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Explain How The Surface Area Of The Solute Affect The Rate Of Dissolution

699 Words3 Pages

The guiding question, why do the surface area of the solute, the temperature of the solvent mixed affect the rate of dissolution. To answer this question we used three hypotheses to test; if you increase the surface area than the rate of dissolution increases, If you increase the temperature of solvent then the rate of diffusion increases, If you increase the amount of agitation then the rate of dissolution. We predicted that changing the stress, surface area, temperature, and stirring in a controlled experiment it would forward the rate of dissolution. Based on the background on making lemonade, when sugar is added to water and stirred the sugar (solute) dissolves quickly, when sugar (solute) is fine, the temperature is raised, and agitation is increased the solution dissolves at an increased rate. …show more content…

In hypothesis one we added surface area (stress) to the solute. In this experiment we used 1 gram sample of medium crystals and 1 gram sample of fine crystals. We put the 2 samples into separate beakers and added 40 mL of water to each beaker at the same time. During observations, both fine and medium crystals sank to the bottom of the water. The finer crystals had small bubbles rising to the surface of the liquid and the water (solvent) dissolved more fine crystals (solute) than medium crystals in 10 minutes. In our results we found that the solute with less surface area dissolves into a solvent faster than a solute with more surface area. We can now confirm that the stress of surface area on a solute affects the rate of dissolution, the more surface area of a solute the rate of dissolution increases. This is proven through the results of our first hypothesis

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