A simple dilution is the combination of a liquid material of interest with a solvent liquid to achieve the desired concentration. The dilution factor refers to the ratio of the volume of the initial concentrated solution to the volume of the final dilute solution. The diluted material must be thoroughly mixes well to achieve the true dilution. The formula, C1V1 = C2V2 is widely used in dilution to calculate the concentration or volume of the solution either is on before or after the dilution. V1 = Volume of stock solution needed to make the new solution C1 = Concentration of stock solution V2 = Final volume of new solution C2 = Final concentration of new solution The dilution factor can be used alone or as the denominator of the fraction. …show more content…
The different level of blue colour of the solutions after adding the iodine solution show the different concentration of starch concentration in it. The change in colour is due to the formation of polyiodide chains from the reaction of starch and iodine. The amylose in starch forms helices where iodine molecules assemble, forming a dark blue or black color. 1ml of starch solution with concentration 5000 are added to test tube A. 1 unit volume of the starch solution to be diluted plus 9 unit volumes of the solvent medium. Hence, 1+ 9=10. 1 : 10 is the dilution factor. The test tube is shaked will before 1 ml solution is transferred to test tube B. The concentration of starch of the 1ml solution from test tube A is 500 after dilute with 9ml distilled water in test tube A. The 500 of starch solution become more dilute after added into 9ml test tube B, which become 50 . The concentration of solution in the few next test tube decreases in such way. The dilution factor, 5000 ratio to 50 is 1 : 100 in test tube B while the dilution factor in test tube C, 5000 ratio to 5 is 1 : 1000 and so …show more content…
The colour showed in test tube A is dark blue but the rest are all nearly yellow. This mean there must be an error when the experiment is carried out during the dilution and transfer of solution from one test tube to another. With each sequential serial dilution step, transfer inaccuracies can lead to less accurate and less precise dispensing. To relieve this error possibility, longer mixing times are required, which increases the time required to perform the serial dilution to allow the solution to be thoroughly mixed well. Theoretically, longer mixing times are required for more dilute samples,. However, this is usually not compensated for and unequal concentrations which are usually used to innoculate the next
Prelab week 1 Calculations Preparation of 1.5μmol/L mixed low-level standard dilution 150μmol/L × V1=1.5μmol/L × 10ml V1=(1.5μmol/L×10ml)/(150μmol/L)=0.1ml Conversion of milliliters to microliters (0.1ml×1000)μL= 100μL Preparation of 3μmol/L mixed low-level standard dilution 150μmol/L × V1=3μmol/L × 10ml V1=(3μmol/L×10ml)/(150μmol/L)=0.2ml Conversion of milliliters to microliters (0.2ml×1000)μL= 200μL Preparation of 3μmol/L mixed low-level standard dilution 150μmol/L × V1=7.5μmol/L × 10ml V1=(7.5μmol/L×10ml)/(150μmol/L)=0.5ml Conversion of milliliters to microliters (0.5ml×1000)μL= 500μL Preparation of the blank samples The volumetric flask will be filled to the mark with 150μmole/L of stock solution to act as blank (reference). Additional two blanks will
Marwah Alabbad Post lab 10/21/15 Question 1: 1. Experiment 1: Number of trails NaOH concentration (M) Volume of HCl solution (mL) Initial volume of NaOH(mL) final volume of NaOH(mL) The volume of NaOH to titrate HCl (mL) Concentration of HCl (M) 1st 0.1023 25.0 10.05 36.12 26.07 0.085 2nd 0.1023 25.0 5.74 31.40 25.66 0.105 3rd 0.1023 25.0 9.84 35.52 25.68 0.105 First trail calculation: 0.02607L× (0.1023mole NaOH/1L)×(1 mol of HCL/1 mol of NaOH)×(1/0.025)= 0.085M of HCl
The serial 2-fold dilution were done with a volumetric pipette, its pump, and 10 mL volumetric flasks. Eight different solutions were produced, half of which came from Red 40 and the other half, from Blue 1. These different concentrated solutions were placed in a 10 mL volumetric flask, each labelled with either R for Red 40
This was done to get more accurate results. The first time the experiment was conducted it was tested at three different time points, at zero minutes, fifteen minutes and
Starch solution is then placed into the test tube at a quantity of 5 mL. 5 drops of Lugol’s Iodine solution is added to the test tube. If the color changes, then it is known that starches are present in the solution. Proteins are next tested. In order to do this, 5 mL of gelatin solution is added to the test tube. 10 drops of Biuret’s reagent are added to test for protein.
5 litres of 1x10^-2 Dodecylamin has been diluted to 1x10^-5M by adding accurate amount of water from the tap. To calculate required water amount mathematical equations given below : C1V1=C2V2 10^-2M x V1 =10^-5M x 1,000 mL V1 = 10^-5/10^ -2
The investigation was carried out to identify the presence or absence of biological molecules in serum 2216. If the concentration in each test tube of the dilutions carried out will be more concentrated then the concentration of the test tube before it, then the color will be at an equal concentration with the other dilutions performed. The hypothesis was wrong because of the difference in concentrations due to the different measurements within the dilutions done. The test for starch was to add a drop of iodine solution to the pipette in the spotting tile. A reducing sugar solutions is add inside a test tube with 3 drops to then add 3 drops of benedicts and plane in a water bath.
Introduction The purpose of this lab is to use control variables to help identify different macromolecules. Biological systems are made up of these four major macromolecules: carbohydrates, lipids, proteins and nucleic acids. Carbohydrates are sugar molecules (monosaccharides, disaccharides, and polysaccharides) which make them the most abundant macromolecule on the earth. Lipids (oils and fats, phospholipids and steroids) are insoluble in water and perform many functions such as energy source, essential nutrients, hormones and insulators (Lehman, 1955).
In this lab we used two processes called Diffusion and Osmosis. Diffusion is the movement of molecules from areas of high concentration to areas of low concentration. Diffusion is a process that requires no energy and involves smaller non-polar molecules. In Figure 1 you can see the molecules spreading throughout the glass from the area of high concentration, so that the areas with low concentration are filled evenly as well. The other process was osmosis.
Lab Report Experiment 6 Rates of Chemical Reactions By Nikhola Mirashirova Lab Partner: Dina Abetova Section 3, Saturday October 31, 2015 Introduction Rate reaction is the measure of the change in concentration of the reactants or the change in concentration of the products per unit time.1,2 Rate law for this experiment: Rate = k(I-)m(BrO3-)n(H+)p There are several factors which affect the rate of reaction: catalyst, reactant concentration, and temperature.1,2 A catalyst is a substance that changes, increases or decreases, the rate of a chemical reaction but is not being used up during the reaction.3 It provides an alternative way, so that the rate of reaction changes.4 Catalyst, which is used in this experiment, is (NH4)2MoO (0.5 M).
7) Test tube four contains 7 mL of distilled water and 3 mL of CoCl2. The fifth had 7 mL of distilled water and 3 mL of CoCl2. 8) Test tube five contains 6 mL of distilled water and 4 mL of CoCl2. 9) Test tube six contains 5 mL of distilled water and 5 mL of CoCl2. 10) After all of the test tubes are prepared, they will be put into cuvettes.
Controlled Concentration of amylase Amount of amylase/starch Ph of the amylase/starch The concentration of the Amylase was kept at 1% at at times throughout the experiment. 5cm3 of both will be used in each reaction. pH of the Amylase/starch will be kept the same.
Use these results to determine the product concentration, using Beer-Lambert’s Law: A= ɛCl (where A is the absorbance, ɛ is the molar absorptivity, C is the product concentration and l is the length of solution that the light passes through). Calculate the product concentrations at every minute for 10 minutes for all 7 of the test tubes using Beer-Lambert’s Law. Plot a graph of product concentration vs. time and then use the gradients of the 7 test tubes to determine the velocities of the reaction. After calculating the velocities, plot a Michaelis-Menten graph of velocity vs. substrate concentration.
The solution with the pigments was spotted 15 times on both region A and region B and then allowed to dry. When the plate was dry it was placed into the tank for at least 20
Introduction Buffer is a solution that resists a change in pH when bases or acid are added. Solutions that are acidic contain high concentrations of hydrogen ions (H+) and have pH values less than seven. Buffer usually consist of a weak acid, and its conjugate base or a weak base and its conjugate acid. The function of buffer is to resist the changes in hydrogen ion concentration as a result of internal and environmental factor. This buffer experiment is important so that we relies the important of buffer in our life.