In this lab, the oxidation of a secondary alcohol was performed and analyzed. An environmentally friendly reagent, sodium hypochlorite, was used to oxidize the alcohol, and an IR spectrum was obtained in order to identify the starting compound and final product. The starting compound could have been one of four alcohols, cyclopentanol, cyclohexanol, 3-heptanol, or 2-heptanol. Since these were the only four initial compounds, the ketone obtained at the end of the experiment could only be one of four products, cyclopentanone, cyclohexanone, 3-heptanone, or 2-heptanone. In order to retrieve one of these ketones, first 1.75g of unknown D was obtained.
Like how the temperature affected how long it took for the tablet to react to the water, if there is only one drop water used to dissolve the whole tablet, the time it takes for the whole tablet to react to the water and start to dissolve will be
In this lab there were five different stations. For the first station we had to determine an unknown mass and the percent difference. To find the unknown mass we set up the equation Fleft*dleft = Fright*dright. We then substituted in the values (26.05 N * 41cm = 34cm * x N) and solved for Fright to get (320.5g). To determine the percent difference we used the formula Abs[((Value 1 - Value 2) / average of 1 & 2) * 100], substituted the values (Abs[((320.5 - 315.8) /
5. 150 ml of the solution in beaker A was added to the separating funnel with 10ml of chloroform. The funnel was gently shaken and vented to release the pressure. This was done five times. 6.
Thus, a higher percent yield was calculated for acetaminophen. Although, a second filtration was performed; however, a very low concentration of acetaminophen was recovered as a result of human errors, and the transfer of solution/solid contributed to product loss. However, the mass use to calculate percent yield was the first mass recorded because it may be more consistent than the mass measured after the second filtration. However, for further experiments, the percent yield must be calculated with the corresponding mass of product (actual yield) even though there is loss of product, the actual yield is the final concentration of the recovered product in the experiment. Thus, the results may be more conclusive if the actual percent yield was used.
The mass we measured after the whole process came up, was 121.80g. The chemical reaction happened between the water and the tablet conserves the mass of the water. As a whole point, we claimed that there was a chemical reaction between the water and the tablet that produced carbon dioxide and the mass remained as same as before and after the
Introduction: In this assignment, I will be doing two experimentations on examining the impact of temperature on the Alka-Seltzer’s response time. The first experimentation that I will be doing involves some water that is room temperature. The second experimentation that I will be doing involves some water that is very hot. If I want to be able to figure out the impact of the temperature on water, I will have to document the time it will take for the Alka-Seltzer to go into solution.
To do this we created proportions. We calculated that we need to put .25 mL of salt in 50 mL of water to create .5% salinity, 1.5 mL of salt in 50 mL of water to create 3% salinity, and 2.5 mL of salt
Next, about 10 mL of both solutions, Red 40 and Blue 1, were added to a small beaker. The concentration of the stock solution were recorded, 52.1 ppm for Red 40 and 16.6 ppm for Blue 1. Then, using the volumetric pipette, 5 mL of each solution was transferred into a 10 mL volumetric flask, labelled either R1 or B1. Deionized water was added into the flask using a pipette until the solution level reached a line which indicated 10 mL. A cap for the flask was inserted and the flask was invented a few times to completely mix the solution. Then, the volumetric pipette was rinsed with fresh deionized water and
The mass of an 11 dram vial was taken before and after it was filled with 15 mL of distilled water, resulting in a mass of 29.9667 grams without the distilled water and 44.7771 grams with the distilled water. The looped wire was inserted into the 11 dram vial, to be used for stirring. The 11 dram vial was then submerged into the ice bath, and the Vernier temperature probe was immersed into the 11 dram vial. Once the temperature of the distilled water reached 10°C, the temperature was recorded every 10 seconds. After the data was collected, the 11 dram vial was brought back to room temperature.
Introduction The goal of the experiment is to examine how the rate of reaction between Hydrochloric acid and Sodium thiosulphate is affected by altering the concentrations. The concentration of Sodium thiosulfate will be altered by adding deionised water and decreasing the amount of Sodium thiosulphate. Once the Sodium thiosulphate has been tested several times. The effect of concentration on the rate of reaction can be examined in this experiment.
IV. Data and observations Mass of beaker (g) 174.01 Mass of beaker + NaOH pellets (g) 174.54 Mass of NaOH pellets 0.53 TRIAL 1 TRIAL 2 Mass of potassium acid phtalate (KHP) (g) 0.15 0.15 final buret reading (ml) 30.75
In this experiment, the amount of water lost in the 0.99 gram sample of hydrated salt was 0.35 grams, meaning that 35.4% of the salt’s mass was water. The unknown salt’s percent water is closest to that of Copper (II) Sulfate Pentahydrate, or CuSO4 ⋅ 5H2O. The percent error from the accepted percent water in CuSO4 ⋅ 5H2O is 1.67%, since the calculated value came out to be 0.6 less than the accepted value of 36.0%.This lab may have had some issues or sources of error, including the possibility of insufficient heating, meaning that some water may not have evaporated, that the scale was uncalibrated, or that the evaporating dish was still hot while being measured. This would have resulted in convection currents pushing up on the plate and making it seem lighter by lifting it up
The mixture was then distilled. When the temperature was reached to about 59℃, half vial of distillate (1V) and 1 mL of the liquid residue (1L) were collected. For 61.0℃, the distillation was then continued. Samples (2V, 2L) were taken at about 61.0℃.
There are multiple points both at 43°C and at 72°C which indicates that liquid was collected at these temperatures. Based on this information, it would appear that two different liquids were present in solution and that one liquid has a boiling point of approximately 43°C and that the other has a boiling point of approximately 72°C. The literature value boiling point for DCM in is reported to be about 40°C and it is about 80°C for cyclohexane. Based on the graph, DCM was collected from 4 ml to 22 ml, thus 18 ml of DCM was collected.