Abbey Jacobson

Math 212

Reflection 2

Reflect 4.4

⅖ths is larger than 2/7ths because when changing the fraction to a common denominator, in this case 35, we get 14/35ths and 10/35ths respectively.

4/10ths is larger than 3/8ths, I found this by finding the common denominator of 80 and changing the fractions accordingly to get 32/80 and 30/80 respectively.

When comparing 6/11 and ⅗ we find the ⅗ is larger when we find the common denominator. The common denominator is 55, we get 30/55 and 33/55 respectively, showing that ⅗ is larger than 6/11.

I multiplied ¾ by 2 to get 6/8, to make it visually easy to find the larger fraction between ¾ and ⅝. We see that ¾ is larger.

I found the common denominator of 6/5 and 8/7, changing them to 42/35 and*…show more content…*

By multiplying 4 by 2 we get 8, which makes it a common numerator with 8/15, we get 4/7 as 8/14 and can now compare it to 8/15. Since we know that 1 unit cut into 14 equal sizes pieces will produce larger pieces than 1 unit cut into 15 equal size pieces, 4/7 has to be the larger fraction.

Common Denominator

To find the common denominator of ⅘ and 9/10 we need to multiply ⅘ by 2, making it 8/10. Now that the two fractions have the same denominator we can now compare the two fractions. We can think of each fraction as 1 unit cut into ten equal size pieces. In one unit we would shade 8 of the 10 pieces to represent 8/10 and we would shade 9 out of the 10 pieces on the other unit, because we can see that the second unit has 9 out of the 10 pieces shaded we know that 9/10 is the larger fraction.

Benchmark

7/13 and 11/23 are best compared through the benchmarking strategy. We are going to use ½ as our benchmark for these two fractions. First we need to divide each of the denominators by 2 to get 6.5 and 11.5 respectively. As we can see 7 is greater than 6.5, this means that 7/13 will be to the right of ½ on a number line. 11 is less than 11.5 meaning 11/23 will be to the left of ½ on a number line. We know that the number furthest to the right on a number line is the larger number, so 7/13 is the greater

Math 212

Reflection 2

Reflect 4.4

⅖ths is larger than 2/7ths because when changing the fraction to a common denominator, in this case 35, we get 14/35ths and 10/35ths respectively.

4/10ths is larger than 3/8ths, I found this by finding the common denominator of 80 and changing the fractions accordingly to get 32/80 and 30/80 respectively.

When comparing 6/11 and ⅗ we find the ⅗ is larger when we find the common denominator. The common denominator is 55, we get 30/55 and 33/55 respectively, showing that ⅗ is larger than 6/11.

I multiplied ¾ by 2 to get 6/8, to make it visually easy to find the larger fraction between ¾ and ⅝. We see that ¾ is larger.

I found the common denominator of 6/5 and 8/7, changing them to 42/35 and

By multiplying 4 by 2 we get 8, which makes it a common numerator with 8/15, we get 4/7 as 8/14 and can now compare it to 8/15. Since we know that 1 unit cut into 14 equal sizes pieces will produce larger pieces than 1 unit cut into 15 equal size pieces, 4/7 has to be the larger fraction.

Common Denominator

To find the common denominator of ⅘ and 9/10 we need to multiply ⅘ by 2, making it 8/10. Now that the two fractions have the same denominator we can now compare the two fractions. We can think of each fraction as 1 unit cut into ten equal size pieces. In one unit we would shade 8 of the 10 pieces to represent 8/10 and we would shade 9 out of the 10 pieces on the other unit, because we can see that the second unit has 9 out of the 10 pieces shaded we know that 9/10 is the larger fraction.

Benchmark

7/13 and 11/23 are best compared through the benchmarking strategy. We are going to use ½ as our benchmark for these two fractions. First we need to divide each of the denominators by 2 to get 6.5 and 11.5 respectively. As we can see 7 is greater than 6.5, this means that 7/13 will be to the right of ½ on a number line. 11 is less than 11.5 meaning 11/23 will be to the left of ½ on a number line. We know that the number furthest to the right on a number line is the larger number, so 7/13 is the greater

Related

- Powerful Essays
## Heart Muscle Lab Report

- 1596 Words
- 7 Pages

The mean baseline cardiac output (CO) was obtained to be 4,060 ml/min. However, the CO increased with increase in the intensity of exercise with the CO for mild exercise increasing to 8,820 and that for moderate exercise increasing to 18,375. This was an increase of 117% and 353% respectively. The baseline mean arterial pressure (MAP) was 88.3 mmHg. With the introduction of mild exercise, the MAP reduced by 8.66 mmHg to 79.67 mmHg.

- 1596 Words
- 7 Pages

Powerful Essays - Good Essays
## Guinea Fowl Case Study

- 3354 Words
- 14 Pages

The PXP genotype similarly manifested a higher body weight gain from Table 1: Mean growth performance of three genotypes of guinea fowl Weeks Parameter Genotypes SEM P × P B × B B×P Wk2 Body weight (g) 100.79 97.62 99.91 2.40 Body weight gain (g/bird) 75.96 71.92 73.22 2.35 2-weekly feed intake (g/bird) 203.17 203.17 203.17

- 3354 Words
- 14 Pages

Good Essays - Powerful Essays
## Maths In Rugby Research Paper

- 2977 Words
- 12 Pages

In order to find the position that provides the maximum angle, a series of expanding circles with AB as a chord can be drawn. All the inscribed angles in each of the circles are equal (inscribed angles on the same chord law) and these sets of equal angles decrease with an increase in size of the circle (exterior angle theorem for a triangle). For example, angle AFB = angle ACB and angle ADB>AGB. Consequently, the optimal position would be found where the conversion line forms a tangent with one of the circles as it provides the largest angle along the conversion line (line TF) than any other point.

- 2977 Words
- 12 Pages

Powerful Essays - Powerful Essays
## Bess Bug Lab Report

- 1131 Words
- 5 Pages

The bessbug was able to carry 6 weights which has the mass of 18.85 grams, while ten times the mass of a bessbug is 17.6 grams. The maximum amount of weights the bessbug was able to pull was 10 weights which is equal to 31.46 grams. The data shows the strength of the bessbug and how much the bessbug is able to carry in all. The data occurred because the capacity of the bessbug allows the bessbug to carry 10 weights. The data supports the hypothesis because the bessbug was able to lift ten times the weight of the bessbug which is 17.6 grams, and much more because the total amount the bessbug was able to pull was 31.46 grams.

- 1131 Words
- 5 Pages

Powerful Essays - Good Essays
## Psychoanalytic Theory Of 16PF

- 1348 Words
- 6 Pages

For the 16PF primary scales, test–retest reliabilities average 0.80 over a two-week interval (ranging from 0.69 to 0.87), and 0.70 over a two-month interval (ranging from 0.56 to 0.79). The five global scales of the 16PF Questionnaire show even higher test–retest reliabilities (they have more items); they average 0.87 for a two week interval (ranging from 0.84 to 0.91), and 0.78 for a two-month interval (ranging from 0.70 to 0.82). One important source of validity for the 16PF Questionnaire has been factor-analytic studies of the structure of the primary and global traits across diverse samples of people. These studies have used exploratory and confirmatory factor analysis to confirm the number, identity, and independence of the primary factors; and to confirm the number, identity, and primary factor make-up of the global factors. There are numerous applications for 16PF and it is useful in the following settings: • Career Choices • Counselling and correctional

- 1348 Words
- 6 Pages

Good Essays - Good Essays
## Essay On Turkey Microbes

- 839 Words
- 4 Pages

This table presents the information in colony factoring units per gram, or CFU/G. To obtain this number, a series of calculations were conducted. Beginning with the total number of colonies in each dilution, this number was divided by 0.1. Then the number found from the division explained previously was then multiplied by 10 to the power of n, where n was the number in the dilution set. For example: dilution 4 would solved using the answer to the division problem and multiplying by 10 to the 4th power.

- 839 Words
- 4 Pages

Good Essays - Good Essays
## Monascus Purpureus Case Study

- 1723 Words
- 7 Pages

9. Juzlova et al (1996) described that amino acid addition in growth medium of Monascus lead to increase red pigment production than other pigment. Metal ions additions showed a great effect on Monascus both growth and red pigment production (Fig. 10). Weinberg (1989) stated that trace metals have stimulatory effects on secondary metabolism. Metal ions, Fe2+, Zn2+ and Mg2+ showed strong effect on both growth and pigments production of Monascus sp.

- 1723 Words
- 7 Pages

Good Essays - Good Essays
David Ricardo’s work “On The Principles of Political Economy and Taxation” written in 1817 is the example of classical writings about economics. The point Ricardo makes in Chapter 7 “On Foreign Trade” is generally that trade is beneficial and a basis for trade is comparative advantage (1817). The essay states that comparative advantage can be a reason for international trade; however there are still problems with its implication in practice. To prove that this paper will first explain Ricardo’s comparative advantage theory. Second, it will provide an example of Kazakhstan and Russia for more explanation.

- 879 Words
- 4 Pages

Good Essays - Good Essays
## The Chi-Square Test

- 882 Words
- 4 Pages

For that reason, degree of freedom is equal to 2. For data with one category: Degree of freedom = number of observations -1 For data with more than one category represented in a table: Degrees of freedom =

- 882 Words
- 4 Pages

Good Essays - Good Essays
## Omar Khayyam: A Brief Biography

- 848 Words
- 4 Pages

Based on making 8 of every 33 years leap years, it was more accurate than the present Gregorian calendar, and it was adopted in 1075 by Malik-Shāh. Khayyam found that 1,029,983 days made 2,820 years. This gives a tropical year length of 365.2422 days to seven significant figures. Although it has become fashionable to quote more decimal places than this, Khayyam’s input of 1,029,983 days contains seven significant figures, so it is unreasonable to quote more than this number of significant figures in the calculated year length. Today we know that the length of a tropical year actually changes by as much as 30 minutes from year to year.

- 848 Words
- 4 Pages

Good Essays - Powerful Essays
## Apportionment: Thomas Jefferson And Alexander Hamilton

- 1070 Words
- 5 Pages

The standard quota will now become two. The next highest decimal remainder is 13.904 for Apus. The standard quota will now become 14. The third highest decimal remainder is

- 1070 Words
- 5 Pages

Powerful Essays - Good Essays
## Acct 556 Week 3 Individual Assignment

- 1158 Words
- 5 Pages

The most appropriate high tech SGD hardware for my client would be the Accent 1000. The reason why is because of the amount of the symbols located on the page of the screen. Since there is 84 symbols located on the first page, Cruz would not have to navigate as much though many different pages to find the words that he needs to express himself The weight of the device is 3.6 pounds with 13 to 15 hours of battery life. The weight and the battery coincide with one another. The device weighs 3.6 pounds which means the battery is included and this can affect the weight.

- 1158 Words
- 5 Pages

Good Essays - Satisfactory Essays
## Sandwich Blitz Unit 6 Lab Report

- 301 Words
- 2 Pages

Calculation: Initial Mass(g)－Final Mass (g)=Change in Mass (g) Trial 1 74.5-62.0=12.5(g) Trial 2 272.7－271.5=1.2（g） Percent Error: 272.7-271.5 x 100 272.7 ＝0.440% Percent Change: 74.5-62.0 x 100 74.5 (Trial 1) =16.778% 272.7-271.5 x 100 272.7 (Trial 2) ＝0.440%

- 301 Words
- 2 Pages

Satisfactory Essays - Good Essays
## Slope Measurement Lab Report

- 538 Words
- 3 Pages

In our group our data was pretty good we had two mess ups on scale 2 (.06kg, 1N) and (.14kg, 2N). These points were a lot bigger then the points with scale 1 and scale 3, and when I made the graph those two points were farther away and more of set of the line of best fit. Also on scale 2 and 1 I had the same weight for 2 different masses I had 2N for both .14kg and .16kg this also happened on scale 1 and 3 on trail 6 and 5 on scale 1 I had (.14kg, 1.8N) and on scale 3 I had (.16kg, 1.8N). I think these mistakes happened because I read the scale wrong.

- 538 Words
- 3 Pages

Good Essays - Good Essays
## Case Study: A Letter To The Rocky Mountains

- 762 Words
- 4 Pages

One final topic of this letter to you is the Port City. Now we were going to buy it anyways for 10 million dollars which really isn 't that much less than the price now for the entire Louisiana Territory which costs 15 million. This city makes trading a lot easier than what it is now it makes us open, gives us a place to dock the foreign traders and their goods, let alone our goods and our traders. Jefferson was also planning to expand the land around it as well so we can gain more land than just the 524.8 million acres for just the mere 15 million dollars in which you were just going to spend 10 million of it on this city which is still included in this deal it didn 't change what was in it already it just

- 762 Words
- 4 Pages

Good Essays