to buy the time card. He goes to the opposite corner and disappears.
Each folder can have sub folders inside it. Folders can contain files. It is important to give files and folders sensible names so we know what it is about. This is very good as it enables us to keep track of all our work.